該源碼為C8051F120混合片上數據采集系統中實現4~32768點數據的FFT運算功能。所占的代碼空間小，運行快。
上傳時間： 2013-12-18
上傳用戶：zhouli
可實現簡單的加法運算功能 范圍-32768~~~32767
上傳時間： 2017-01-18
上傳用戶：13160677563
基于AT89S52單片機的nRF2401無線模塊開發板 資料齊全
上傳時間： 2014-06-14
上傳用戶：nshark
多數程序設計語言處理整數的能力時有限的，如C語言中，int類型數據范圍是-32768－32767。實際問題的處理過程中往往涉及大整數的運算，如RSA加密算法要求至少64bit的整數，設計算法實現大整數的加減運算。
上傳時間： 2014-07-08
上傳用戶：偷心的海盜
IO 驅動 LCD , *** *** *** *** *** *** *** *** FILE NAME: IO_LCD MCU: HT46R22 MASK OPTION: WAKE-UP: PA6,PA7 PULL-HIGH: PA,PB,PC IIC: DISABLE PFD: DISABLE PWM: DISABLE WDT: ENABLE CLRWDT: ONE WDT CLOCK SOURCE: T1 WDT TIME OUT SELECT: WDT CLOCK SOURCE/32768 LVR: DISABLE OSC: CRYSTAL SYSVOLT: 3.0V SYSFRAG: 4000KHZ AUTHOR: RADOME HISTORY: 2005.08.
上傳時間： 2014-12-21
上傳用戶：watch100
計算xk+1除CRC-CCITT后的余式，k從1到32768
上傳時間： 2014-01-19
上傳用戶：ruixue198909
計算xk+1除CRC-CCITT后的余式，k從1到32768
上傳時間： 2016-06-18
上傳用戶：ynsnjs
計算xk+1除CRC-32后的余式，k從1到32768
上傳時間： 2013-11-25
上傳用戶：wangchong
atmega8控制的4位時鐘，32768時鐘源
上傳時間： 2013-12-17
上傳用戶：exxxds
For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
標簽： Limit following solving problem
上傳時間： 2014-01-12
上傳用戶：362279997
