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溫度華氏轉變攝氏
#include <stdio.h>
#include <stdlib.h>
enum x {A,B,C,D,E}
int main(void)
{
int a=73,b=85,c=66
{
if (a>=90)
printf("a=A等級!!\n")
else if (a>=80)
printf("73分=B等級!!\n")
else if (a>=70)
printf("73分=C等級!!\n")
else if (a>=60)
printf("73分=D等級!!\n")
else if (a<60)
printf("73分=E等級!!\n")
}
{
if (b>=90)
printf("b=A等級!!\n")
else if (b>=80)
printf("85分=B等級!!\n")
else if (b>=70)
printf("85分=C等級!!\n")
else if (b>=60)
printf("85分=D等級!!\n")
else if (b<60)
printf("85分=E等級!!\n")
}
{
if (c>=90)
printf("c=A等級!!\n")
else if (c>=80)
printf("66分=B等級!!\n")
else if (c>=70)
printf("66分=C等級!!\n")
else if (c>=60)
printf("66分=D等級!!\n")
else if (c<60)
printf("66分=E等級!!\n")
}
system("pause")
return 0
}
標簽：
include
stdlib
stdio
gt
上傳時間：
2014-11-10
上傳用戶：wpwpwlxwlx
-
溫度華氏轉變攝氏
#include <stdio.h>
#include <stdlib.h>
enum x {A,B,C,D,E}
int main(void)
{
int a=73,b=85,c=66
{
if (a>=90)
printf("a=A等級!!\n")
else if (a>=80)
printf("73分=B等級!!\n")
else if (a>=70)
printf("73分=C等級!!\n")
else if (a>=60)
printf("73分=D等級!!\n")
else if (a<60)
printf("73分=E等級!!\n")
}
{
if (b>=90)
printf("b=A等級!!\n")
else if (b>=80)
printf("85分=B等級!!\n")
else if (b>=70)
printf("85分=C等級!!\n")
else if (b>=60)
printf("85分=D等級!!\n")
else if (b<60)
printf("85分=E等級!!\n")
}
{
if (c>=90)
printf("c=A等級!!\n")
else if (c>=80)
printf("66分=B等級!!\n")
else if (c>=70)
printf("66分=C等級!!\n")
else if (c>=60)
printf("66分=D等級!!\n")
else if (c<60)
printf("66分=E等級!!\n")
}
system("pause")
return 0
}
標簽：
include
stdlib
stdio
gt
上傳時間：
2013-12-12
上傳用戶：亞亞娟娟123
-
Geoprocessor Programming Model
Use CreateObject to create a Spatial
Reference, a Value Table, or a
FieldInfo Object
標簽：
Geoprocessor
CreateObject
Programming
Reference
上傳時間：
2013-12-23
上傳用戶：天涯
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源代碼\用動態規劃算法計算序列關系個數
用關系"<"和"="將3個數a，b，c依次序排列時，有13種不同的序列關系：
a=b=c,a=b<c,a<b=v,a<b<c,a<c<b
a=c<b,b<a=c,b<a<c,b<c<a,b=c<a
c<a=b,c<a<b,c<b<a
若要將n個數依序列，設計一個動態規劃算法，計算出有多少種不同的序列關系，
要求算法只占用O(n),只耗時O(n*n).
標簽：
lt
源代碼
動態規劃
序列
上傳時間：
2013-12-26
上傳用戶：siguazgb
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The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d .
Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet.
Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1.
Definition
標簽：
government
streamline
important
alphabet
上傳時間：
2015-06-09
上傳用戶：weixiao99
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代入法的啟發示搜索
我的代碼實現是：按照自然語言各字母出現頻率的大小從高到低（已經有人作國統計分析了）先生成一張字母出現頻率統計表（A）--------(e),(t,a,o,i,n,s,h,r),(d,l),(c,u,m,w,f,g,y,p,b),(v,k,j,x,q,z)
，再對密文字母計算頻率，并按頻率從高到低生成一張輸入密文字母的統計表（B），通過兩張表的對應關系，不斷用A中的字母去替換B中的字母，搜索不成功時就回退，在這里回朔是一個關鍵。
標簽：
字母
頻率
搜索
代碼
上傳時間：
2015-10-24
上傳用戶：wanqunsheng
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A one-dimensional calibration object consists of three or more collinear points with known relative positions.
It is generally believed that a camera can be calibrated only when a 1D calibration object is in planar motion or rotates
around a ¯ xed point. In this paper, it is proved that when a multi-camera is observing a 1D object undergoing general
rigid motions synchronously, the camera set can be linearly calibrated. A linear algorithm for the camera set calibration
is proposed，and then the linear estimation is further re¯ ned using the maximum likelihood criteria. The simulated and
real image experiments show that the proposed algorithm is valid and robust.
標簽：
one-dimensional
calibration
collinear
consists
上傳時間：
2014-01-12
上傳用戶：璇珠官人
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1、典型連續時間信號波形繪制
1）單邊指數信號
要求：
(1) 畫出t=0,1,2,…,500共501點
(2)在一個坐標系中用三種不同顏色分別繪制如下三種情況下的波形
(a) E=200,X=62.5
(b) E=200,X=125.0
(c) E=200,X=250.0
(3)標出特殊點的坐標，如t=0和 的坐標
代碼為此題目的解
標簽：
500
200
501
信號
上傳時間：
2014-11-30
上傳用戶：小草123
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We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽：
represented
integers
group
items
上傳時間：
2016-01-17
上傳用戶：jeffery
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Generate 100 samples of a zero-mean white noise sequence with variance , by using a uniform random number generator.
a Compute the autocorrelation of for .
b Compute the periodogram estimate and plot it.
c Generate 10 different realizations of , and compute the corresponding sample autocorrelation sequences , and . Compute the average autocorrelation sequence as and the corresponding periodogram for .
d Compute and plot the average periodogram using the Bartlett method.
e Comment on the results in parts (a) through (d).
標簽：
zero-mean
Generate
sequence
variance
上傳時間：
2016-03-04
上傳用戶：朗朗乾坤
