樣板 B 樹 ( B - tree ) 規(guī)則 : (1) 每個節(jié)點內(nèi)元素個數(shù)在 [MIN,2*MIN] 之間, 但根節(jié)點元素個數(shù)為 [1,2*MIN] (2) 節(jié)點內(nèi)元素由小排到大, 元素不重複 (3) 每個節(jié)點內(nèi)的指標個數(shù)為元素個數(shù)加一 (4) 第 i 個指標所指向的子節(jié)點內(nèi)的所有元素值皆小於父節(jié)點的第 i 個元素 (5) B 樹內(nèi)的所有末端節(jié)點深度一樣
上傳時間： 2017-05-14
上傳用戶：日光微瀾
歐幾里德算法：輾轉(zhuǎn)求余 原理: gcd(a,b)=gcd(b,a mod b) 當b為0時,兩數(shù)的最大公約數(shù)即為a getchar()會接受前一個scanf的回車符
上傳時間： 2014-01-10
上傳用戶：2467478207
Consider a BPSK and a QPSK system for the following two cases: 1) The probability that the symbol 1 is sent and the probability that the symbol 0 is sent are all the same. 2) The probability that the symbol 1 is sent is two times than the probability that the symbol 0 is sent. Assume that the noise is Gaussian distributed with mean=0 and 2 = 1.
標簽： probability following the Consider
上傳時間： 2017-08-15
上傳用戶：凌云御清風
數(shù)據(jù)結(jié)構(gòu)課程設計 數(shù)據(jù)結(jié)構(gòu)B+樹 B+ tree Library
標簽： Library tree 數(shù)據(jù)結(jié)構(gòu) 樹
上傳時間： 2013-12-31
上傳用戶：semi1981
All inputs of the C16x family have Schmitt-Trigger input characteristics. These Schmitt-Triggers are intended to always provide proper internal low and high levels, even if anundefined voltage level (between TTL-VIL and TTL-VIH) is externally applied to the pin.The hysteresis of these inputs, however, is very small, and can not be properly used in anapplication to suppress signal noise, and to shape slow rising/falling input transitions.Thus, it must be taken care that rising/falling input signals pass the undefined area of theTTL-specification between VIL and VIH with a sufficient rise/fall time, as generally usualand specified for TTL components (e.g. 74LS series: gates 1V/us, clock inputs 20V/us).The effect of the implemented Schmitt-Trigger is that even if the input signal remains inthe undefined area, well defined low/high levels are generated internally. Note that allinput signals are evaluated at specific sample points (depending on the input and theperipheral function connected to it), at that signal transitions are detected if twoconsecutive samples show different levels. Thus, only the current level of an input signalat these sample points is relevant, that means, the necessary rise/fall times of the inputsignal is only dependant on the sample rate, that is the distance in time between twoconsecutive evaluation time points. If an input signal, for instance, is sampled throughsoftware every 10us, it is irrelevant, which input level would be seen between thesamples. Thus, it would be allowable for the signal to take 10us to pass through theundefined area. Due to the sample rate of 10us, it is assured that only one sample canoccur while the signal is within the undefined area, and no incorrect transition will bedetected. For inputs which are connected to a peripheral function, e.g. capture inputs, thesample rate is determined by the clock cycle of the peripheral unit. In the case of theCAPCOM unit this means a sample rate of 400ns @ 20MHz CPU clock. This requiresinput signals to pass through the undefined area within these 400ns in order to avoidmultiple capture events.For input signals, which do not provide the required rise/fall times, external circuitry mustbe used to shape the signal transitions.In the attached diagram, the effect of the sample rate is shown. The numbers 1 to 5 in thediagram represent possible sample points. Waveform a) shows the result if the inputsignal transition time through the undefined TTL-level area is less than the time distancebetween the sample points (sampling at 1, 2, 3, and 4). Waveform b) can be the result ifthe sampling is performed more than once within the undefined area (sampling at 1, 2, 5,3, and 4).Sample points:1. Evaluation of the signal clearly results in a low level2. Either a low or a high level can be sampled here. If low is sampled, no transition willbe detected. If the sample results in a high level, a transition is detected, and anappropriate action (e.g. capture) might take place.3. Evaluation here clearly results in a high level. If the previous sample 2) had alreadydetected a high, there is no change. If the previous sample 2) showed a low, atransition from low to high is detected now.
上傳時間： 2013-10-23
上傳用戶：copu
* 高斯列主元素消去法求解矩陣方程AX=B,其中A是N*N的矩陣,B是N*M矩陣 * 輸入: n----方陣A的行數(shù) * a----矩陣A * m----矩陣B的列數(shù) * b----矩陣B * 輸出: det----矩陣A的行列式值 * a----A消元后的上三角矩陣 * b----矩陣方程的解X
上傳時間： 2015-07-26
上傳用戶：xauthu
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
(1) 、用下述兩條具體規(guī)則和規(guī)則形式實現(xiàn).設大寫字母表示魔王語言的詞匯 小寫字母表示人的語言詞匯 希臘字母表示可以用大寫字母或小寫字母代換的變量.魔王語言可含人的詞匯. (2) 、B→tAdA A→sae (3) 、將魔王語言B(ehnxgz)B解釋成人的語言.每個字母對應下列的語言.
上傳時間： 2013-12-30
上傳用戶：ayfeixiao
1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經(jīng)過研究發(fā)現(xiàn)，漢諾塔的破解很簡單，就是按照移動規(guī)則向一個方向移動金片： 如3階漢諾塔的移動：A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外，漢諾塔問題也是程序設計中的經(jīng)典遞歸問題
標簽： 移動 發(fā)現(xiàn)
上傳時間： 2016-07-25
上傳用戶：gxrui1991
1. 下列說法正確的是 （ ） A. Java語言不區(qū)分大小寫 B. Java程序以類為基本單位 C. JVM為Java虛擬機JVM的英文縮寫 D. 運行Java程序需要先安裝JDK 2. 下列說法中錯誤的是 ( ) A. Java語言是編譯執(zhí)行的 B. Java中使用了多進程技術(shù) C. Java的單行注視以//開頭 D. Java語言具有很高的安全性 3. 下面不屬于Java語言特點的一項是( ) A. 安全性 B. 分布式 C. 移植性 D. 編譯執(zhí)行 4. 下列語句中，正確的項是 ( ) A . int $e,a,b=10 B. char c,d=’a’ C. float e=0.0d D. double c=0.0f
上傳時間： 2017-01-04
上傳用戶：netwolf
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