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Blitz-<b>Ball</b>-The

  • 1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動(dòng)一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經(jīng)過(guò)研究發(fā)現(xiàn)

    1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動(dòng)一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經(jīng)過(guò)研究發(fā)現(xiàn),漢諾塔的破解很簡(jiǎn)單,就是按照移動(dòng)規(guī)則向一個(gè)方向移動(dòng)金片: 如3階漢諾塔的移動(dòng):A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外,漢諾塔問(wèn)題也是程序設(shè)計(jì)中的經(jīng)典遞歸問(wèn)題

    標(biāo)簽: 移動(dòng) 發(fā)現(xiàn)

    上傳時(shí)間: 2016-07-25

    上傳用戶:gxrui1991

  • 1. 下列說(shuō)法正確的是 ( ) A. Java語(yǔ)言不區(qū)分大小寫 B. Java程序以類為基本單位 C. JVM為Java虛擬機(jī)JVM的英文縮寫 D. 運(yùn)行Java程序需要先安裝JDK

    1. 下列說(shuō)法正確的是 ( ) A. Java語(yǔ)言不區(qū)分大小寫 B. Java程序以類為基本單位 C. JVM為Java虛擬機(jī)JVM的英文縮寫 D. 運(yùn)行Java程序需要先安裝JDK 2. 下列說(shuō)法中錯(cuò)誤的是 ( ) A. Java語(yǔ)言是編譯執(zhí)行的 B. Java中使用了多進(jìn)程技術(shù) C. Java的單行注視以//開(kāi)頭 D. Java語(yǔ)言具有很高的安全性 3. 下面不屬于Java語(yǔ)言特點(diǎn)的一項(xiàng)是( ) A. 安全性 B. 分布式 C. 移植性 D. 編譯執(zhí)行 4. 下列語(yǔ)句中,正確的項(xiàng)是 ( ) A . int $e,a,b=10 B. char c,d=’a’ C. float e=0.0d D. double c=0.0f

    標(biāo)簽: Java A. B. C.

    上傳時(shí)間: 2017-01-04

    上傳用戶:netwolf

  • 漢諾塔!!! Simulate the movement of the Towers of Hanoi puzzle Bonus is possible for using animation

    漢諾塔!!! Simulate the movement of the Towers of Hanoi puzzle Bonus is possible for using animation eg. if n = 2 A→B A→C B→C if n = 3 A→C A→B C→B A→C B→A B→C A→C

    標(biāo)簽: the animation Simulate movement

    上傳時(shí)間: 2017-02-11

    上傳用戶:waizhang

  • This includes the project using a stereo vision to catch the ball shot from a high pressure air cann

    This includes the project using a stereo vision to catch the ball shot from a high pressure air cannon. The trajectory of the ball is located first by finding the ball color in the left and right camera. Then the trajectory is calculated to estimate the depth from the ball to the camera. The camera is calibrated to map the world coordinate to the camera coordinate and it can reach an accuracy over 90 . Enjoy

    標(biāo)簽: the includes pressure project

    上傳時(shí)間: 2013-12-24

    上傳用戶:cxl274287265

  • Input Signal Rise and Fall Tim

    All inputs of the C16x family have Schmitt-Trigger input characteristics. These Schmitt-Triggers are intended to always provide proper internal low and high levels, even if anundefined voltage level (between TTL-VIL and TTL-VIH) is externally applied to the pin.The hysteresis of these inputs, however, is very small, and can not be properly used in anapplication to suppress signal noise, and to shape slow rising/falling input transitions.Thus, it must be taken care that rising/falling input signals pass the undefined area of theTTL-specification between VIL and VIH with a sufficient rise/fall time, as generally usualand specified for TTL components (e.g. 74LS series: gates 1V/us, clock inputs 20V/us).The effect of the implemented Schmitt-Trigger is that even if the input signal remains inthe undefined area, well defined low/high levels are generated internally. Note that allinput signals are evaluated at specific sample points (depending on the input and theperipheral function connected to it), at that signal transitions are detected if twoconsecutive samples show different levels. Thus, only the current level of an input signalat these sample points is relevant, that means, the necessary rise/fall times of the inputsignal is only dependant on the sample rate, that is the distance in time between twoconsecutive evaluation time points. If an input signal, for instance, is sampled throughsoftware every 10us, it is irrelevant, which input level would be seen between thesamples. Thus, it would be allowable for the signal to take 10us to pass through theundefined area. Due to the sample rate of 10us, it is assured that only one sample canoccur while the signal is within the undefined area, and no incorrect transition will bedetected. For inputs which are connected to a peripheral function, e.g. capture inputs, thesample rate is determined by the clock cycle of the peripheral unit. In the case of theCAPCOM unit this means a sample rate of 400ns @ 20MHz CPU clock. This requiresinput signals to pass through the undefined area within these 400ns in order to avoidmultiple capture events.For input signals, which do not provide the required rise/fall times, external circuitry mustbe used to shape the signal transitions.In the attached diagram, the effect of the sample rate is shown. The numbers 1 to 5 in thediagram represent possible sample points. Waveform a) shows the result if the inputsignal transition time through the undefined TTL-level area is less than the time distancebetween the sample points (sampling at 1, 2, 3, and 4). Waveform b) can be the result ifthe sampling is performed more than once within the undefined area (sampling at 1, 2, 5,3, and 4).Sample points:1. Evaluation of the signal clearly results in a low level2. Either a low or a high level can be sampled here. If low is sampled, no transition willbe detected. If the sample results in a high level, a transition is detected, and anappropriate action (e.g. capture) might take place.3. Evaluation here clearly results in a high level. If the previous sample 2) had alreadydetected a high, there is no change. If the previous sample 2) showed a low, atransition from low to high is detected now.

    標(biāo)簽: Signal Input Fall Rise

    上傳時(shí)間: 2013-10-23

    上傳用戶:copu

  • 數(shù)字運(yùn)算

    數(shù)字運(yùn)算,判斷一個(gè)數(shù)是否接近素?cái)?shù) A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    標(biāo)簽: 數(shù)字 運(yùn)算

    上傳時(shí)間: 2015-05-21

    上傳用戶:daguda

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標(biāo)簽: represented integers group items

    上傳時(shí)間: 2016-01-17

    上傳用戶:jeffery

  • robocup 的高層決策機(jī)構(gòu) if ball is kickable kick ball to goal else if i am fastest player to ball and no

    robocup 的高層決策機(jī)構(gòu) if ball is kickable kick ball to goal else if i am fastest player to ball and no opponent can intercept ball intercept the ball else move to strategic position and pos ba

    標(biāo)簽: ball kickable robocup fastest

    上傳時(shí)間: 2014-01-13

    上傳用戶:1051290259

  • 1) Write a function reverse(A) which takes a matrix A of arbitrary dimensions as input and returns a

    1) Write a function reverse(A) which takes a matrix A of arbitrary dimensions as input and returns a matrix B consisting of the columns of A in reverse order. Thus for example, if A = 1 2 3 then B = 3 2 1 4 5 6 6 5 4 7 8 9 9 8 7 Write a main program to call reverse(A) for the matrix A = magic(5). Print to the screen both A and reverse(A). 2) Write a program which accepts an input k from the keyboard, and which prints out the smallest fibonacci number that is at least as large as k. The program should also print out its position in the fibonacci sequence. Here is a sample of input and output: Enter k>0: 100 144 is the smallest fibonacci number greater than or equal to 100. It is the 12th fibonacci number.

    標(biāo)簽: dimensions arbitrary function reverse

    上傳時(shí)間: 2016-04-16

    上傳用戶:waitingfy

  • 微電腦型數(shù)學(xué)演算式隔離傳送器

    特點(diǎn): 精確度0.1%滿刻度 可作各式數(shù)學(xué)演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT類比輸出功能 輸入與輸出絕緣耐壓2仟伏特/1分鐘(input/output/power) 寬范圍交直流兩用電源設(shè)計(jì) 尺寸小,穩(wěn)定性高

    標(biāo)簽: 微電腦 數(shù)學(xué)演算 隔離傳送器

    上傳時(shí)間: 2014-12-23

    上傳用戶:ydd3625

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