TLC2543是TI公司的12位串行模數(shù)轉(zhuǎn)換器,使用開(kāi)關(guān)電容逐次逼近技術(shù)完成A/D轉(zhuǎn)換過(guò)程。由于是串行輸入結(jié)構(gòu),能夠節(jié)省51系列單片機(jī)I/O資源;且價(jià)格適中,分辨率較高,因此在儀器儀表中有較為廣泛的應(yīng)用。 TLC2543的特點(diǎn) (1)12位分辯率A/D轉(zhuǎn)換器; (2)在工作溫度范圍內(nèi)10μs轉(zhuǎn)換時(shí)間; (3)11個(gè)模擬輸入通道; (4)3路內(nèi)置自測(cè)試方式; (5)采樣率為66kbps; (6)線性誤差±1LSBmax; (7)有轉(zhuǎn)換結(jié)束輸出EOC; (8)具有單、雙極性輸出; (9)可編程的MSB或LSB前導(dǎo); (10)可編程輸出數(shù)據(jù)長(zhǎng)度。 TLC2543的引腳排列及說(shuō)明 TLC2543有兩種封裝形式:DB、DW或N封裝以及FN封裝,這兩種封裝的引腳排列如圖1,引腳說(shuō)明見(jiàn)表1 TLC2543電路圖和程序欣賞 #include<reg52.h> #include<intrins.h> #define uchar unsigned char #define uint unsigned int sbit clock=P1^0; sbit d_in=P1^1; sbit d_out=P1^2; sbit _cs=P1^3; uchar a1,b1,c1,d1; float sum,sum1; double sum_final1; double sum_final; uchar duan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f}; uchar wei[]={0xf7,0xfb,0xfd,0xfe}; void delay(unsigned char b) //50us { unsigned char a; for(;b>0;b--) for(a=22;a>0;a--); } void display(uchar a,uchar b,uchar c,uchar d) { P0=duan[a]|0x80; P2=wei[0]; delay(5); P2=0xff; P0=duan[b]; P2=wei[1]; delay(5); P2=0xff; P0=duan[c]; P2=wei[2]; delay(5); P2=0xff; P0=duan[d]; P2=wei[3]; delay(5); P2=0xff; } uint read(uchar port) { uchar i,al=0,ah=0; unsigned long ad; clock=0; _cs=0; port<<=4; for(i=0;i<4;i++) { d_in=port&0x80; clock=1; clock=0; port<<=1; } d_in=0; for(i=0;i<8;i++) { clock=1; clock=0; } _cs=1; delay(5); _cs=0; for(i=0;i<4;i++) { clock=1; ah<<=1; if(d_out)ah|=0x01; clock=0; } for(i=0;i<8;i++) { clock=1; al<<=1; if(d_out) al|=0x01; clock=0; } _cs=1; ad=(uint)ah; ad<<=8; ad|=al; return(ad); } void main() { uchar j; sum=0;sum1=0; sum_final=0; sum_final1=0; while(1) { for(j=0;j<128;j++) { sum1+=read(1); display(a1,b1,c1,d1); } sum=sum1/128; sum1=0; sum_final1=(sum/4095)*5; sum_final=sum_final1*1000; a1=(int)sum_final/1000; b1=(int)sum_final%1000/100; c1=(int)sum_final%1000%100/10; d1=(int)sum_final%10; display(a1,b1,c1,d1); } }
上傳時(shí)間: 2013-11-19
上傳用戶:shen1230
#include<iom16v.h> #include<macros.h> #define uint unsigned int #define uchar unsigned char uint a,b,c,d=0; void delay(c) { for for(a=0;a<c;a++) for(b=0;b<12;b++); }; uchar tab[]={ 0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,
標(biāo)簽: AVR 單片機(jī) 數(shù)碼管
上傳時(shí)間: 2013-10-21
上傳用戶:13788529953
臺(tái)灣光寶光耦全系列產(chǎn)品 LTV-817S-TA1-C LTV-817X-B LTV-817X-C LTV-817X-C-SC LTV-817-D MOC3021 MOC3021S-TA1 MOC-3052 4N28 4N35 4N35S 4N35S-TA1 6N136 6N137 6N138 6N139 LTV-217-A-G LTV-217-B LTV-352T LTV-354T LTV-356T-B LTV-356T-C LTV-814 LTV-816X-B LTV-816X-C LTV-816X-D
標(biāo)簽: 光耦
上傳時(shí)間: 2013-11-12
上傳用戶:199311
題目:利用條件運(yùn)算符的嵌套來(lái)完成此題:學(xué)習(xí)成績(jī)>=90分的同學(xué)用A表示,60-89分之間的用B表示,60分以下的用C表示。 1.程序分析:(a>b)?a:b這是條件運(yùn)算符的基本例子。
上傳時(shí)間: 2015-01-08
上傳用戶:lifangyuan12
RSA算法 :首先, 找出三個(gè)數(shù), p, q, r, 其中 p, q 是兩個(gè)相異的質(zhì)數(shù), r 是與 (p-1)(q-1) 互質(zhì)的數(shù)...... p, q, r 這三個(gè)數(shù)便是 person_key,接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 這個(gè) m 一定存在, 因?yàn)?r 與 (p-1)(q-1) 互質(zhì), 用輾轉(zhuǎn)相除法就可以得到了..... 再來(lái), 計(jì)算 n = pq....... m, n 這兩個(gè)數(shù)便是 public_key ,編碼過(guò)程是, 若資料為 a, 將其看成是一個(gè)大整數(shù), 假設(shè) a < n.... 如果 a >= n 的話, 就將 a 表成 s 進(jìn)位 (s
標(biāo)簽: person_key RSA 算法
上傳時(shí)間: 2013-12-14
上傳用戶:zhuyibin
用CY7C63723設(shè)計(jì)的鼠標(biāo)固件程序 chip.c - include file that defines CY7C63723 constants - combi.c - main source file - combi.hex - Intel hex file for programming a CY7C63723 microcontroller - combi.lst - output listing from c-compiler for use with the CYDB debugger - macros.h - defines macros used in combi.c - ps2defs.h - defines PS/2 interface constants - usb_desc.h - defines the USB descriptors - usbdefs.h - defines USB interface constants
標(biāo)簽: C63723 63723 CY7 constants
上傳時(shí)間: 2014-02-15
上傳用戶:aappkkee
The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition
標(biāo)簽: government streamline important alphabet
上傳時(shí)間: 2015-06-09
上傳用戶:weixiao99
一個(gè)人力資源管理系統(tǒng)的實(shí)現(xiàn),采用了C/S和B/S混合的軟件體系結(jié)構(gòu),包括從問(wèn)題分析到具體實(shí)現(xiàn)的全過(guò)程
標(biāo)簽: 人力資源管理系統(tǒng)
上傳時(shí)間: 2013-12-16
上傳用戶:litianchu
使用工具為.net2003,涉及的語(yǔ)言包括c#、vb.net、托管c++,集C/S和B/S模式于一體,最主要一點(diǎn)是文檔相當(dāng)齊全。
上傳時(shí)間: 2015-09-04
上傳用戶:busterman
按照Clifford A . Shaffer《數(shù)據(jù)結(jié)構(gòu)與算法分析(第二版)》指導(dǎo),用C#實(shí)現(xiàn)的B+樹(shù),接口定義良好。最好重寫(xiě)“從文件載入新建樹(shù)部分”的代碼以提高建樹(shù)效率。實(shí)現(xiàn)細(xì)節(jié)之一:當(dāng)“需要插入子節(jié)點(diǎn)的節(jié)點(diǎn)”已滿而相鄰節(jié)點(diǎn)未滿時(shí)會(huì)平分兩者節(jié)點(diǎn)而不是分裂該節(jié)點(diǎn)。
標(biāo)簽: Clifford Shaffer 數(shù)據(jù)結(jié)構(gòu) 算法分析
上傳時(shí)間: 2016-07-02
上傳用戶:362279997
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