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Double

  • 將一個數(shù)進行階乘結(jié)果會是一個很大的數(shù)

    將一個數(shù)進行階乘結(jié)果會是一個很大的數(shù),在c語言里Double型也最大只能存一個兩位數(shù)的整數(shù)的階乘。本算法是對大數(shù)進行階乘計算。

    標簽:

    上傳時間: 2013-12-15

    上傳用戶:ggwz258

  • -- Hamming Decoder -- This Hamming decoder accepts an 8-bit Hamming code (produced by the encoder a

    -- Hamming Decoder -- This Hamming decoder accepts an 8-bit Hamming code (produced by the encoder above) and performs single error correction and Double error detection. -- download from: www.pld.com.cn & www.fpga.com.cn LIBRARY ieee USE ieee.std_logic_1164.ALL ENTITY hamdec IS PORT(hamin : IN BIT_VECTOR(0 TO 7) --d0 d1 d2 d3 p0 p1 p2 p4 dataout : OUT BIT_VECTOR(0 TO 3) --d0 d1 d2 d3 sec, ded, ne : OUT BIT) --diagnostic outputs END hamdec ARCHITECTURE ver1 OF hamdec IS BEGIN

    標簽: Hamming produced Decoder decoder

    上傳時間: 2017-07-15

    上傳用戶:520

  • hcon是工作在Linux控制臺下的高效雙字節(jié)中/日/韓(CJK)虛擬終端

    hcon是工作在Linux控制臺下的高效雙字節(jié)中/日/韓(CJK)虛擬終端,就像DOS環(huán)境中的UCDOS一樣,為控制臺(console)環(huán)境提供完整的雙字節(jié)語言環(huán)境。-zhcon work in the Linux console is under the efficient Double-byte Chinese / Japanese / Korean (CJK) virtual terminal, just like DOS environment UCDOS same for console (console) environment to provide a complete Double-byte language environments.

    標簽: Linux hcon CJK 控制臺

    上傳時間: 2013-12-26

    上傳用戶:wsf950131

  • 購物車系統(tǒng)中的用戶類

    購物車系統(tǒng)中的用戶類,private Integer id private Product product private String shopname private Double shopprice

    標簽: 用戶

    上傳時間: 2017-08-03

    上傳用戶:從此走出陰霾

  • 編寫一個程序

    編寫一個程序,輸出基本數(shù)據(jù)類型char, short, int, long, float, Double和指針類型void *, char *, short *, int *, long *, float *, Double *的數(shù)據(jù)類型的長度。

    標簽: 編寫 程序

    上傳時間: 2013-12-26

    上傳用戶:pompey

  • c語言深度剖析

    第一章關(guān)鍵字...................................................................................................................................9 1.1,最寬恒大量的關(guān)鍵字----auto..........................................................................................11 1.2,最快的關(guān)鍵字---- register............................................................................................... 11 1.2.1,皇帝身邊的小太監(jiān)----寄存器............................................................................. 11 1.2.2,使用register 修飾符的注意點.............................................................................11 1.3,最名不符實的關(guān)鍵字----static........................................................................................12 1.3.1,修飾變量...............................................................................................................12 1.3.2,修飾函數(shù)...............................................................................................................13 1.4,基本數(shù)據(jù)類型----short、int、long、char、float、Double........................................... 13 1.4.1,數(shù)據(jù)類型與“模子”............................................................................................... 14 1.4.2,變量的命名規(guī)則...................................................................................................14 1.5,最冤枉的關(guān)鍵字----sizeof...............................................................................................18 1.5.1,常年被人誤認為函數(shù)...........................................................................................18 1.5.2,sizeof(int)*p 表示什么意思?........................................................................18 1.4,signed、unsigned 關(guān)鍵字................................................................................................19 1.6,if、else 組合.................................................................................................................... 20 1.6.1,bool 變量與“零值”進行比較...............................................................................20 1.6.2, float 變量與“零值”進行比較.................................................................................21 1.6.3,指針變量與“零值”進行比較...............................................................................21 1.6.4,else 到底與哪個if 配對呢?...............................................................................22 1.6.5,if 語句后面的分號............................................................................................... 23 1.6.6,使用if 語句的其他注意事項.............................................................................. 24 1.7,switch、case 組合........................................................................................................... 24 1.7.1,不要拿青龍偃月刀去削蘋果.............................................................................. 24 1.7.2,case 關(guān)鍵字后面的值有什么要求嗎?.............................................................. 25 1.7.3,case 語句的排列順序...........................................................................................25 1.7.4,使用case 語句的其他注意事項..........................................................................27 1.8,do、while、for 關(guān)鍵字................................................................................................... 28 1.8.1,break 與continue 的區(qū)別.....................................................................................28 1.8.2,循環(huán)語句的注意點...............................................................................................29 1.9,goto 關(guān)鍵字......................................................................................................................30 1.10,void 關(guān)鍵字....................................................................................................................31 1.10.1,void a?............................................................................................................31 1.10,return 關(guān)鍵字................................................................................................................. 34 1.11,const 關(guān)鍵字也許該被替換為readolny....................................................................... 34 1.11.2,節(jié)省空間,避免不必要的內(nèi)存分配,同時提高效率.................................... 35 1.12,最易變的關(guān)鍵字----volatile.......................................................................................... 36 1.13,最會帶帽子的關(guān)鍵字----extern.................................................................................... 37 1.14,struct 關(guān)鍵字..................................................................................................................38

    標簽: c語言深度剖析

    上傳時間: 2015-05-01

    上傳用戶:cascas

  • 道理特分解法

    #include "iostream" using namespace std; class Matrix { private: Double** A; //矩陣A Double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend Double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new Double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new Double* [x]; for(int i=0;i<x;i++) A[i]=new Double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構(gòu)中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個:"<<endl; cin>>b[j]; } } Double* Dooli(Matrix& A) { Double *Xn=new Double [A.size]; Matrix L(A.size),U(A.size); //分別求得U,L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U,L的第r行,第r列 Double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計算U得:"<<endl; U.Disp(); cout<<"計算L的:"<<endl; L.Disp(); Double *Y=new Double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ Double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ Double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); Double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; } 

    標簽: 道理特分解法

    上傳時間: 2018-05-20

    上傳用戶:Aa123456789

  • 隊列函數(shù)queue

    參照棧類模板的例子編寫一個隊列類模板class <T> Queue,私有成員包括:隊首指針Front,隊尾指針Tail,隊列容積max。實現(xiàn):構(gòu)造函數(shù)Queue,復(fù)制構(gòu)造函數(shù)Queue,析構(gòu)函數(shù)~Queue,入隊函數(shù)In,出隊函數(shù)Out(每次出隊,后面的元素自動前移一位),判隊列空函數(shù)Empty。并分別用隊列類模板定義int和Double對象,通過實例調(diào)用各個成員函數(shù)。

    標簽: Queue 函數(shù) Double class Front Empty 隊列 Tail 模板 Out

    上傳時間: 2020-05-04

    上傳用戶:1qw2e3r4t5y6u7i8

  • Broadband Access Networks Technologies

    At present, there is a strong worldwide push toward bringing fiber closer to indi- vidual homes and businesses. Fiber-to-the-Home/Business (FTTH/B) or close to it networks are poised to become the next major success story for optical fiber com- munications. In fact, FTTH connections are currently experiencing Double-digit or even higher growth rates, e.g., in the United States the annual growth rate was 112% between September 2006 and September 2007, and their presence can add value of U.S. $4,000–15,000 to the selling price of a home.

    標簽: Technologies Broadband Networks Access

    上傳時間: 2020-05-26

    上傳用戶:shancjb

  • Interference Analysis

    We were on the lookout for ice. I was in a 32 foot sailing yacht with writer and explorer Tristan Gooley, undertaking a Double-handed sail from Scotland through the Faroes up to 66 33 45.7 N and the midnight sun. Now sailing out of the Arctic Circle we were approaching Iceland from the north, heading for the Denmark Straits, where ice flowed south. The Admiralty Pilot warned of bergs but the ice charts we had sailed with were over a week old. We needed an update.

    標簽: Interference Analysis

    上傳時間: 2020-05-27

    上傳用戶:shancjb

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