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ELEMENTS

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential ELEMENTS of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    標簽: essential textbooks the European

    上傳時間: 2013-12-18

    上傳用戶:498732662

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential ELEMENTS of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    標簽: essential textbooks the European

    上傳時間: 2014-01-07

    上傳用戶:qilin

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential ELEMENTS of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    標簽: essential textbooks the European

    上傳時間: 2013-12-17

    上傳用戶:zl5712176

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential ELEMENTS of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    標簽: essential textbooks the European

    上傳時間: 2013-12-09

    上傳用戶:stella2015

  • While there are many textbooks about the European Union (EU), Clive Archer covers the essential el

    While there are many textbooks about the European Union (EU), Clive Archer covers the essential ELEMENTS of the EU clearly and con- cisely, outlining the key debates and issues it faces today

    標簽: essential textbooks the European

    上傳時間: 2014-11-21

    上傳用戶:cursor

  • 24小時學通Qt編程

    Qt學習資料,界面設計必備。一個跨平臺的C++應用程序開發框架。廣泛用于開發GUI程序,這種情況下又被稱為部件工具箱。也可用于開發非GUI程序,比如控制臺工具和服務器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop ELEMENTS、VirtualBox與Mathematica以及被Autodesk 、歐洲空間局、夢工廠、Google、HP、KDE、盧卡斯影業、西門子公司、富豪集團, 華特迪士尼動畫制作公司、三星集團、飛利浦、Panasonic 所使用。

    標簽: Qt

    上傳時間: 2015-12-06

    上傳用戶:filling87

  • 《Qt及Qt Quick開發實戰精解》代碼

    《Qt及Qt Quick開發實戰精解》代碼。Qt(官方發音同cute 發音為/kju:t/,雖然也俗稱為Q.T.發音為/kju:ti?/")是一個跨平臺的C++應用程序開發框架。廣泛用于開發GUI程序,這種情況下又被稱為部件工具箱。也可用于開發非GUI程序,比如控制臺工具和服務器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop ELEMENTS、VirtualBox與Mathematica以及被Autodesk 、歐洲空間局、夢工廠、Google、HP、KDE、盧卡斯影業、西門子公司、富豪集團, 華特迪士尼動畫制作公司、三星集團、飛利浦、Panasonic 所使用。

    標簽: 《Qt及Qt Quick開發實戰精解》代碼

    上傳時間: 2015-12-06

    上傳用戶:filling87

  • 計算本征值程序

    Computes all eigenvalues and eigenvectors of a real symmetric matrix a, ! which is of size n by n, stored in a physical np by np array. ! On output, ELEMENTS of a above the diagonal are destroyed. ! d returns the eigenvalues of a in its first n ELEMENTS. ! v is a matrix with the same logical and physical dimensions as a, ! whose columns contain, on output, the normalized eigenvectors of a. ! nrot returns the number of Jacobi rotations that were required. ! Please notice that the eigenvalues are not ordered on output. ! If the sorting is desired, the addintioal routine "eigsrt" ! can be invoked to reorder the output of jacobi.

    標簽: 計算 程序

    上傳時間: 2016-06-04

    上傳用戶:1512313

  • C語言算法排序問題

    1.Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two ELEMENTS in S whose sum is exactly x. (Implement exercise 2.3-7.)

    標簽: 算法 排序

    上傳時間: 2017-04-01

    上傳用戶:糖兒水嘻嘻

  • c語言算法排序

    1.Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two ELEMENTS in S whose sum is exactly x. (Implement exercise 2.3-7.) #include<stdio.h> #include<stdlib.h> void merge(int arr[],int low,int mid,int high){      int i,k;      int *tmp=(int*)malloc((high-low+1)*sizeof(int));      int left_low=low;      int left_high=mid;      int right_low=mid+1;      int right_high=high;      for(k=0;left_low<=left_high&&right_low<=right_high;k++)      {      if(arr[left_low]<=arr[right_low]){                                        tmp[k]=arr[left_low++];                                        }      else{           tmp[k]=arr[right_low++];           } }             if(left_low<=left_high){                              for(i=left_low;i<=left_high;i++){                                                               tmp[k++]=arr[i];                                                               }                              }       if(right_low<=right_high){                              for(i=right_low;i<=right_high;i++)                                                                tmp[k++]=arr[i];                                                        }                              for(i=0;i<high-low+1;i++)                                                       arr[low+i]=tmp[i];       } void merge_sort(int a[],int p,int r){      int q;      if(p<r){              q=(p+r)/2;              merge_sort(a,p,q);              merge_sort(a,q+1,r);              merge(a,p,q,r);              }      } int main(){     int a[8]={3,5,8,6,4,1,1};     int i,j;     int x=10;     merge_sort(a,0,6);     printf("after Merging-Sort:\n");     for(i=0;i<7;i++){                      printf("%d",a[i]);                      }     printf("\n");     i=0;j=6;     do{                                    if(a[i]+a[j]==x){                                  printf("exist");                                  break;                                  }                  if(a[i]+a[j]>x)                                 j--;                  if(a[i]+a[j]<x)                                 i++;                       }while(i<=j);     if(i>j)              printf("not exist");     system("pause");     return 0;     }

    標簽: c語言 算法 排序

    上傳時間: 2017-04-01

    上傳用戶:糖兒水嘻嘻

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