While there are many textbooks about the European Union (EU), Clive Archer covers the essential Elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today
標簽： essential textbooks the European
上傳時間： 2013-12-18
上傳用戶：498732662
While there are many textbooks about the European Union (EU), Clive Archer covers the essential Elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today
標簽： essential textbooks the European
上傳時間： 2014-01-07
上傳用戶：qilin
While there are many textbooks about the European Union (EU), Clive Archer covers the essential Elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today
標簽： essential textbooks the European
上傳時間： 2013-12-17
上傳用戶：zl5712176
While there are many textbooks about the European Union (EU), Clive Archer covers the essential Elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today
標簽： essential textbooks the European
上傳時間： 2013-12-09
上傳用戶：stella2015
While there are many textbooks about the European Union (EU), Clive Archer covers the essential Elements of the EU clearly and con- cisely, outlining the key debates and issues it faces today
標簽： essential textbooks the European
上傳時間： 2014-11-21
上傳用戶：cursor
Qt學(xué)習(xí)資料，界面設(shè)計必備。一個跨平臺的C++應(yīng)用程序開發(fā)框架。廣泛用于開發(fā)GUI程序，這種情況下又被稱為部件工具箱。也可用于開發(fā)非GUI程序，比如控制臺工具和服務(wù)器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop Elements、VirtualBox與Mathematica以及被Autodesk 、歐洲空間局、夢工廠、Google、HP、KDE、盧卡斯影業(yè)、西門子公司、富豪集團, 華特迪士尼動畫制作公司、三星集團、飛利浦、Panasonic 所使用。
標簽： Qt
上傳時間： 2015-12-06
上傳用戶：filling87
《Qt及Qt Quick開發(fā)實戰(zhàn)精解》代碼。Qt（官方發(fā)音同cute 發(fā)音為/kju:t/，雖然也俗稱為Q.T.發(fā)音為/kju:ti?/"）是一個跨平臺的C++應(yīng)用程序開發(fā)框架。廣泛用于開發(fā)GUI程序，這種情況下又被稱為部件工具箱。也可用于開發(fā)非GUI程序，比如控制臺工具和服務(wù)器。Qt使用于OPIE、Skype、VLC media player、Adobe Photoshop Elements、VirtualBox與Mathematica以及被Autodesk 、歐洲空間局、夢工廠、Google、HP、KDE、盧卡斯影業(yè)、西門子公司、富豪集團, 華特迪士尼動畫制作公司、三星集團、飛利浦、Panasonic 所使用。
標簽： 《Qt及Qt Quick開發(fā)實戰(zhàn)精解》代碼
上傳時間： 2015-12-06
上傳用戶：filling87
Computes all eigenvalues and eigenvectors of a real symmetric matrix a, ! which is of size n by n, stored in a physical np by np array. ! On output, Elements of a above the diagonal are destroyed. ! d returns the eigenvalues of a in its first n Elements. ! v is a matrix with the same logical and physical dimensions as a, ! whose columns contain, on output, the normalized eigenvectors of a. ! nrot returns the number of Jacobi rotations that were required. ! Please notice that the eigenvalues are not ordered on output. ! If the sorting is desired, the addintioal routine "eigsrt" ! can be invoked to reorder the output of jacobi.
上傳時間： 2016-06-04
上傳用戶：1512313
1．Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two Elements in S whose sum is exactly x. (Implement exercise 2.3-7.)
上傳時間： 2017-04-01
上傳用戶：糖兒水嘻嘻
1．Describe a Θ(n lg n)-time algorithm that, given a set S of n integers and another integer x, determines whether or not there exist two Elements in S whose sum is exactly x. (Implement exercise 2.3-7.) #include<stdio.h> #include<stdlib.h> void merge(int arr[],int low,int mid,int high){ int i,k; int *tmp=(int*)malloc((high-low+1)*sizeof(int)); int left_low=low; int left_high=mid; int right_low=mid+1; int right_high=high; for(k=0;left_low<=left_high&&right_low<=right_high;k++) { if(arr[left_low]<=arr[right_low]){ tmp[k]=arr[left_low++]; } else{ tmp[k]=arr[right_low++]; } } if(left_low<=left_high){ for(i=left_low;i<=left_high;i++){ tmp[k++]=arr[i]; } } if(right_low<=right_high){ for(i=right_low;i<=right_high;i++) tmp[k++]=arr[i]; } for(i=0;i<high-low+1;i++) arr[low+i]=tmp[i]; } void merge_sort(int a[],int p,int r){ int q; if(p<r){ q=(p+r)/2; merge_sort(a,p,q); merge_sort(a,q+1,r); merge(a,p,q,r); } } int main(){ int a[8]={3,5,8,6,4,1,1}; int i,j; int x=10; merge_sort(a,0,6); printf("after Merging-Sort:\n"); for(i=0;i<7;i++){ printf("%d",a[i]); } printf("\n"); i=0;j=6; do{ if(a[i]+a[j]==x){ printf("exist"); break; } if(a[i]+a[j]>x) j--; if(a[i]+a[j]<x) i++; }while(i<=j); if(i>j) printf("not exist"); system("pause"); return 0; }
上傳時間： 2017-04-01
上傳用戶：糖兒水嘻嘻
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