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  • BISON-C: A one-dimensional transport and burnup calculation code with consideration of actinides and

    BISON-C: A one-dimensional transport and burnup calculation code with consideration of actinides and fission products Auteur(s) / Author(s) CETNAR J. (1) GRONEK P. (1) Affiliation(s) du ou des auteurs / Author(s) Affiliation(s) (1) University of Mining and Metallurgy, Faculty of Physics and Nuclear Techniques, 30 059 Cracow, POLOGNE

    標簽: one-dimensional consideration calculation and

    上傳時間: 2015-07-17

    上傳用戶:wendy15

  • JavaTV Program source code Need to play Windows Media files and streams, mpeg4 video or DVDs in j

    JavaTV Program source code Need to play Windows Media files and streams, mpeg4 video or DVDs in java? Access WDM capture devices? Control a firewire DVCam? Then maybe this can help you. dsj is an ongoing project to provide a java wrapper around Microsoft s DirectShow API. It offers a set of high level classes that give java easy access to functionality widely missed by java programmers and also lets you dive deeper into the interiors of Windows core api for 2D media. On the java side dsj tries to keep things open as possible - you may use it standalone or let it feed data into JMF or other APIs.

    標簽: Program Windows streams JavaTV

    上傳時間: 2013-12-17

    上傳用戶:TF2015

  • % 該Matlab程序基于牛頓-拉夫遜算法

    % 該Matlab程序基于牛頓-拉夫遜算法,用于計算已知導納矩陣、PQ節點、PV節點、平衡節點(UA)的電力網絡潮流 % U - 各節點母線電壓 S - 各節點注入功率 S_net - 電力網絡總損耗 % PQ_P - 實算PQ節點注入有功功率 PQ_Q - 實算PQ節點注入無功功率 % delt_PQ_P - 實算PQ節點有功功率修正值 delt_PQ_Q -實算PQ節點無功功率修正值 % delt_UA_P - 實平衡節點有功功率修正值 delt_U_2 - 實平衡節點電壓平方修正值 % delt_PQV - 實算P Q U^2修正值 J - 雅可比矩陣 % e - 電壓實部 f - 電壓虛部 delt_ef - 電壓實部與虛部修正值

    標簽: Matlab 程序 牛頓 算法

    上傳時間: 2015-07-23

    上傳用戶:王楚楚

  • 給定n 個整數a ,a , ,an 1 2  組成的序列

    給定n 個整數a ,a , ,an 1 2  組成的序列, a n i | |£ ,1 £ i £ n。如果對于i £ j ,有 0 = å = j k i k a ,則稱序列區間i i j a , a , , a +1  為一個零和區間,相應的區間長度為j-i+1。

    標簽: 61516 an 整數 序列

    上傳時間: 2015-07-23

    上傳用戶:zhangzhenyu

  • 給定n 個整數a ,a , ,an 1 2  組成的序列

    給定n 個整數a ,a , ,an 1 2  組成的序列, a n i | |£ ,1 £ i £ n。如果對于i £ j ,有 0 = å = j k i k a ,則稱序列區間i i j a , a , , a +1  為一個零和區間,相應的區間長度為j-i+1。

    標簽: 61516 an 整數 序列

    上傳時間: 2013-12-21

    上傳用戶:偷心的海盜

  • CrossPointNo=53 %%%輸入圖中節點的總數目 對已知的邊進行賦值

    CrossPointNo=53 %%%輸入圖中節點的總數目 對已知的邊進行賦值,注意:有向圖的Cost(i,j)=Cost(j,i)

    標簽: CrossPointNo 53 輸入 節點

    上傳時間: 2015-08-08

    上傳用戶:天誠24

  • 假近鄰法(False Nearest Neighbor, FNN)計算嵌入維的Matlab程序 文件夾說明: Main_FNN.m - 程序主函數

    假近鄰法(False Nearest Neighbor, FNN)計算嵌入維的Matlab程序 文件夾說明: Main_FNN.m - 程序主函數,直接運行此文件即可 LorenzData.dll - 產生Lorenz時間序列 PhaSpaRecon.m - 相空間重構 fnn_luzhenbo.dll - 假近鄰計算主函數 SearchNN.dll - 近鄰點搜索 buffer_SearchNN_1.dll - 近鄰點搜索緩存1 buffer_SearchNN_2.dll - 近鄰點搜索緩存2 參考文獻: M.B.Kennel, R.Brown, H.D.I.Abarbanel. Determining embedding dimension for phase-space reconstruction using a geometrical construction[J]. Phys. Rev. A 1992,45:3403.

    標簽: Main_FNN Neighbor Nearest Matlab

    上傳時間: 2013-12-10

    上傳用戶:songnanhua

  • 摘要:采用Foxpro2.5T3數據庫開發平臺開發了一種計算機機房和網吧收費管理系統

    摘要:采用Foxpro2.5T3數據庫開發平臺開發了一種計算機機房和網吧收費管理系統,該系 統的帳戶信h,基」幾條形碼識別身份,也可以直接鍵入用戶帳戶的數碼,所需的用戶信h,完全山 計算機集中管理。該系統是一種重l從對上機計費、值班人員工作日志與收費情況進行詳細記 錄,J{含有信任委托技術在內的機房網吧管理收費系統,系統成木低廉、運行速度快、代碼緊 湊、功能健全、開發平臺簡單。

    標簽: Foxpro 2.5 數據庫 開發平臺

    上傳時間: 2013-12-23

    上傳用戶:wkchong

  • 一個基于網格和最近鄰居的聚類算法 Similarity(x, y) = size ( SKNN(x) SKNN(y) )

    一個基于網格和最近鄰居的聚類算法 Similarity(x, y) = size ( SKNN(x) SKNN(y) ),while Link(x, y)=1

    標簽: SKNN Similarity size 網格

    上傳時間: 2014-01-14

    上傳用戶:zhangliming420

  • ACM試題An Easy Problem Description As we known, data stored in the computers is in binary form. The

    ACM試題An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".

    標簽: Description computers Problem binary

    上傳時間: 2013-12-11

    上傳用戶:libenshu01

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