thinkinjava2English
Thinking in Java,
2nd Edition, Release 11
To be published by Prentice-Hall mid-June, 2000
Bruce Eckel, President,
MindView, Inc.
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標簽：
thinkinjava2English
Prentice-Hall
published
Thinking
上傳時間：
2014-01-15
上傳用戶：ANRAN
Ink Blotting
One method for escaping from a maze is via ‘ink-blotting’. In this method your starting square
is marked with the number ‘1’. All free, valid squares north, south, east and west around the
number ‘1‘ are marked with a number ‘2’. In the next step, all free, valid squares around the two
are marked with a ‘3’ and the process is repeated iteratively until :
The exit is found (a free square other than the starting position is reached on the very edge
of the maze), or,
No more free squares are available, and hence no exit is possible.
標簽：
method
ink-blotting
Blotting
escaping
上傳時間：
2014-12-03
上傳用戶：123啊
河內塔問題
#include<stdio.h>
#include<stdlib.h>
int fun_a(int)
void fun_b(int,int,int,int)
int main(void)
{
int n
int option
printf("題目二:河內塔問題\n")
printf("請輸入要搬移的圓盤數目\n")
scanf("％d",&n)
printf("最少搬移的次數為％d次\n",fun_a(n))
printf("是否顯示移動過程? 是請輸入1,否則輸入0\n")
scanf("％d",&option)
if(option==1)
{
fun_b(n,1,2,3)
}
system("pause")
return 0
}
int fun_a(int n)
{
int sum1=2,sum2=0,i
for(i=n i>1 i--)
{
sum1=sum1*2
}
sum2=sum1-1
return sum2
}
void fun_b(int n,int left,int mid,int right)
{
if(n==1)
printf("把第％d個盤子從第％d座塔移動到第％d座塔\n",n,left,right)
else
{
fun_b(n-1,left,right,mid)
printf("把第％d個盤子從第％d座塔移動到第％d座塔\n",n,left,right)
fun_b(n-1,mid,left,right)
}
}
標簽：
int
include
stdlib
fun_a
上傳時間：
2016-12-08
上傳用戶：努力努力再努力
