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On-The-<b>Go</b>

  • SystemC_tutorial

    This tutorial will focus on the strong connection between C++ and SystemC by making the analogy between Hardware modeling and Object-Oriented modeling. The first section will look at the creation of Hardware components in C++. The second section will highlight the benefits of a SystemC implementation. Lastly, a worked example will allow you to gain experience with the steps involved in the creation, and simulation, of a SystemC design. 

    標簽: systemc

    上傳時間: 2015-06-25

    上傳用戶:ycc‘eeworm

  • SharpPcap c#抓包實現時時獲取網卡信息

    SharpPcap c#抓包實現時時獲取網卡信息 SharpPcap tutorial: a step by step guide to using SharpPcap The text of this tutorial is taken directly from WinPcap's official tutorial but is modified to show the C# use of the SharpPcap library. All examples can be downloaded together with SharpPcap source code from SharpPcap 's homepage. The WinPcap library must be installed before attempting to run any of these examples, so please download and install the latest version from WinPcap's download page. SharpPcap was written and tested using .NET v1.1 and Windows 2000/XP. I have no idea about other .NET and Windows versions. If you do try it, please report your results. The following topics are covered in this tutorial: Obtaining the device list Obtaining advanced information about installed devices Opening an adapter and capturing packets Capturing packets without the event handler Filtering the traffic Interpreting the packets Handling offline dump files Sending Packets Gathering Statistics on the network traffic 1. Obtaining the device list

    標簽: SharpPcap c#抓包 獲取網卡信息

    上傳時間: 2015-07-06

    上傳用戶:muzongda

  • GRE數學寶典(英文原版GRE Math Bible)

    GRE 數學圣經,下面是詳細的英文介紹: Comprehensive Prep for GRE Math Every year, students pay $1,000 and more to test prep companies to prepare for the math section of the GRE. Now you can get the same preparation in a book. Although the GRE math section is difficult, it is very learnable. GRE Math Bible presents a thorough analysis of GRE math and introduces numerous analytic techniques that will help you immensely, not only on the GRE but in graduate school as well.

    標簽: GRE Math 數學

    上傳時間: 2015-08-22

    上傳用戶:東大寺的

  • GoAhead Webs 2.1.5

    ===================================== GoAhead WebServer 2.1.8 Release Notes ===================================== .. NOTES: .. This document is maintained using the reStructuredText markup system. .. You may download this from <http://docutils.sf.net>. Also note that running .. the docutils code requires that a version of Python version 2.1 or later .. be installed on the machine. Since the GoAhead release procedure itself .. runs in Python, this should not be a problem. .. .. To add new entries to the release notes, follow the markup shown below .. (releases should be underlined with a row of '=' characters, each item .. noted within a release should be underlined with '-' characters.

    標簽: web server embedded arm

    上傳時間: 2016-01-30

    上傳用戶:zrxkn

  • GoAhead Webs 2.1.5 embedded webserver arm

    ===================================== GoAhead WebServer 2.1.8 Release Notes ===================================== .. NOTES: .. This document is maintained using the reStructuredText markup system. .. You may download this from <http://docutils.sf.net>. Also note that running .. the docutils code requires that a version of Python version 2.1 or later .. be installed on the machine. Since the GoAhead release procedure itself .. runs in Python, this should not be a problem. .. .. To add new entries to the release notes, follow the markup shown below .. (releases should be underlined with a row of '=' characters, each item .. noted within a release should be underlined with '-' characters.

    標簽: web html embed server arm small http

    上傳時間: 2016-01-30

    上傳用戶:zrxkn

  • stm3210e_eval

    Description The STM3210E-EVAL evaluation board is a complete development platform for STMicroelectronic's ARM Cortex-M3 core-based STM32F103ZET6 or STM32F103ZGT6 microcontroller. The range of hardware features on the board help you to evaluate all peripherals (LCD, SPI Flash, USART, IrDA, USB, audio, CAN bus, smartcard, MicroSD Card, NOR Flash, NAND Flash, SRAM, temperature sensor, audio DAC and motor control) and develop your own applications.

    標簽: stm3210e_eval

    上傳時間: 2016-03-27

    上傳用戶:guozhenhui1st

  • R for beginners

    The goal of the present document is to give a starting point for people newly interested in R. I chose to emphasize on the understanding of how R works, with the aim of a beginner, rather than expert use.

    標簽: R

    上傳時間: 2016-04-08

    上傳用戶:mrchen...

  • 離散實驗 一個包的傳遞 用warshall

     實驗源代碼 //Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("請輸入矩陣第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可傳遞閉包關系矩陣是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元關系的可傳遞閉包\n"); void warshall(int,int); int k , n; printf("請輸入矩陣的行數 i: "); scanf("%d",&k); 四川大學實驗報告 printf("請輸入矩陣的列數 j: "); scanf("%d",&n); warshall(k,n); } 

    標簽: warshall 離散 實驗

    上傳時間: 2016-06-27

    上傳用戶:梁雪文以

  • Bio Medical CMOS IC

    A major societal challenge for the decades to come will be the delivery of effective medical services while at the same time curbing the growing cost of healthcare. It is expected that new concepts-particularly electronically assisted healthcare will provide an answer. This will include new devices, new medical services as well as networking. On the device side, impressive innovation has been made possible by micro- and nanoelectronics or CMOS Integrated Circuits. Even higher accuracy and smaller form factor combined with reduced cost and increased convenience of use are enabled by incorporation of CMOS IC design in the realization of biomedical systems. The compact hearing aid devices and current pacemakers are good examples of how CMOS ICs bring about these new functionalities and services in the medical field. Apart from these existing applications, many researchers are trying to develop new bio-medical solutions such as Artificial Retina, Deep Brain Stimulation, and Wearable Healthcare Systems. These are possible by combining the recent advances of bio-medical technology with low power CMOS IC technology.

    標簽: Medical CMOS Bio IC

    上傳時間: 2017-02-06

    上傳用戶:linyj

  • 道理特分解法

    #include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個:"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U,L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U,L的第r行,第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計算U得:"<<endl; U.Disp(); cout<<"計算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; } 

    標簽: 道理特分解法

    上傳時間: 2018-05-20

    上傳用戶:Aa123456789

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