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S-<b>IS</b>OMAP

  • 數(shù)據(jù)結(jié)構(gòu)課程設(shè)計(jì) 數(shù)據(jù)結(jié)構(gòu)B+樹 B+ tree Library

    數(shù)據(jù)結(jié)構(gòu)課程設(shè)計(jì) 數(shù)據(jù)結(jié)構(gòu)B+樹 B+ tree Library

    標(biāo)簽: Library tree 數(shù)據(jù)結(jié)構(gòu)

    上傳時(shí)間: 2013-12-31

    上傳用戶:semi1981

  • The primary goal of MySQL and Java Developer’s Guide is to provide a comprehensive approach to writ

    The primary goal of MySQL and Java Developer’s Guide is to provide a comprehensive approach to writing code from a Java application to a MySQL database using the industry standard: JDBC. As you will see later in this Introduction, the chapter titles indicate what area of database connectivity and manipulation they cover. The chapters are ordered to reflect the JDBC specification, but we aren’t here to simply describe the specification.

    標(biāo)簽: comprehensive Developer approach primary

    上傳時(shí)間: 2014-01-13

    上傳用戶:lnnn30

  • SQL: A Beginner’s Guide is recommended for anyone trying to build a foundation in SQL programming.

    SQL: A Beginner’s Guide is recommended for anyone trying to build a foundation in SQL programming. The book is designed specifically for those who are new or relatively new to SQL however, those of you who need a refresher in SQL will also find this book beneficial.Whether you’re an experienced programmer, have had some web development experience, are a database administrator, or are new to programming and databases, SQL: A Beginner’s Guide provides a strong foundation that will be useful to any of you wishing to learn more about SQL.

    標(biāo)簽: recommended programming foundation SQL

    上傳時(shí)間: 2013-12-24

    上傳用戶:Amygdala

  • 給定兩個(gè)集合A、B

    給定兩個(gè)集合A、B,集合內(nèi)的任一元素x滿足1 ≤ x ≤ 109,并且每個(gè)集合的元素個(gè)數(shù)不大于105。我們希望求出A、B之間的關(guān)系。 任 務(wù)?。航o定兩個(gè)集合的描述,判斷它們滿足下列關(guān)系的哪一種: A是B的一個(gè)真子集,輸出“A is a proper subset of B” B是A的一個(gè)真子集,輸出“B is a proper subset of A” A和B是同一個(gè)集合,輸出“A equals B” A和B的交集為空,輸出“A and B are disjoint” 上述情況都不是,輸出“I m confused!”

    標(biāo)簽:

    上傳時(shí)間: 2017-03-15

    上傳用戶:yulg

  • This routine calls the glpk library to solve a LP/MIP problem. A typical LP problem has following s

    This routine calls the glpk library to solve a LP/MIP problem. A typical LP problem has following structure: [min|max] C x s.t. Ax ["="|"<="|">="] b {x <= UB} {x >= LB} The calling syntax is: [XMIN,FMIN,STATUS,EXTRA]=glpkmex(SENSE,C,A,B,CTYPE,LB,UB,... VARTYPE,PARAM,LPSOLVER,SAVE)

    標(biāo)簽: problem following routine library

    上傳時(shí)間: 2014-12-01

    上傳用戶:changeboy

  • 本ppt介紹了多層C/S型數(shù)據(jù)庫(kù)應(yīng)用

    本ppt介紹了多層C/S型數(shù)據(jù)庫(kù)應(yīng)用,多層數(shù)據(jù)庫(kù)應(yīng)用的結(jié)構(gòu),典型的三層C/S結(jié)構(gòu),B/S型數(shù)據(jù)庫(kù)應(yīng)用,典型的B/S結(jié)構(gòu)(三層),結(jié)合三層C/S的B/S結(jié)構(gòu)(四層),使用多層分布式應(yīng)用結(jié)構(gòu)的優(yōu)勢(shì),高可靠性的多層分布式結(jié)構(gòu)等方面的內(nèi)容

    標(biāo)簽: 多層 數(shù)據(jù)庫(kù)

    上傳時(shí)間: 2015-03-15

    上傳用戶:songnanhua

  • * 高斯列主元素消去法求解矩陣方程AX=B,其中A是N*N的矩陣,B是N*M矩陣 * 輸入: n----方陣A的行數(shù) * a----矩陣A * m----矩陣B的列數(shù) * b----矩

    * 高斯列主元素消去法求解矩陣方程AX=B,其中A是N*N的矩陣,B是N*M矩陣 * 輸入: n----方陣A的行數(shù) * a----矩陣A * m----矩陣B的列數(shù) * b----矩陣B * 輸出: det----矩陣A的行列式值 * a----A消元后的上三角矩陣 * b----矩陣方程的解X

    標(biāo)簽: 矩陣 AX 高斯 元素

    上傳時(shí)間: 2015-07-26

    上傳用戶:xauthu

  • 上下文無關(guān)文法(Context-Free Grammar, CFG)是一個(gè)4元組G=(V, T, S, P)

    上下文無關(guān)文法(Context-Free Grammar, CFG)是一個(gè)4元組G=(V, T, S, P),其中,V和T是不相交的有限集,S∈V,P是一組有限的產(chǎn)生式規(guī)則集,形如A→α,其中A∈V,且α∈(V∪T)*。V的元素稱為非終結(jié)符,T的元素稱為終結(jié)符,S是一個(gè)特殊的非終結(jié)符,稱為文法開始符。 設(shè)G=(V, T, S, P)是一個(gè)CFG,則G產(chǎn)生的語言是所有可由G產(chǎn)生的字符串組成的集合,即L(G)={x∈T* | Sx}。一個(gè)語言L是上下文無關(guān)語言(Context-Free Language, CFL),當(dāng)且僅當(dāng)存在一個(gè)CFG G,使得L=L(G)。 *⇒ 例如,設(shè)文法G:S→AB A→aA|a B→bB|b 則L(G)={a^nb^m | n,m>=1} 其中非終結(jié)符都是大寫字母,開始符都是S,終結(jié)符都是小寫字母。

    標(biāo)簽: Context-Free Grammar CFG

    上傳時(shí)間: 2013-12-10

    上傳用戶:gaojiao1999

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標(biāo)簽: represented integers group items

    上傳時(shí)間: 2016-01-17

    上傳用戶:jeffery

  • (1) 、用下述兩條具體規(guī)則和規(guī)則形式實(shí)現(xiàn).設(shè)大寫字母表示魔王語言的詞匯 小寫字母表示人的語言詞匯 希臘字母表示可以用大寫字母或小寫字母代換的變量.魔王語言可含人的詞匯. (2) 、B→tAdA A

    (1) 、用下述兩條具體規(guī)則和規(guī)則形式實(shí)現(xiàn).設(shè)大寫字母表示魔王語言的詞匯 小寫字母表示人的語言詞匯 希臘字母表示可以用大寫字母或小寫字母代換的變量.魔王語言可含人的詞匯. (2) 、B→tAdA A→sae (3) 、將魔王語言B(ehnxgz)B解釋成人的語言.每個(gè)字母對(duì)應(yīng)下列的語言.

    標(biāo)簽: 字母 tAdA 語言 詞匯

    上傳時(shí)間: 2013-12-30

    上傳用戶:ayfeixiao

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