The 87C576 includes two separate methods of programming theEPROM array, the traditional modified Quick-Pulse method, and anew On-Board Programming technique (OBP).Quick Pulse programming is a method using a number of devicepins in parallel (see Figure 1) and is the traditional way in which87C51 family members have been programmed. The Quick-Pulsemethod supports the following programming functions:– program USER EPROM– verify USER EPROM– program KEY EPROM– program security bits– verify security bits– read Signature bytesThe Quick-Pulse method is quite easily suited to standardprogramming equipment as evidenced by the numerous vendors of87C51 compatible programmers on the market today. Onedisadvantage is that this method is not well suited to programming inthe embedded application because of the large number of signallines that must be isolated from the application. In addition, parallelsignals from a programmer would need to be cabled to theapplication’s circuit board, or the application circuit board wouldneed to have logic built-in to perform the programming functions.These requirements have generally made in-circuit programmingusing the modified Quick Pulse method impractical in almost all87C51 family applications.
A new blind adaptive multiuser detection scheme based on a hybrid of Kalman filter and
subspace estimation is proposed. It is shown that the detector can be expressed as an anchored
signal in the signal subspace and the coefficients can be estimated by the Kalman filter using only
the Signature waveform and the timing of the desired user.
Problem Statement
You are given a string input. You are to find the longest substring of input such that the reversal of the substring is also a substring of input. In case of a tie, return the string that occurs earliest in input.
Definition
Class: ReverseSubstring
Method: findReversed
Parameters: string
Returns: string
Method Signature: string findReversed(string input)
(be sure your method is public)
Notes
The substring and its reversal may overlap partially or completely.
The entire original string is itself a valid substring (see example 4).
Constraints
input will contain between 1 and 50 characters, inclusive.
Each character of input will be an uppercase letter ( A - Z ).
Examples
0)
"XBCDEFYWFEDCBZ"
Returns: "BCDEF"
We see that the reverse of BCDEF is FEDCB, which appears later in the string.
1)
SHA-1(Secure Hash Algorithm)是美國國家標準局(National Institute of Standard and Technology NIST)為了配合數位簽章演算法(Digital Signature Algorithm DSA)的使用所發布的聯邦資訊處理標準-FIPS PUB 180-1(Federal Information Processing Standard Publication 180-1),而SHA-1 則是SHA-1 (FIPS180)的改良版,現今與MD5 皆廣被使用拿來做密碼驗證功能.其設計的方法是根據MD4,來對輸入的資料訊息(Message)產生出一個160 位元的訊息摘要(Digest) ,對於資料安全性提供了有效的保障.
if an application works with restricted low level system calls, it must obtain a Microsoft Mobile2Market privileged Signature. To get a privileged Signature, logo certification is now a requirement, not an option! This article shows how to abstract some of the most common issues a developer will encounter when creating a native code application that must be logo certified for each platform. windowsmobile5.0以上版本logo注冊例子，可以加入自己的工程文件中。
C++ 標準程序庫提供一組通用類別（classes）和接口（interfaces），可大幅擴充 C++ 核心語言。由于程序庫本身并不容易，為了完整運用其組件并從其強大的威力中獲得幫助，你需要一份完善的資源，而非一份僅僅陳列類和函數的普通文檔?！禩he C++ Standard Library》不僅對每一個程序庫組件提供范圍廣泛的說明，也對繁雜的感念提供清楚明亮的解釋，并描述高效運用這些組件時需要的實際編程細節，提出一個又一個的范例程序。這本包含最新資料的完整書籍，反映出被 ANSI/ISO C++ 語言標準規格書納入的 C++ 標準程序庫的結構。更明確地說，本書將焦點放在標準模板庫（Standard Template Library）身上，檢驗其中的容器（containers）、迭代器（iterators）、仿函數（functors）和算法（algorithms）。你還可以找到特殊容器、字符串（strings）、數值類別、國際化議題、IOStream。每一個組件都有深刻的呈現，包括其介紹、設計、運用實例、細部解說、陷阱、意想不到的危險，以及相關類別和函數的確切標記（Signature）和定義。一份見解深刻的基礎概念介紹和一個程序庫綜合鳥瞰，會對新手帶來快速的提升。
RSA ( Rivest Shamir Adleman )is crypthograph system that used to give a secret information and digital Signature . Its security based on Integer Factorization Problem (IFP). RSA uses an asymetric key. RSA was created by Rivest, Shamir, and Adleman in 1977. Every user have a pair of key, public key and private key. Public key (e) . You may choose any number for e with these requirements, 1< e <Æ (n), where Æ (n)= (p-1) (q-1) ( p and q are first-rate), gcd (e,Æ (n))=1 (gcd= greatest common divisor). Private key (d). d=(1/e) mod(Æ (n)) Encyption (C) . C=Mª mod(n), a = e (public key), n=pq Descryption (D) . D=C° mod(n), o = d (private key
