SDELab 解隨機微分方程的一個Matlab工具包 A package for Solving stochastic differential equations in MATLAB
標簽： differential stochastic equations package
上傳時間： 2013-12-19
上傳用戶：er1219
譜域法求解電磁場擴散方程的Fortran程序 A working example of Solving the electromagnetic diffusion equation using a spectral method
標簽： electromagnetic diffusion equation Fortran
上傳時間： 2014-01-10
上傳用戶：璇珠官人
The Source Code of Solving the Sudoku Game.
標簽： Solving Source Sudoku Code
上傳時間： 2014-12-20
上傳用戶：wanqunsheng
Algorithms Data Structures and Problem Solving with C++.pdf。。。提供給需要的共學下載
標簽： Algorithms Structures Problem Solving
上傳時間： 2014-11-04
上傳用戶：diets
aiNet application is a very powerful and a very simple tool for Solving the problems which are usually solved with artificial neural networks (ANN). All possible tests we had run proved that the results obtained with aiNet are at least as good as the results obtained with some other ANNs. Let us state some of aiNet抯 features. (c) aiNet 1995-1997
標簽： very application powerful problems
上傳時間： 2014-01-16
上傳用戶：wang5829
經典數據結構外國教材Data Abstraction & Problem Solving with C++.的源代碼
標簽： Abstraction Problem Solving Data
上傳時間： 2016-07-28
上傳用戶：youlongjian0
MATLAB潮流和最佳潮流計算程序 MATPOWER - Matlab routines for Solving power flow problems.
標簽： MATPOWER routines problems Solving
上傳時間： 2014-01-18
上傳用戶：zhanditian
Swarm intelligence is an innovative computational way to Solving hard problems. This discipline is inspired by the behavior of social insects such as fish schools and bird flocks and colonies of ants, termites, bees and wasps. In general, this is done by mimicking the behavior of the biological creatures within their swarms and colonies.
標簽： computational intelligence innovative discipline
上傳時間： 2014-01-14
上傳用戶：小儒尼尼奧
For Solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
標簽： Limit following Solving problem
上傳時間： 2014-01-12
上傳用戶：362279997
A program for Solving equations using Newton s Method.Just need to modify the data in the main function. If there is any bugs, please contact chenxiang@cad.zju.edu.cn
標簽： equations the program Solving
上傳時間： 2016-11-03
上傳用戶：xwd2010
