c語言版的多項式曲線擬合。 用最小二乘法進行曲線擬合. 用p－1 次多項式進行擬合，p<= 10 x,y 的第0個域x[0],y[0],沒有用，有效數據從x[1],y[1] 開始 nNodeNum,有效數據節點的個數。 b,為輸出的多項式系數，b[i] 為b[i-1]次項。b[0],沒有用。 b,有10個元素ok。
上傳時間： 2014-01-12
上傳用戶：變形金剛
Wavelets have widely been used in many signal and image processing applications. In this paper, a new serial-parallel architecture for wavelet-based image compression is introduced. It is based on a 4-tap wavelet transform, which is realised using some FIFO memory modules implementing a pixel-level pipeline architecture to compress and decompress images. The real filter calculation over 4 · 4 window blocks is done using a tree of carry save adders to ensure the high speed processing required for many applications. The details of implementing both compressor and decompressor sub-systems are given. The primarily analysis reveals that the proposed architecture, implemented using current VLSI technologies, can process a video stream in real time.
標簽： applications processing Wavelets widely
上傳時間： 2014-01-22
上傳用戶：hongmo
crc任意位生成多項式 任意位運算 自適應算法 循環冗余校驗碼(CRC，Cyclic Redundancy Code)是采用多項式的 編碼方式，這種方法把要發送的數據看成是一個多項式的系數 ，數據為bn-1bn-2…b1b0 (其中為0或1)，則其對應的多項式為： bn-1Xn-1+bn-2Xn-2+…+b１X+b０ 例如：數據“10010101”可以寫為多項式 X７+X４+X２+1。 循環冗余校驗CRC 循環冗余校驗方法的原理如下： (1) 設要發送的數據對應的多項式為P(x)。 (2) 發送方和接收方約定一個生成多項式G(x)，設該生成多項式 的最高次冪為r。 (3) 在數據塊的末尾添加r個0，則其相對應的多項式為M(x)=XrP(x) 。(左移r位) (4) 用M(x)除以G(x)，獲得商Q(x)和余式R(x)，則 M(x)=Q(x) ×G(x)+R(x)。 (5) 令T(x)=M(x)+R(x)，采用模2運算，T(x)所對應的數據是在原數 據塊的末尾加上余式所對應的數據得到的。 (6) 發送T(x)所對應的數據。 (7) 設接收端接收到的數據對應的多項式為T’(x)，將T’(x)除以G(x) ，若余式為0，則認為沒有錯誤，否則認為有錯。
上傳時間： 2014-11-28
上傳用戶：宋桃子
硬件設計指南(PDF格式)，主要包括：Low Voltage Interfaces；Grounding in Mixed Signal Systems；Digital Isolation Techniques； Power Supply Noise Reduction and Filtering； Dealing with High Speed Logic
上傳時間： 2015-08-31
上傳用戶：阿四AIR
Absolute Database 5.12 src. Absolute Database lets you forget the Borland Database Engine (BDE). This BDE replacement is the compact, high-speed, robust and easy-to-use database engine. With Absolute Database you will not need special installation and configuration, it compiles right into your EXE. Make your application faster and smaller with Absolute Database BDE alternative!
標簽： Database Absolute Borland forget
上傳時間： 2013-12-19
上傳用戶：海陸空653
crc任意位生成多項式 任意位運算 自適應算法 循環冗余校驗碼(CRC，Cyclic Redundancy Code)是采用多項式的 編碼方式，這種方法把要發送的數據看成是一個多項式的系數 ，數據為bn-1bn-2…b1b0 (其中為0或1)，則其對應的多項式為： bn-1Xn-1+bn-2Xn-2+…+b１X+b０ 例如：數據“10010101”可以寫為多項式 X７+X４+X２+1。 循環冗余校驗CRC 循環冗余校驗方法的原理如下： (1) 設要發送的數據對應的多項式為P(x)。 (2) 發送方和接收方約定一個生成多項式G(x)，設該生成多項式 的最高次冪為r。 (3) 在數據塊的末尾添加r個0，則其相對應的多項式為M(x)=XrP(x) 。(左移r位) (4) 用M(x)除以G(x)，獲得商Q(x)和余式R(x)，則 M(x)=Q(x) ×G(x)+R(x)。 (5) 令T(x)=M(x)+R(x)，采用模2運算，T(x)所對應的數據是在原數 據塊的末尾加上余式所對應的數據得到的。 (6) 發送T(x)所對應的數據。 (7) 設接收端接收到的數據對應的多項式為T’(x)，將T’(x)除以G(x) ，若余式為0，則認為沒有錯誤，否則認為有錯
上傳時間： 2014-01-16
上傳用戶：hphh
Jitter is extremely important in systems using PLL-based clock drivers. The effects of jitter range from not having any effect on system operation to rendering the system completely non-functional. This application note provides the reader with a clear understanding of jitter in high-speed systems. It introduces the reader to various kinds of jitter in high-speed systems, their causes and their effects, and methods of reducing jitter. This application note will concentrate on jitter in PLL-based frequency synthesizers.
標簽： extremely PLL-based important drivers
上傳時間： 2014-11-25
上傳用戶：asddsd
bulk endpoint endless source/sink firmware. EP2OUT will always accept a bulk OUT EP4OUT will always accept a bulk OUT EP6IN will always return a 512 byte packet. The packet contains an incrementing byte starting at 0x02. Since EP6 always returns a 512 byte packet, this endpoint should never be accessed except with a high-speed host controller. EP8IN will continuously return the packet most recently written to EP4OUT
標簽： bulk will endpoint firmware
上傳時間： 2016-01-14
上傳用戶：sk5201314
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
The PCI Local bus concept was developed to break the PC data I/O bottleneck and clearly opens the door to increasing system speed and expansion capabilities. The PCI Local bus moves high speed peripherals from the I/O bus and places them closer to the system’s processor bus, providing faster data transfers between the processor and peripherals. The PCI Local bus also addresses the industry’s need for a bus standard which is not directly dependent on the speed, size and type of system processor. It represents the first microprocessor independent bus offering performance more than adequate for the most demanding applications such as full-motion video.
標簽： bottleneck developed the concept
上傳時間： 2014-12-03
上傳用戶：ikemada
