5 ledblink -- 跑馬燈程序
該項(xiàng)目在SDT2.51下編譯調(diào)試。最簡(jiǎn)單的demo程序，運(yùn)行后3個(gè)發(fā)光二極管輪流點(diǎn)亮。
6 timerint -- 定時(shí)器中斷demo程序
該項(xiàng)目在SDT2.51下編譯調(diào)試。將子目錄timerint拷貝到c:\ 下。
該demo程序的主程序是while空循環(huán)，定時(shí)器中斷服務(wù)程序每500ms將3個(gè)LED反相。
在57600超級(jí)終端里也可以看到中斷發(fā)生時(shí)的信息。
7 uart -- 串口測(cè)試程序
該項(xiàng)目在SDT2.51下編譯調(diào)試。運(yùn)行后在57600的超級(jí)終端里等待PC鍵盤的輸入，當(dāng)按下 a 或 b 或 c 按鍵時(shí)，超級(jí)終端里將顯示 You Pressed a ,You Pressed b ,You Pressed c .
數(shù)字運(yùn)算，判斷一個(gè)數(shù)是否接近素?cái)?shù)
A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value.
Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not.
Input
Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone.
Output
For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise.
Sample Input
10 111
2 110
10 123
6 1000
8 2314
0
Sample Output
yes
yes
no
yes
no
