北京大學ACM比賽題目 In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of two odd prime numbers. For example: 8 = 3 + 5. Both 3 and 5 are odd prime numbers. 20 = 3 + 17 = 7 + 13. 42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23. Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.) Anyway, your task is now to verify Goldbach s conjecture for all even numbers less than a million.
標簽： mathematician Christian Goldbach Leonhard
上傳時間： 2016-04-22
上傳用戶：wangchong
北京大學ACM比賽題目 Consider an infinite full binary search tree (see the figure below), the numbers in the nodes are 1, 2, 3, .... In a subtree whose root node is X, we can get the minimum number in this subtree by repeating going down the left node until the last level, and we can also find the maximum number by going down the right node. Now you are given some queries as "What are the minimum and maximum numbers in the subtree whose root node is X?" Please try to find answers for there queries.
標簽： the Consider infinite numbers
上傳時間： 2013-12-16
上傳用戶：日光微瀾
北京大學ACM比賽題目 Write a program to read four lines of upper case (i.e., all CAPITAL LETTERS) text input (no more than 72 characters per line) from the input file and print a vertical histogram that shows how many times each letter (but not blanks, digits, or punctuation) appears in the all-upper-case input. Format your output exactly as shown.
標簽： CAPITAL LETTERS program Write
上傳時間： 2014-01-17
上傳用戶：410805624
用蠻力法解決的Acm icpc試題（求矩陣每一列列和的最小值）。
上傳時間： 2016-04-22
上傳用戶：bruce
北大ACM在線做題網站的部分題目答案。代碼為c++原碼。
上傳時間： 2013-12-27
上傳用戶：z1191176801
北大acm平臺正版源代碼acm2749
上傳時間： 2016-04-29
上傳用戶：yzy6007
ACM題解 歷年試題，經典題目，還有算法 前人經驗等
上傳時間： 2014-01-19
上傳用戶：invtnewer
這個一道ACM競賽中的復雜模擬程序。按照國際象棋的規則，程序從check_in中讀入雙方落子的步驟 通過程序模擬該盤棋過程，并最后判斷輸贏。將結果仿真check_out中。
上傳時間： 2016-05-02
上傳用戶：hakim
stl跟 acm的關系， 相當的好啊。。啊
上傳時間： 2016-05-05
上傳用戶：sdq_123
Interface for Microsoft Audio Compression Manager. - Delphi Source The ACM uses existing driver interface hooks to override the default mapping algorithm for waveform audio devices. This allows the ACM to intercept device-open calls. After a call has been intercepted, the ACM can perform a variety of tasks to process the audio data, such as inserting an external compressor or decompressor into the sequence.
標簽： Compression Interface Microsoft existing
上傳時間： 2013-12-13
上傳用戶：541657925
