private double PointToAngle(Point AOrigin, Point APoint) { if (APoint.X == AOrigin.X) if (APoint.Y > AOrigin.Y) return Math.PI * 0.5f else return Math.PI * 1.5f else if (APoint.Y == AOrigin.Y) if (APoint.X > AOrigin.X) return 0 else return Math.PI else {
標簽： AOrigin APoint Point PointToAngle
上傳時間： 2013-12-18
上傳用戶：rocketrevenge
This utility has two views: (a) one view that will show you the entire PnP enumeration tree of device objects, including relationships among objects and all the device s reported PnP characteristics, and (b) a second view that shows you the device objects created, sorted by driver name. There is nothing like this utility available anywhere else.
標簽： enumeration utility entire devic
上傳時間： 2013-12-17
上傳用戶：zjf3110
function [U,center,result,w,obj_fcn]= fenlei(data) [data_n,in_n] = size(data) m= 2 ％ Exponent for U max_iter = 100 ％ Max. iteration min_impro =1e-5 ％ Min. improvement c=3 [center, U, obj_fcn] = fcm(data, c) for i=1:max_iter if F(U)>0.98 break else w_new=eye(in_n,in_n) center1=sum(center)/c a=center1(1)./center1 deta=center-center1(ones(c,1),:) w=sqrt(sum(deta.^2)).*a for j=1:in_n w_new(j,j)=w(j) end data1=data*w_new [center, U, obj_fcn] = fcm(data1, c) center=center./w(ones(c,1),:) obj_fcn=obj_fcn/sum(w.^2) end end display(i) result=zeros(1,data_n) U_=max(U) for i=1:data_n for j=1:c if U(j,i)==U_(i) result(i)=j continue end end end
標簽： data function Exponent obj_fcn
上傳時間： 2013-12-18
上傳用戶：ynzfm
void insert_sort(int *a,int n) { if(n==1) return insert_sort(a,n-1) int temp=a[n-1] for(int i=n-2 i>=0 i--) { if(temp<a[i]) a[i+1]=a[i] else break } a[i+1]=temp }
標簽： insert_sort int return void
上傳時間： 2014-01-22
上傳用戶：banyou
Instead of finding the longest common subsequence, let us try to determine the length of the LCS. Then tracking back to find the LCS. Consider a1a2…am and b1b2…bn. Case 1: am=bn. The LCS must contain am, we have to find the LCS of a1a2…am-1 and b1b2…bn-1. Case 2: am≠bn. Wehave to find the LCS of a1a2…am-1 and b1b2…bn, and a1a2…am and b b b b1b2…bn-1 Let A = a1 a2 … am and B = b1 b2 … bn Let Li j denote the length of the longest i,g g common subsequence of a1 a2 … ai and b1 b2 … bj. Li,j = Li-1,j-1 + 1 if ai=bj max{ L L } a≠b i-1,j, i,j-1 if ai≠j L0,0 = L0,j = Li,0 = 0 for 1≤i≤m, 1≤j≤n.
標簽： the subsequence determine Instead
上傳時間： 2013-12-17
上傳用戶：evil
//獲得當前的模式 oldmode = vga_getcurrentmode[] //初始化 vga_init[] //判斷是否支持該模式 if[vga_hasmode[mode]] vga_setmode[mode] else { printf["No such mode\n"] exit[1] } //取得信息 width = vga_getxdim[] height = vga_getydim[] colors = vga_getcolors[] //繪圖 for[i=0 i<colors i++]{ vga_setcolor[i] vga_drawline[0, i, width-1, i] }
標簽： vga_getcurrentmode vga_init oldmode vga_ha
上傳時間： 2014-12-19
上傳用戶：maizezhen
//獲得當前的模式 oldmode = vga_getcurrentmode[] //初始化 vga_init[] //判斷是否支持該模式 if[vga_hasmode[mode]] vga_setmode[mode] else { printf["No such mode\n"] exit[1] } //獲得當前的模式 mode = vga_getcurrentmode[] info = vga_getmodeinfo[mode]
標簽： vga_getcurrentmode vga_init oldmode vga_ha
上傳時間： 2017-03-24
上傳用戶：ecooo
Program Description: The program asks the user to choice from the menu an option A. Check to see if a number is prime. B. Count the number of vowels in a line. X. Exit the program.
標簽： Description the Program program
上傳時間： 2017-04-08
上傳用戶：磊子226
A Convex Hull is the smallest convex polygon that contains every point of the set S. A polygon P is convex if and only if, for any two points A and B inside the polygon, the line segment AB is inside P. One way to visualize a convex hull is to put a "rubber band" around all the points, and let it wrap as tight as it can. The resultant polygon is a convex hull.
上傳時間： 2013-12-23
上傳用戶：it男一枚
P3.20. Consider an analog signal xa (t) = sin (2πt), 0 ≤t≤ 1. It is sampled at Ts = 0.01, 0.05, and 0.1 sec intervals to obtain x(n). b) Reconstruct the analog signal ya (t) from the samples x(n) using the sinc interpolation (use ∆ t = 0.001) and determine the frequency in ya (t) from your plot. (Ignore the end effects.) C) Reconstruct the analog signal ya (t) from the samples x (n) using the cubic spline interpolation and determine the frequency in ya (t) from your plot. (Ignore the end effects.)
標簽： Consider sampled analog signal
上傳時間： 2017-07-12
上傳用戶：咔樂塢
