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karel-the-<b>Robot</b>-learns-java

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標(biāo)簽: represented integers group items

    上傳時(shí)間: 2016-01-17

    上傳用戶:jeffery

  • You may have heard the Latest Brief web service on CodeProject.com. It provides several methods for

    You may have heard the Latest Brief web service on CodeProject.com. It provides several methods for web client programs to retrieve information about CodeProject.com, such as the latest article updates, the latest comments, and the latest lounge posts, etc. Some very popular articles on the CodeProject site make use of this service. In this article, I am going to present a java client program that uses soap message to call the methods of this web service. My program is not a general java soap client, which means you cannot use it to call other web services directly. However, you can easily modify it for other web services. The program uses only basic Java, it does not depend on any other external class library.

    標(biāo)簽: CodeProject provides service methods

    上傳時(shí)間: 2014-01-25

    上傳用戶:baiom

  • 鈥?What Is a Thread? o The Thread Class o Simple Thread Examples 鈥?Problems with Multithreading

    鈥?What Is a Thread? o The Thread Class o Simple Thread Examples 鈥?Problems with Multithreading o What Goes Wrong? o Thread Names and Current Threads o Java s synchronized 鈥?Synchronizing Threads o Multiple Locks 鈥?The Dining Philosophers Problem o Deadlocks o A Solution to the Dining Philosophers Problem o Java s wait() and notify() o Dining Philosophers Example 鈥?Summary

    標(biāo)簽: Thread Multithreading Examples Problems

    上傳時(shí)間: 2017-03-02

    上傳用戶:kristycreasy

  • fft analysis

          Use the fast Fourier transform function fft to analyse following signal. Plot the original signal, and the magnitude of its spectrum linearly and logarithmically. Apply Hamming window to reduce the leakage.   .   The hamming window can be coded in Matlab as   for n=1:N hamming(n)=0.54+0.46*cos((2*n-N+1)*pi/N); end;   where N is the data length in the FFT.

    標(biāo)簽: matlab fft

    上傳時(shí)間: 2015-11-23

    上傳用戶:石灰?guī)r123

  • fft analysis

    Use fft to analyse signal by plotting the original signal and its spectrum.  

    標(biāo)簽: matlab fft

    上傳時(shí)間: 2015-11-23

    上傳用戶:石灰?guī)r123

  • 微電腦型數(shù)學(xué)演算式隔離傳送器

    特點(diǎn): 精確度0.1%滿刻度 可作各式數(shù)學(xué)演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT類比輸出功能 輸入與輸出絕緣耐壓2仟伏特/1分鐘(input/output/power) 寬范圍交直流兩用電源設(shè)計(jì) 尺寸小,穩(wěn)定性高

    標(biāo)簽: 微電腦 數(shù)學(xué)演算 隔離傳送器

    上傳時(shí)間: 2014-12-23

    上傳用戶:ydd3625

  • CMOS模擬開關(guān)工作原理

    開關(guān)在電路中起接通信號(hào)或斷開信號(hào)的作用。最常見的可控開關(guān)是繼電器,當(dāng)給驅(qū)動(dòng)繼電器的驅(qū)動(dòng)電路加高電平或低電平時(shí),繼電器就吸合或釋放,其觸點(diǎn)接通或斷開電路。CMOS模擬開關(guān)是一種可控開關(guān),它不象繼電器那樣可以用在大電流、高電壓場合,只適于處理幅度不超過其工作電壓、電流較小的模擬或數(shù)字信號(hào)。 一、常用CMOS模擬開關(guān)引腳功能和工作原理  1.四雙向模擬開關(guān)CD4066  CD4066 的引腳功能如圖1所示。每個(gè)封裝內(nèi)部有4個(gè)獨(dú)立的模擬開關(guān),每個(gè)模擬開關(guān)有輸入、輸出、控制三個(gè)端子,其中輸入端和輸出端可互換。當(dāng)控制端加高電平時(shí),開關(guān)導(dǎo)通;當(dāng)控制端加低電平時(shí)開關(guān)截止。模擬開關(guān)導(dǎo)通時(shí),導(dǎo)通電阻為幾十歐姆;模擬開關(guān)截止時(shí),呈現(xiàn)很高的阻抗,可以看成為開路。模擬開關(guān)可傳輸數(shù)字信號(hào)和模擬信號(hào),可傳輸?shù)哪M信號(hào)的上限頻率為40MHz。各開關(guān)間的串?dāng)_很小,典型值為-50dB。

    標(biāo)簽: CMOS 模擬開關(guān) 工作原理

    上傳時(shí)間: 2013-10-27

    上傳用戶:bibirnovis

  • 印刷電路板設(shè)計(jì)原則

    減小電磁干擾的印刷電路板設(shè)計(jì)原則 內(nèi) 容 摘要……1 1 背景…1 1.1 射頻源.1 1.2 表面貼裝芯片和通孔元器件.1 1.3 靜態(tài)引腳活動(dòng)引腳和輸入.1 1.4 基本回路……..2 1.4.1 回路和偶極子的對(duì)稱性3 1.5 差模和共模…..3 2 電路板布局…4 2.1 電源和地…….4 2.1.1 感抗……4 2.1.2 兩層板和四層板4 2.1.3 單層板和二層板設(shè)計(jì)中的微處理器地.4 2.1.4 信號(hào)返回地……5 2.1.5 模擬數(shù)字和高壓…….5 2.1.6 模擬電源引腳和模擬參考電壓.5 2.1.7 四層板中電源平面因該怎么做和不應(yīng)該怎么做…….5 2.2 兩層板中的電源分配.6 2.2.1 單點(diǎn)和多點(diǎn)分配.6 2.2.2 星型分配6 2.2.3 格柵化地.7 2.2.4 旁路和鐵氧體磁珠……9 2.2.5 使噪聲靠近磁珠……..10 2.3 電路板分區(qū)…11 2.4 信號(hào)線……...12 2.4.1 容性和感性串?dāng)_……...12 2.4.2 天線因素和長度規(guī)則...12 2.4.3 串聯(lián)終端傳輸線…..13 2.4.4 輸入阻抗匹配...13 2.5 電纜和接插件……...13 2.5.1 差模和共模噪聲……...14 2.5.2 串?dāng)_模型……..14 2.5.3 返回線路數(shù)目..14 2.5.4 對(duì)板外信號(hào)I/O的建議14 2.5.5 隔離噪聲和靜電放電ESD .14 2.6 其他布局問題……...14 2.6.1 汽車和用戶應(yīng)用帶鍵盤和顯示器的前端面板印刷電路板...15 2.6.2 易感性布局…...15 3 屏蔽..16 3.1 工作原理…...16 3.2 屏蔽接地…...16 3.3 電纜和屏蔽旁路………………..16 4 總結(jié)…………………………………………17 5 參考文獻(xiàn)………………………17  

    標(biāo)簽: 印刷電路板 設(shè)計(jì)原則

    上傳時(shí)間: 2013-10-24

    上傳用戶:18165383642

  • 傳輸線理論

    目錄  第一章           傳輸線理論 一 傳輸線原理 二 微帶傳輸線 三 微帶傳輸線之不連續(xù)分析 第二章           被動(dòng)組件之電感設(shè)計(jì)與分析 一 電感原理 二 電感結(jié)構(gòu)與分析 三 電感設(shè)計(jì)與模擬 電感分析與量測

    標(biāo)簽: 傳輸線

    上傳時(shí)間: 2013-12-12

    上傳用戶:浩子GG

  • 微電腦型數(shù)學(xué)演算式雙輸出隔離傳送器

    特點(diǎn)(FEATURES) 精確度0.1%滿刻度 (Accuracy 0.1%F.S.) 可作各式數(shù)學(xué)演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 類比輸出功能(16 bit DAC isolating analog output function) 輸入/輸出1/輸出2絕緣耐壓2仟伏特/1分鐘(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 寬范圍交直流兩用電源設(shè)計(jì)(Wide input range for auxiliary power) 尺寸小,穩(wěn)定性高(Dimension small and High stability)

    標(biāo)簽: 微電腦 數(shù)學(xué)演算 輸出 隔離傳送器

    上傳時(shí)間: 2013-11-24

    上傳用戶:541657925

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