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  • 武林DLL注入源碼 VB調(diào)用 Private Declare Function CallHotKey Lib "wulin.dll" (ByVal hWnd As Long, ByVal hotke

    武林DLL注入源碼 VB調(diào)用 Private Declare Function CallHotKey Lib "wulin.dll" (ByVal hWnd As Long, ByVal hotkey As Long) As Boolean Private Declare Function CallBase Lib "wulin.dll" (ByVal hWnd As Long, ByVal action As Long) As Boolean CallHotKey(窗體句柄,HotKey) HotKey ====0---------17 分別是0-----9 F1-----F8 CallBase(窗體句柄,Action) Action==0-------N 分別實(shí)現(xiàn)不同的功能 Action=0 選怪 函數(shù)反回值是 布爾值 ( 窗體句柄,Action 窗體句柄,HotKey 都為DWORD值)

    標(biāo)簽: ByVal CallHotKey Function Private

    上傳時間: 2013-11-25

    上傳用戶:maizezhen

  • 1 #define GPBCON (*(volatile unsigned long *)0x56000010) 2 #define GPBDAT (*(volatile unsigned long

    1 #define GPBCON (*(volatile unsigned long *)0x56000010) 2 #define GPBDAT (*(volatile unsigned long *)0x56000014) 3 #define GPFCON (*(volatile unsigned long *)0x56000050) 4 #define GPFDAT (*(volatile unsigned long *)0x56000054)

    標(biāo)簽: volatile unsigned define long

    上傳時間: 2013-12-27

    上傳用戶:BIBI

  • Traveling Salesman Problem (TSP) has been an interesting problem for a long time in classical optim

    Traveling Salesman Problem (TSP) has been an interesting problem for a long time in classical optimization techniques which are based on linear and nonlinear programming. TSP can be described as follows: Given a number of cities to visit and their distances from all other cities know, an optimal travel route has to be found so that each city is visited one and only once with the least possible distance traveled. This is a simple problem with handful of cities but becomes complicated as the number increases.

    標(biāo)簽: interesting Traveling classical Salesman

    上傳時間: 2016-02-06

    上傳用戶:rocwangdp

  • Just what is a regular expression, anyway? Take the tutorial to get the long answer. The short answ

    Just what is a regular expression, anyway? Take the tutorial to get the long answer. The short answer is that a regular expression is a compact way of describing complex patterns in texts. You can use them to search for patterns and, once found, to modify the patterns in complex ways. You can also use them to launch programmatic actions that depend on patterns. A tongue-in-cheek comment by programmers is worth thinking about: "Sometimes you have a programming problem and it seems like the best solution is to use regular expressions now you have two problems." Regular expressions are amazingly powerful and deeply expressive. That is the very reason writing them is just as error-prone as writing any other complex programming code. It is always better to solve a genuinely simple problem in a simple way when you go beyond simple, think about regular expressions. Tutorial: Using regular expressions

    標(biāo)簽: expression the tutorial regular

    上傳時間: 2013-12-19

    上傳用戶:sardinescn

  • 編程題(15_01.c) 結(jié)構(gòu) struct student { long num char name[20] int score struct student *

    編程題(15_01.c) 結(jié)構(gòu) struct student { long num char name[20] int score struct student *next } 鏈表練習(xí): (1).編寫函數(shù)struct student * creat(int n),創(chuàng)建一個按學(xué)號升序排列的新鏈表,每個鏈表中的結(jié)點(diǎn)中 的學(xué)號、成績由鍵盤輸入,一共n個節(jié)點(diǎn)。 (2).編寫函數(shù)void print(struct student *head),輸出鏈表,格式每行一個結(jié)點(diǎn),包括學(xué)號,姓名,分?jǐn)?shù)。 (3).編寫函數(shù)struct student * merge(struct student *a,struct student *b), 將已知的a,b兩個鏈表 按學(xué)號升序合并,若學(xué)號相同則保留成績高的結(jié)點(diǎn)。 (4).編寫函數(shù)struct student * del(struct student *a,struct student *b),從a鏈表中刪除b鏈表中有 相同學(xué)號的那些結(jié)點(diǎn)。 (5).編寫main函數(shù),調(diào)用函數(shù)creat建立2個鏈表a,b,用print輸出倆個鏈表;調(diào)用函數(shù)merge升序合并2個 鏈表,并輸出結(jié)果;調(diào)用函數(shù)del實(shí)現(xiàn)a-b,并輸出結(jié)果。 a: 20304,xxxx,75, 20311,yyyy,89 20303,zzzz,62 20307,aaaa,87 20320,bbbb,79 b: 20302,dddd,65 20301,cccc,99 20311,yyyy,87 20323,kkkk,88 20307,aaaa,92 20322,pppp,83

    標(biāo)簽: student struct score long

    上傳時間: 2016-04-13

    上傳用戶:zxc23456789

  • 堆棧的數(shù)據(jù)結(jié)構(gòu)和操作 ypedef struct{ HGLOBAL hMem //堆棧全局內(nèi)存句柄 POINT *lpMyStack //指向該句柄的指針 LONG ElementsNum /

    堆棧的數(shù)據(jù)結(jié)構(gòu)和操作 ypedef struct{ HGLOBAL hMem //堆棧全局內(nèi)存句柄 POINT *lpMyStack //指向該句柄的指針 LONG ElementsNum //堆棧的大小 LONG ptr //指向棧頂?shù)弥羔?/p>

    標(biāo)簽: ElementsNum lpMyStack HGLOBAL ypedef

    上傳時間: 2013-11-26

    上傳用戶:15736969615

  • //按柱面和磁道來讀取磁盤數(shù)據(jù),要求 Public Function ReadDisk(ByVal Cylinders As Long, ByVal Tracks As Long, db() As

    //按柱面和磁道來讀取磁盤數(shù)據(jù),要求 Public Function ReadDisk(ByVal Cylinders As Long, ByVal Tracks As Long, db() As Byte) As Boolean

    標(biāo)簽: ByVal Long Cylinders Function

    上傳時間: 2014-01-13

    上傳用戶:zxc23456789

  • 用AVR單片機(jī)設(shè)計的MP3播放器 功能: MP3 Player IDE ATA interface FAT 32 with long file name support USB

    用AVR單片機(jī)設(shè)計的MP3播放器 功能: MP3 Player IDE ATA interface FAT 32 with long file name support USB interface On board power supply (input from 7v to 20v DC) Bootloader firmware upgradeable via USB port Infrared bi-directional interface Remote Control Back light graphic LCD worked with only 2x AA batteries In sleep mode sink less than 1uA (2.5mA in active mode) 5 buttons for easy navigation Long range (more than 20 feets)

    標(biāo)簽: MP3 interface support Player

    上傳時間: 2016-07-02

    上傳用戶:fandeshun

  • C-package of "Long Short-Term Memory" for Protein classification

    C-package of "Long Short-Term Memory" for Protein classification

    標(biāo)簽: classification Short-Term C-package Protein

    上傳時間: 2014-01-24

    上傳用戶:www240697738

  • 編寫具有如下原型的函數(shù):int f(unsigned long x, int n, int& Lxn) 它負(fù)責(zé)將整數(shù)x的第n位(從左邊數(shù)第n位

    編寫具有如下原型的函數(shù):int f(unsigned long x, int n, int& Lxn) 它負(fù)責(zé)將整數(shù)x的第n位(從左邊數(shù)第n位,n>0)的數(shù)值放到引用Lxn之中(將作為結(jié)果返回到主調(diào)函數(shù)的對應(yīng)實(shí)參變量中),并將倒數(shù)第n位(從右邊數(shù)第n位,n>0)的數(shù)值作為函數(shù)結(jié)果返回去。并編制主函數(shù)對它進(jìn)行調(diào)用以驗(yàn)證其正確性。 例如,當(dāng)x=123456789,n=7時,執(zhí)行語句“Rxn=f(x, n, Lxn) ”將使返回的Lxn為7,并使Rxn變?yōu)?;而執(zhí)行語句“Rxn=f(12345, 6, Lxn) ”將使Lxn與Rxn都變?yōu)闉?(超出數(shù)的“長度”即總位數(shù)時返回0)。

    標(biāo)簽: int unsigned long Lxn

    上傳時間: 2017-01-02

    上傳用戶:s363994250

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