We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
segment,一個簡單的中文分詞程序，命令行如下： java -jar segmenter.jar [-b|-g|-8|-s|-t] inputfile.txt -b Big5, -g GB2312, -8 UTF-8, -s simp. chars, -t trad. chars Segmented text will be saved to inputfile.txt.seg
上傳時間： 2014-01-04
上傳用戶：ynzfm
垃圾文件清理： 垃圾文件清理: 垃圾文件清理 Clean Windows Programs: :rd_dir if " R:~-2,1 "=="\" set R=" R:~1,-2 " if not exist R goto :DD cd /d R for /f "delims=" a in ( dir/ad/b ) do rd /s /q " a" del /f /s /q * cdrd /s /q R :DD Clean Windows Programs: :rd_dir if " R:~-2,1 "=="\" set R=" R:~1,-2 " if not exist R goto :DD cd /d R for /f "delims=" a in ( dir/ad/b ) do rd /s /q " a" del /f /s /q * cdrd /s /q R :DD
標簽： Programs Windows rd_dir Clean
上傳時間： 2017-04-21
上傳用戶：lanhuaying
one of video tool Skype only in windows mobile5.0 more than running, but my task is to let it run Skype in WINCE only in windows mobile5.0 more than running, but my task is to let it run in WINCE . Leave no stone unturned when I can not get windows mobile, they thought would be needed for skype all library files to my WINCE, so perhaps will be able to run skype. 1. Used depend Show skype depends on which files. In fact, not many documents, I can remember only under the following: core.dllcommctr.dllaygeshell.dllhtmlview.dll In addition to htmlview.dll, the other documents in WINCE have (if your system does not, please IMAGE Canada on the corresponding module). Therefore, I find on the Internet htmlview.dll, the results really find
標簽： running windows mobile Skype
上傳時間： 2014-01-17
上傳用戶：miaochun888
將魔王的語言抽象為人類的語言：魔王語言由以下兩種規則由人的語言逐步抽象上去的：α-〉β1β2β3…βm ；θδ1δ2…-〉θδnθδn-1…θδ1 設大寫字母表示魔王的語言，小寫字母表示人的語言B-〉tAdA，A-〉sae，eg：B(ehnxgz)B解釋為tsaedsaeezegexenehetsaedsae對應的話是：“天上一只鵝地上一只鵝鵝追鵝趕鵝下鵝蛋鵝恨鵝天上一只鵝地上一只鵝”。(t-天d-地s-上a-一只e-鵝z-追g-趕x-下n-蛋h-恨)
上傳時間： 2013-12-19
上傳用戶：aix008
The many variants of the Unix operating system require use of a mode of thought that s significantly different from the one that s required by simpler operating systems. Think Unix introduces readers to important fundamental and intermediate Unix commands and, in the process, inculcates them in the Unix way of thinking. It s a worthy goal in a world with more Linux users than ever, and author Jon Lasser accomplishes it. He s both a capable writer and a knowledgeable user of Unix shell commands. Lasser uses bash under Red Hat Linux in most examples--which usually apply equally well to other Unix variants--and makes asides about other shells and environments, as needed.
標簽： significantly operating variants of
上傳時間： 2017-09-04
上傳用戶：qq521
|- PyQt5開發與實戰【里面是3個小的壓縮文件，內容和6G的一樣】 - 0 B|- IT學習交流QQ群674392033各種資源交流共享 此文件夾本來就是空的 - 0 B|- 【完整版】第二講PyQt5開發與實戰視頻教程-2-搭建PyQt5開發環境.zip - 14.00 MB|- PyQt5開發與實戰.zip - 6.02 GB
上傳時間： 2022-06-06
上傳用戶：
特點： 精確度0.1%滿刻度 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT類比輸出功能 輸入與輸出絕緣耐壓2仟伏特/1分鐘(input/output/power) 寬范圍交直流兩用電源設計 尺寸小,穩定性高
上傳時間： 2014-12-23
上傳用戶：ydd3625
/*--------- 8051內核特殊功能寄存器 -------------*/ sfr ACC = 0xE0; //累加器 sfr B = 0xF0; //B 寄存器 sfr PSW = 0xD0; //程序狀態字寄存器 sbit CY = PSW^7; //進位標志位 sbit AC = PSW^6; //輔助進位標志位 sbit F0 = PSW^5; //用戶標志位0 sbit RS1 = PSW^4; //工作寄存器組選擇控制位 sbit RS0 = PSW^3; //工作寄存器組選擇控制位 sbit OV = PSW^2; //溢出標志位 sbit F1 = PSW^1; //用戶標志位1 sbit P = PSW^0; //奇偶標志位 sfr SP = 0x81; //堆棧指針寄存器 sfr DPL = 0x82; //數據指針0低字節 sfr DPH = 0x83; //數據指針0高字節 /*------------ 系統管理特殊功能寄存器 -------------*/ sfr PCON = 0x87; //電源控制寄存器 sfr AUXR = 0x8E; //輔助寄存器 sfr AUXR1 = 0xA2; //輔助寄存器1 sfr WAKE_CLKO = 0x8F; //時鐘輸出和喚醒控制寄存器 sfr CLK_DIV = 0x97; //時鐘分頻控制寄存器 sfr BUS_SPEED = 0xA1; //總線速度控制寄存器 /*----------- 中斷控制特殊功能寄存器 --------------*/ sfr IE = 0xA8; //中斷允許寄存器 sbit EA = IE^7; //總中斷允許位 sbit ELVD = IE^6; //低電壓檢測中斷控制位 8051
上傳時間： 2013-10-30
上傳用戶：yxgi5
#include<iom16v.h> #include<macros.h> #define uint unsigned int #define uchar unsigned char uint a,b,c,d=0; void delay(c) { for for(a=0;a<c;a++) for(b=0;b<12;b++); }; uchar tab[]={ 0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90,
上傳時間： 2013-10-21
上傳用戶：13788529953
