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  • Spring in action,Spring in action

    Spring in action,Spring in action

    標(biāo)簽： Spring action in

    上傳時(shí)間： 2017-08-23

    上傳用戶：coeus

  • Kth Largest element in an array in time O(n) without sorting the entire array.

    Kth Largest element in an array in time O(n) without sorting the entire array.

    標(biāo)簽： array Largest element sorting

    上傳時(shí)間： 2014-01-08

    上傳用戶：woshini123456

  • function g=distance_classify(A,b) 距離判別法程序。 輸入已分類樣本A（元胞數(shù)組）

    function g=distance_classify(A,b) 距離判別法程序。 輸入已分類樣本A（元胞數(shù)組），輸入待分類樣本b 輸出待分類樣本b的類別g 注：一般還應(yīng)計(jì)算回代誤差yita 輸入已知分類樣本的總類別數(shù)n 每類作為元胞數(shù)組的一列

    標(biāo)簽： distance_classify function 判別 分類

    上傳時(shí)間： 2013-11-25

    上傳用戶：yyyyyyyyyy

  • b+樹源碼

    b+樹源碼，b+樹結(jié)構(gòu)，刪除，插入，等值搜索，範(fàn)圍搜索等功能

    標(biāo)簽：

    上傳時(shí)間： 2015-03-23

    上傳用戶：tianjinfan

  • 溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級(jí)!!\n") else if (a>=80) printf("73分=B等級(jí)!!\n") else if (a>=70) printf("73分=C等級(jí)!!\n") else if (a>=60) printf("73分=D等級(jí)!!\n") else if (a<60) printf("73分=E等級(jí)!!\n") } { if (b>=90) printf("b=A等級(jí)!!\n") else if (b>=80) printf("85分=B等級(jí)!!\n") else if (b>=70) printf("85分=C等級(jí)!!\n") else if (b>=60) printf("85分=D等級(jí)!!\n") else if (b<60) printf("85分=E等級(jí)!!\n") } { if (c>=90) printf("c=A等級(jí)!!\n") else if (c>=80) printf("66分=B等級(jí)!!\n") else if (c>=70) printf("66分=C等級(jí)!!\n") else if (c>=60) printf("66分=D等級(jí)!!\n") else if (c<60) printf("66分=E等級(jí)!!\n") } system("pause") return 0 }

    標(biāo)簽： include stdlib stdio gt

    上傳時(shí)間： 2014-11-10

    上傳用戶：wpwpwlxwlx

  • 溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級(jí)!!\n") else if (a>=80) printf("73分=B等級(jí)!!\n") else if (a>=70) printf("73分=C等級(jí)!!\n") else if (a>=60) printf("73分=D等級(jí)!!\n") else if (a<60) printf("73分=E等級(jí)!!\n") } { if (b>=90) printf("b=A等級(jí)!!\n") else if (b>=80) printf("85分=B等級(jí)!!\n") else if (b>=70) printf("85分=C等級(jí)!!\n") else if (b>=60) printf("85分=D等級(jí)!!\n") else if (b<60) printf("85分=E等級(jí)!!\n") } { if (c>=90) printf("c=A等級(jí)!!\n") else if (c>=80) printf("66分=B等級(jí)!!\n") else if (c>=70) printf("66分=C等級(jí)!!\n") else if (c>=60) printf("66分=D等級(jí)!!\n") else if (c<60) printf("66分=E等級(jí)!!\n") } system("pause") return 0 }

    標(biāo)簽： include stdlib stdio gt

    上傳時(shí)間： 2013-12-12

    上傳用戶：亞亞娟娟123

  • Wi-Fi pollution, or an excessive number of access points in the area, especially on the same or neig

    Wi-Fi pollution, or an excessive number of access points in the area, especially on the same or neighboring channel, can prevent access and interfere with the use of other access points by others, caused by overlapping channels in the 802.11g/b spectrum

    標(biāo)簽： especially pollution excessive the

    上傳時(shí)間： 2017-07-29

    上傳用戶：我們的船長(zhǎng)

  • The Kannel Open Source WAP and SMS gateway works as both an SMS gateway, for implementing keyword b

    The Kannel Open Source WAP and SMS gateway works as both an SMS gateway, for implementing keyword based services via GSM text messages, and a WAP gateway, via UDP. The SMS part is fairly mature, the WAP part is early in its development. In this release, the GET request for WML pages and WMLScript files via HTTP works, including compilation for WML and WMLScript to binary forms. Only the data call bearer (UDP) is supported, not SMS.

    標(biāo)簽： gateway implementing SMS keyword

    上傳時(shí)間： 2014-01-11

    上傳用戶：2525775

  • 數(shù)字運(yùn)算

    數(shù)字運(yùn)算，判斷一個(gè)數(shù)是否接近素?cái)?shù) A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    標(biāo)簽： 數(shù)字 運(yùn)算

    上傳時(shí)間： 2015-05-21

    上傳用戶：daguda

  • /* * EULER S ALGORITHM 5.1 * * TO APPROXIMATE THE SOLUTION OF THE INITIAL VALUE PROBLEM: * Y = F

    /* * EULER S ALGORITHM 5.1 * * TO APPROXIMATE THE SOLUTION OF THE INITIAL VALUE PROBLEM: * Y = F(T,Y), A<=T<=B, Y(A) = ALPHA, * AT N+1 EQUALLY SPACED POINTS IN THE INTERVAL [A,B]. * * INPUT: ENDPOINTS A,B INITIAL CONDITION ALPHA INTEGER N. * * OUTPUT: APPROXIMATION W TO Y AT THE (N+1) VALUES OF T. */

    標(biāo)簽： APPROXIMATE ALGORITHM THE SOLUTION

    上傳時(shí)間： 2015-08-20

    上傳用戶：zhangliming420

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