# include<stdio.h>
# include<math.h>
# define N 3
main(){
float NF2(float *x,float *y);
float A[N][N]={{10,-1,-2},{-1,10,-2},{-1,-1,5}};
float b[N]={7.2,8.3,4.2},sum=0;
float x[N]= {0,0,0},y[N]={0},x0[N]={};
int i,j,n=0;
for(i=0;i<N;i++)
{
x[i]=x0[i];
}
for(n=0;;n++){
//計算下一個值
for(i=0;i<N;i++){
sum=0;
for(j=0;j<N;j++){
if(j!=i){
sum=sum+A[i][j]*x[j];
}
}
y[i]=(1/A[i][i])*(b[i]-sum);
//sum=0;
}
//判斷誤差大小
if(NF2(x,y)>0.01){
for(i=0;i<N;i++){
x[i]=y[i];
}
}
else
break;
}
printf("經過%d次雅可比迭代解出方程組的解：\n",n+1);
for(i=0;i<N;i++){
printf("%f ",y[i]);
}
}
//求兩個向量差的二范數函數
float NF2(float *x,float *y){
int i;
float z,sum1=0;
for(i=0;i<N;i++){
sum1=sum1+pow(y[i]-x[i],2);
}
z=sqrt(sum1);
return z;
}
標簽：
C語言
編寫
迭代
上傳時間：
2019-10-13
上傳用戶：大萌萌撒
include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
uint temp,aa,wang,qian,bai,shi,ge;
sbit dula=P2^6;
sbit wela=P2^7;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
void display( uint wang,uint qian,uint bai,uint shi,uint ge);
void delay(uint z);
void init();
void main()
{
init();//初始化子程序
while(1)
{
if(aa==20)
{
aa=0;
temp++;
if(temp==99999)
{
temp=0;
}
wang=temp/10000;
qian=(temp-wang*10000)/1000;
bai=(temp-wang*10000-qian*1000)/100;
shi=(temp-wang*10000-qian*1000-bai*100)/10;
ge=temp%10;
}
display(wang,qian, bai,shi,ge);
}
}
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void display(uint wang,uint qian,uint bai,uint shi,uint ge)
{
dula=1;
P0=table[wang];
dula=0;
P0=0xff;
wela=1;
P0=0xfe;
wela=0;
delay(1);
dula=1;
P0=table[qian];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delay(1);
dula=1;
P0=table[bai];
dula=0;
P0=0xff;
wela=1;
P0=0xfb;
wela=0;
delay(1);
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xf7;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
}
void init()
{
wela=0;
dula=0;
temp=0;
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}
void timer0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
aa++;
}
include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
uint temp,aa,wang,qian,bai,shi,ge;
sbit dula=P2^6;
sbit wela=P2^7;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
void display( uint wang,uint qian,uint bai,uint shi,uint ge);
void delay(uint z);
void init();
void main()
{
init();//初始化子程序
while(1)
{
if(aa==20)
{
aa=0;
temp++;
if(temp==99999)
{
temp=0;
}
wang=temp/10000;
qian=(temp-wang*10000)/1000;
bai=(temp-wang*10000-qian*1000)/100;
shi=(temp-wang*10000-qian*1000-bai*100)/10;
ge=temp%10;
}
display(wang,qian, bai,shi,ge);
}
}
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void display(uint wang,uint qian,uint bai,uint shi,uint ge)
{
dula=1;
P0=table[wang];
dula=0;
P0=0xff;
wela=1;
P0=0xfe;
wela=0;
delay(1);
dula=1;
P0=table[qian];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delay(1);
dula=1;
P0=table[bai];
dula=0;
P0=0xff;
wela=1;
P0=0xfb;
wela=0;
delay(1);
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xf7;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
}
void init()
{
wela=0;
dula=0;
temp=0;
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}
void timer0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
aa++;
}
include<reg52.h>
#define uint unsigned int
#define uchar unsigned char
uint temp,aa,wang,qian,bai,shi,ge;
sbit dula=P2^6;
sbit wela=P2^7;
uchar code table[]={
0x3f,0x06,0x5b,0x4f,
0x66,0x6d,0x7d,0x07,
0x7f,0x6f,0x77,0x7c,
0x39,0x5e,0x79,0x71};
void display( uint wang,uint qian,uint bai,uint shi,uint ge);
void delay(uint z);
void init();
void main()
{
init();//初始化子程序
while(1)
{
if(aa==20)
{
aa=0;
temp++;
if(temp==99999)
{
temp=0;
}
wang=temp/10000;
qian=(temp-wang*10000)/1000;
bai=(temp-wang*10000-qian*1000)/100;
shi=(temp-wang*10000-qian*1000-bai*100)/10;
ge=temp%10;
}
display(wang,qian, bai,shi,ge);
}
}
void delay(uint z)
{
uint x,y;
for(x=z;x>0;x--)
for(y=110;y>0;y--);
}
void display(uint wang,uint qian,uint bai,uint shi,uint ge)
{
dula=1;
P0=table[wang];
dula=0;
P0=0xff;
wela=1;
P0=0xfe;
wela=0;
delay(1);
dula=1;
P0=table[qian];
dula=0;
P0=0xff;
wela=1;
P0=0xfd;
wela=0;
delay(1);
dula=1;
P0=table[bai];
dula=0;
P0=0xff;
wela=1;
P0=0xfb;
wela=0;
delay(1);
dula=1;
P0=table[shi];
dula=0;
P0=0xff;
wela=1;
P0=0xf7;
wela=0;
delay(1);
dula=1;
P0=table[ge];
dula=0;
P0=0xff;
wela=1;
P0=0xef;
wela=0;
delay(1);
}
void init()
{
wela=0;
dula=0;
temp=0;
TMOD=0x01;
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
EA=1;
ET0=1;
TR0=1;
}
void timer0() interrupt 1
{
TH0=(65536-50000)/256;
TL0=(65536-50000)%256;
aa++;
}
標簽：
矩陣式鍵盤
上傳時間：
2021-12-18
上傳用戶：2590813506
本源代碼是基于STM32F4xx硬件平臺設計的貪吃蛇小游戲，主要難點在：隨機點產生、貪吃蛇轉向、貪吃蛇貪吃點；本部分主要接收產生隨機點，產生隨機點需要注意兩個方面：1、隨機點在有效的范圍內；2、貪吃點與貪吃蛇不重合。產生隨機點主要有兩個函數，分別如下：//隨機數產生任務void rng_chansheng(void *p_arg){OS_ERR err;while(1){OSSemPend(&RNG_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);zou.x = RNG_Get_RandomRange(0,50)*8 + 40;zou.y = RNG_Get_RandomRange(0,50)*8 + 260;lcd_fangkuan(zou.x,zou.y,zou.x+SHE_FAANGKUAN_SIZE,zou.y+SHE_FAANGKUAN_SIZE);OSTimeDlyHMSM(0,0,0,500,OS_OPT_TIME_HMSM_STRICT,&err); //延時500ms}}//往下方向畫一個實心的正方形，代表貪食蛇的一段void lcd_fangkuan(u16 x1,u16 y1,u16 x2 ,u16 y2){u16 i,j;u16 xx,yy;if(((x2 - x1) != SHE_FAANGKUAN_SIZE)||((y2 - y1) != SHE_FAANGKUAN_SIZE))return ;if(x1 > x2) {xx = x1;x1 = x2;x2 = xx;}if(y1 > y2){yy = y1;y1 = y2;y2 = yy;}if((y1 < 260)|| (y2 > 660)||(x1 < 40)||(x2 > 448)){game_yun_error = 1;LCD_ShowString(150,300,500,24,24,"GAME OVER!!");return ;}for(i=x1; i<x2; i++){for(j=y1; j<y2; j++){LCD_DrawPoint(i,j);}}}
標簽：
stm32
ucosiii
貪吃蛇游戲
上傳時間：
2022-08-10
上傳用戶：
