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  • 應(yīng)用JBuilder環(huán)境開(kāi)發(fā)

    應(yīng)用JBuilder環(huán)境開(kāi)發(fā),輸入一個(gè)正整數(shù)n,輸出1~n的組成的全排列

    標(biāo)簽: JBuilder 環(huán)境

    上傳時(shí)間: 2016-12-23

    上傳用戶:exxxds

  • 求 S=a+aa+aaa+…+aaaa…a 之值

    求 S=a+aa+aaa+…+aaaa…a 之值,其中a是一個(gè)數(shù)字。例如:2+22+222+2222+22222(此時(shí)n=5), n由鍵盤(pán)輸入。

    標(biāo)簽: aaaa aaa aa

    上傳時(shí)間: 2013-12-18

    上傳用戶:aeiouetla

  • 實(shí)驗(yàn)內(nèi)容: 編制一程序

    實(shí)驗(yàn)內(nèi)容: 編制一程序,要求接收從鍵盤(pán)輸入的一個(gè)班的學(xué)生成績(jī),并存放于50字節(jié)的GRADE數(shù)組中,其中GRADE+N保存學(xué)號(hào)N+1的學(xué)生成績(jī)。然后根據(jù)GRADE中的學(xué)生成績(jī),把學(xué)生名次填入50字節(jié)的RANK數(shù)組中,其中RANK+N的內(nèi)容是學(xué)號(hào)為N+1學(xué)生的名次。再按學(xué)號(hào)把學(xué)生順序把學(xué)生名次顯示出來(lái)。 實(shí)驗(yàn)要求:1.必須畫(huà)流程圖。2.本程序要求要有多重循環(huán)和子程序,其中 成績(jī)輸入、計(jì)算學(xué)生名次、顯示學(xué)生名次都分別用子程序,也可用宏處理。

    標(biāo)簽: 實(shí)驗(yàn) 編制 程序

    上傳時(shí)間: 2014-12-06

    上傳用戶:cjl42111

  • 編寫(xiě)程序

    編寫(xiě)程序,用遞歸算法求輸出0至n(1<=n&&n>=9)的所有路徑。

    標(biāo)簽: 編寫(xiě) 程序

    上傳時(shí)間: 2017-01-27

    上傳用戶:gonuiln

  • 響鈴

    響鈴,如果輸入為N則響鈴N次,否則不會(huì)響鈴

    標(biāo)簽:

    上傳時(shí)間: 2014-01-22

    上傳用戶:宋桃子

  • Input : A set S of planar points Output : A convex hull for S Step 1: If S contains no more than f

    Input : A set S of planar points Output : A convex hull for S Step 1: If S contains no more than five points, use exhaustive searching to find the convex hull and return. Step 2: Find a median line perpendicular to the X-axis which divides S into SL and SR SL lies to the left of SR . Step 3: Recursively construct convex hulls for SL and SR. Denote these convex hulls by Hull(SL) and Hull(SR) respectively. Step 4: Apply the merging procedure to merge Hull(SL) and Hull(SR) together to form a convex hull. Time complexity: T(n) = 2T(n/2) + O(n) = O(n log n)

    標(biāo)簽: contains Output convex planar

    上傳時(shí)間: 2017-02-19

    上傳用戶:wyc199288

  • The Bit Array structure provides a compacted arrays of Booleans, with one bit for each Boolean value

    The Bit Array structure provides a compacted arrays of Booleans, with one bit for each Boolean value. A 0 [1] bit corresponds to the Boolean value false [true], respectively. We can look at a stream of bytes as a stream of bits each byte contains 8 bits, so any n bytes hold n*8 bits. And the operation to manipulate this stream or bits array is so easy, jut read or change the bits state or make any Boolean operation on the whole bits array, like 鈥楢ND鈥? 鈥極R鈥? or 鈥榅OR鈥?

    標(biāo)簽: structure compacted Booleans provides

    上傳時(shí)間: 2014-01-15

    上傳用戶:壞天使kk

  • 為了開(kāi)發(fā)出適用于各種無(wú)線通信網(wǎng)絡(luò)的應(yīng)用和業(yè)務(wù)

    為了開(kāi)發(fā)出適用于各種無(wú)線通信網(wǎng)絡(luò)的應(yīng)用和業(yè)務(wù),人們通過(guò)不斷的努力,制定了一個(gè)業(yè)界的技術(shù)標(biāo)準(zhǔn)和規(guī)范,這就是無(wú)線應(yīng)用協(xié)議 [ WAP ]。無(wú)線應(yīng)用環(huán)境(Wireless ApplicationE n v i r o n m e n t,WA E)是WAP協(xié)議的一部分,它定義了各種無(wú)線終端,諸如移動(dòng)電話、尋呼機(jī)和個(gè)人數(shù)字助理(P D A)上使用的應(yīng)用結(jié)構(gòu)。

    標(biāo)簽: 無(wú)線通信網(wǎng)絡(luò)

    上傳時(shí)間: 2017-03-13

    上傳用戶:BIBI

  • Measuring Frequency Content in Signals I this section we will study some non parametric methods fo

    Measuring Frequency Content in Signals I this section we will study some non parametric methods for spectrum estimation of a stochastic process. These methods are described in the literature. All methods are based on the Periodogram which is defined for a sequence x[n] with length N according to

    標(biāo)簽: parametric Measuring Frequency Content

    上傳時(shí)間: 2017-03-20

    上傳用戶:秦莞爾w

  • //建立頂級(jí)窗口 toplevel = XtVaAppInitialize[&app, "DrawArea", NULL, 0, &argc, argv, NULL, NULL]

    //建立頂級(jí)窗口 toplevel = XtVaAppInitialize[&app, "DrawArea", NULL, 0, &argc, argv, NULL, NULL] //建立drawarea n = 0 XtSetArg[args[n], XmNwidth, 500 ] n++ XtSetArg[args[n], XmNheight, 500 ] n++ drawarea = XmCreateDrawingArea[toplevel, "drawarea", args, n] XtManageChild[drawarea] //建立繪圖所用的GC prepare[]

    標(biāo)簽: NULL XtVaAppInitialize toplevel DrawArea

    上傳時(shí)間: 2013-12-29

    上傳用戶:a6697238

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