#include <malloc.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #define NULL 0 #define MaxSize 30 typedef struct athletestruct /*運動員*/ { char name[20]; int score; /*分數*/ int range; /**/ int item; /*項目*/ }ATH; typedef struct schoolstruct /*學校*/ { int count; /*編號*/ int serial; /**/ int menscore; /*男選手分數*/ int womenscore; /*女選手分數*/ int totalscore; /*總分*/ ATH athlete[MaxSize]; /**/ struct schoolstruct *next; }SCH; int nsc,msp,wsp; int ntsp; int i,j; int overgame; int serial,range; int n; SCH *head,*pfirst,*psecond; int *phead=NULL,*pafirst=NULL,*pasecond=NULL; void create(); void input () { char answer; head = (SCH *)malloc(sizeof(SCH)); /**/ head->next = NULL; pfirst = head; answer = 'y'; while ( answer == 'y' ) { Is_Game_DoMain: printf("\nGET Top 5 when odd\nGET Top 3 when even"); printf("\n輸入運動項目序號 (x<=%d):",ntsp); scanf("%d",pafirst); overgame = *pafirst; if ( pafirst != phead ) { for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ ) { if ( overgame == *pasecond ) { printf("\n這個項目已經存在請選擇其他的數字\n"); goto Is_Game_DoMain; } } } pafirst = pafirst + 1; if ( overgame > ntsp ) { printf("\n項目不存在"); printf("\n請重新輸入"); goto Is_Game_DoMain; } switch ( overgame%2 ) { case 0: n = 3;break; case 1: n = 5;break; } for ( i = 1 ; i <= n ; i++ ) { Is_Serial_DoMain: printf("\n輸入序號 of the NO.%d (0<x<=%d): ",i,nsc); scanf("%d",&serial); if ( serial > nsc ) { printf("\n超過學校數目,請重新輸入"); goto Is_Serial_DoMain; } if ( head->next == NULL ) { create(); } psecond = head->next ; while ( psecond != NULL ) { if ( psecond->serial == serial ) { pfirst = psecond; pfirst->count = pfirst->count + 1; goto Store_Data; } else { psecond = psecond->next; } } create(); Store_Data: pfirst->athlete[pfirst->count].item = overgame; pfirst->athlete[pfirst->count].range = i; pfirst->serial = serial; printf("Input name:) : "); scanf("%s",pfirst->athlete[pfirst->count].name); } printf("\n繼續輸入運動項目(y&n)？"); answer = getchar(); printf("\n"); } } void calculate() /**/ { pfirst = head->next; while ( pfirst->next != NULL ) { for (i=1;i<=pfirst->count;i++) { if ( pfirst->athlete[i].item % 2 == 0 ) { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 5;break; case 2:pfirst->athlete[i].score = 3;break; case 3:pfirst->athlete[i].score = 2;break; } } else { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 7;break; case 2:pfirst->athlete[i].score = 5;break; case 3:pfirst->athlete[i].score = 3;break; case 4:pfirst->athlete[i].score = 2;break; case 5:pfirst->athlete[i].score = 1;break; } } if ( pfirst->athlete[i].item <=msp ) { pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score; } else { pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score; } } pfirst->totalscore = pfirst->menscore + pfirst->womenscore; pfirst = pfirst->next; } } void output() { pfirst = head->next; psecond = head->next; while ( pfirst->next != NULL ) { // clrscr(); printf("\n第%d號學校的結果成績:",pfirst->serial); printf("\n\n項目的數目\t學校的名字\t分數"); for (i=1;i<=ntsp;i++) { for (j=1;j<=pfirst->count;j++) { if ( pfirst->athlete[j].item == i ) { printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break; } } } printf("\n\n\n\t\t\t\t\t\t按任意建 進入下一頁"); getchar(); pfirst = pfirst->next; } // clrscr(); printf("\n運動會結果:\n\n學校編號\t男運動員成績\t女運動員成績\t總分"); pfirst = head->next; while ( pfirst->next != NULL ) { printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore); pfirst = pfirst->next; } printf("\n\n\n\t\t\t\t\t\t\t按任意建結束"); getchar(); } void create() { pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct)); pfirst->next = head->next ; head->next = pfirst ; pfirst->count = 1; pfirst->menscore = 0; pfirst->womenscore = 0; pfirst->totalscore = 0; } void Save() {FILE *fp; if((fp = fopen("school.dat","wb"))==NULL) {printf("can't open school.dat\n"); fclose(fp); return; } fwrite(pfirst,sizeof(SCH),10,fp); fclose(fp); printf("文件已經成功保存\n"); } void main() { system("cls"); printf("\n\t\t\t 運動會分數統計\n"); printf("輸入學校數目 (x>= 5):"); scanf("%d",&nsc); printf("輸入男選手的項目(x<=20):"); scanf("%d",&msp); printf("輸入女選手項目(<=20):"); scanf("%d",&wsp); ntsp = msp + wsp; phead = (int *)calloc(ntsp,sizeof(int)); pafirst = phead; pasecond = phead; input(); calculate(); output(); Save(); }
標簽： 源代碼
上傳時間： 2016-12-28
上傳用戶：150501
#include "string.h" #include "ctype.h" #include "stdio.h" search(char pd[]) {FILE *fp; int time=0,i=0,j=0,add[80],k=0,m; char *ch, str[900]; m=strlen(pd); if((fp=fopen("haha.txt","r"))==NULL) { printf("Cannot open this file\n"); exit(0); } for(;!feof(fp);i++) { str[i]=fgetc(fp); if(tolower(str[i])==tolower(pd[k])) {k++; if(k==m) if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp)))) { time++; add[j]=i-m+1; j++; k=0; } else k=0; } } if(time) { printf("The time is:%d\n",time); printf("The adders is:\n"); for(i=0;i<j;i++) printf("%5d",add[i]); if(i%5==0) printf("\n"); getch(); fclose(fp); } else printf("Sorry!Cannot find the word(^_^)"); } main() { char pd[10],choose='y'; int flag=1; while(flag) {printf("In put the word you want to seqarch:"); scanf("%s",pd); search(strlwr(pd)); printf("\nWould you want to continue?(Y/N):"); getchar(); scanf("%c",&choose); if((tolower(choose))=='n') flag=0; else flag=1; } printf("Thanks for your using!Bye-bye!\n"); getch(); }
標簽： 學生專用
上傳時間： 2016-12-29
上傳用戶：767483511
VB利用MSCOMM控件控制三菱PLC的X,Y.
上傳時間： 2016-12-31
上傳用戶：ykr1
EEMD算法MATlab代碼，代碼內容為定義一個EEMD函數，只需在同一文件夾寫代碼result =eemd(Y,Nstd,NE)即可
上傳時間： 2017-04-07
上傳用戶：mgy1125
gfgiuiv8hgiuvyiyi;yiy;y;ovyi;o
標簽： rtedi
上傳時間： 2017-08-12
上傳用戶：kfcnvp
function [Rs,Ps]=move_corr(X,Y,a) %%%--- this function is for moving correlation %%%--- X,Y is the imput data, a is the length of the moving window %%%--- Rs is the spwarman correlation coeffcient, Ps is the p_vaue
上傳時間： 2017-12-27
上傳用戶：Clocks
ukf軌跡跟蹤，提供詳細源碼，X,Y,航向角誤差對比圖
標簽： ukf軌跡跟蹤
上傳時間： 2018-05-08
上傳用戶：aihua_1203
#include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個:"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U，L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U，L的第r行，第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計算U得:"<<endl; U.Disp(); cout<<"計算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
標簽： 道理特分解法
上傳時間： 2018-05-20
上傳用戶：Aa123456789
#include<stdio.h> #include<windows.h> int xuanxiang; int studentcount; int banjihao[100]; int xueqihao[100][10]; char xm[100][100]; int xuehao[100][10]; int score[100][3]; int yuwen; int shuxue[000]; int yingyu[100]; int c[100]; int p; char x[1000][100]="",y[100][100]="";/*x學院 y專業 z班級*/ int z[100]; main() { void input(); void inputsc(); void alter(); void scbybannji(); printf("--------學生成績管理-----\n"); printf("請按相應數字鍵來實現相應功能\n"); printf("1.錄入學生信息 2.錄入學生成績 3.修改學生成績\n"); printf("4.查詢學生成績 5.不及格科目及名單 6.按班級輸出學生成績單\n"); printf("請輸入你要實現的功能所對應的數字:"); scanf("%d",&xuanxiang); system("cls"); getchar(); switch (xuanxiang) { case 1:input(); case 2:inputsc(); case 3:alter(); /*case 4:select score(); case 5:bujigekemujimingdan();*/ case 6:scbybanji; } } void input() { int i; printf("請輸入你的學院名稱:"); gets(x); printf("請輸入你的專業名稱:"); gets(y); printf("請輸入你的班級號:"); scanf("%d",&z); printf("請輸入你們一個班有幾個人:"); scanf("%d",&p); system("cls"); for(i=0;i<p;i++) { printf("請輸入第%d個學生的學號:",i+1); scanf("%d",xuehao[i]); getchar(); printf("請輸入第%d個學生的姓名:",i+1); gets(xm[i]); system("cls"); } printf("您已經錄入完畢您的班級所有學生的信息!\n"); printf("您的班級為%s%s%s\n",x,y,z); /*alter(p);*/ } void inputsc() { int i; for(i=0;i<p;i++) { printf("\n"); printf("--------------------------------------------------------------------------------\n\n"); printf("\t\t\t\t錄入學生的成績\n\n\n"); printf("--------------------------------------------------------------------------------\n\n"); printf("\t\t\t\t%s\n",xm[i]); printf("\n"); printf("\t\t\t\t數學:"); scanf("%d",&shuxue[i]); printf("\n"); getchar(); printf("\t\t\t\t英語:"); scanf("%d",&yingyu[i]); printf("\n"); getchar(); printf("\t\t\t\tc語言:"); scanf("%d",&c[i]); system("cls"); } } void alter() { int i;/*循環變量*/ int m[10000];/*要查詢的學號*/ int b;/*修改后的成績*/ char kemu[20]=""; printf("請輸入你要修改的學生的學號"); scanf("%d",&m); for (i=0;i<p;i++) { if (m==xuehao[i]) { printf("%s的數學成績為%d,英語成績為%d,c語言成績為%d,xm[i],shuxue[i],yingyu[i],c[i]"); printf("請輸入你想修改的科目");} } gets(kemu); getchar(); if (kemu=="數學"); { scanf("%d",&b); shuxue[i]=b;} if (kemu=="英語"); { scanf("%d",&b); yingyu[i]=b;} if (kemu=="c語言"); { scanf("%d",&b); c[i]=b; } printf("%s的數學成績為%d,英語成績為%d,c語言成績為%d,xm[i],shuxue[i],yingyu[i],c[i]"); } void scbybannji() { int i; char zyname[20]; int bjnumber; printf("請輸入你的專業名稱"); scanf("%s",&zyname); printf("請輸入你的班級號"); scanf("%d",&bjnumber); for (i=0;i<p;i++) { if (zyname==y[i]); if (bjnumber==z[i]); printf("專業名稱%s班級號%d數學成績%d英語成績%dc語言成績%d，y[i],z[i],shuxue[i],yingyu[i],c[i]"); } }
標簽： c語言
上傳時間： 2018-06-08
上傳用戶：2369043090
VK2C22是一款存儲器映射和多功能 LCD 控制 / 驅動芯片。該系列芯片顯示模式有 176 點 (44×4)VK2C22 軟件配置特性使 得它適用于多種 LCD 應用，包括 LCD 模塊和顯示子系統。VK2C22 通過雙線雙向 I2C 接口與大多數微處理器 / 微控制器進行通信。 VK2C2X系列為I2C介面、RAM mapping的LCD控制暨驅動IC，此系列以先進設計技術降低IC耗電、提升抗雜訊及ESD防護能力。全系列包含VK2C22、VK2C23、VK2C24等。VK2C22已成功獲得單相電表客戶的認可及采用，VK2C23及VK2C24適合于點數需求較大的三相電表的應用。
標簽： C22 22 16C VK2 HT 16 2C VK 兼容 電表
上傳時間： 2018-07-10
上傳用戶：szqxw1688
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