We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical) of any level of nesting to XML format and vice versa.
For example,
>> project.name = MyProject
>> project.id = 1234
>> project.param.a = 3.1415
>> project.param.b = 42
becomes with str=xml_format(project, off )
"<project>
<name>MyProject</name>
<id>1234</id>
<param>
<a>3.1415</a>
<b>42</b>
</param>
</project>"
On the other hand, if an XML string XStr is given, this can be converted easily to a MATLAB data type or structure V with the command V=xml_parse(XStr).
漢諾塔！！！
Simulate the movement of the Towers of Hanoi puzzle Bonus is possible for using animation
eg. if n = 2 A→B A→C B→C
if n = 3 A→C A→B C→B A→C B→A B→C A→C
基于事件驅動的串口通訊控件
消息幀數據格式:
1 0 A B X X
其中 10 為消息標識,
AB表示文本長度,L=A*100+B
XX為配位字符,任意
控制幀數據格式
0 1 A B M N
其中 01為控制標識,
AB為請求標識
MN為附加標識
11表示請求對方接收文件,M表示描述字串中文件名子串的長度
N表示描述字串中文件大小子串的長度
10通知對方放棄傳輸
00通知文件傳輸完畢
01請求對方發送數據, MN為10請求發送下一個
MN為00請求重發
數據幀數據格式
0 0 A B M N
其中 00 為數據標識,
AB表示數據長度,L=A*100+B
MN為校驗,M*100+N=A+B
