Linux 2.4.18 s3c2440 led driver
使用dev-C++撰寫，需要linux 2.4.18 kernel include，編譯完成後產生led module。
insmod main.o //安裝模組
mknod /dev/leds c 221 0
使用方法：
int main(int argc, char *argv[])
{
int testdev
//led test...
testdev = open("/dev/QuickMarkLed",O_RDWR)
ioctl(testdev, 2, 1) //ioctl(device, led number, open/close) open=1
ioctl(testdev, argv[1][0]- 0 , argv[2][0]- 0 ) //ioctl(device, led number, open/close) open=1
close(testdev)
return 0
}
標簽：
s3c2440
driver
Linux
dev-C
上傳時間：
2014-01-01
上傳用戶：qlpqlq
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽：
represented
integers
group
items
上傳時間：
2016-01-17
上傳用戶：jeffery
