#include<reg51.h> #define uchar unsigned char #define uint unsigned int uint i,j; sbit dula=P2^6; sbit wela=P2^7; uchar code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d, 0x7d,0x07,0x7f,0x6f,0x77,0x7c, 0x39,0x5e,0x79,0x71}; void main() { j=0; i=0; TMOD=0X01; TH0=(65536-50000)/256; TL0=(65536-50000)%6; EA=1; ET0=1; TR0=1; while(1); } void time0() interrupt 1 { TH0=(65536-50000)/256; TL0=(65536-50000)%6; i++; if(i==15) { P0=table[j]; dula=1; dula=0; P0=0XC0; wela=1; wela=0; j++; i=0; if(j==16) { j=0; } } }
標(biāo)簽: 用定時(shí)器以間隔500MS在6位數(shù)碼管上依次顯示0、1、 2、3….C、D、E、F,重復(fù)。
上傳時(shí)間: 2016-02-11
上傳用戶(hù):嬌縱Pamper
#include <malloc.h> #include <stdio.h> #include <stdlib.h> #include <string.h> #define NULL 0 #define MaxSize 30 typedef struct athletestruct /*運(yùn)動(dòng)員*/ { char name[20]; int score; /*分?jǐn)?shù)*/ int range; /**/ int item; /*項(xiàng)目*/ }ATH; typedef struct schoolstruct /*學(xué)校*/ { int count; /*編號(hào)*/ int serial; /**/ int menscore; /*男選手分?jǐn)?shù)*/ int womenscore; /*女選手分?jǐn)?shù)*/ int totalscore; /*總分*/ ATH athlete[MaxSize]; /**/ struct schoolstruct *next; }SCH; int nsc,msp,wsp; int ntsp; int i,j; int overgame; int serial,range; int n; SCH *head,*pfirst,*psecond; int *phead=NULL,*pafirst=NULL,*pasecond=NULL; void create(); void input () { char answer; head = (SCH *)malloc(sizeof(SCH)); /**/ head->next = NULL; pfirst = head; answer = 'y'; while ( answer == 'y' ) { Is_Game_DoMain: printf("\nGET Top 5 when odd\nGET Top 3 when even"); printf("\n輸入運(yùn)動(dòng)項(xiàng)目序號(hào) (x<=%d):",ntsp); scanf("%d",pafirst); overgame = *pafirst; if ( pafirst != phead ) { for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ ) { if ( overgame == *pasecond ) { printf("\n這個(gè)項(xiàng)目已經(jīng)存在請(qǐng)選擇其他的數(shù)字\n"); goto Is_Game_DoMain; } } } pafirst = pafirst + 1; if ( overgame > ntsp ) { printf("\n項(xiàng)目不存在"); printf("\n請(qǐng)重新輸入"); goto Is_Game_DoMain; } switch ( overgame%2 ) { case 0: n = 3;break; case 1: n = 5;break; } for ( i = 1 ; i <= n ; i++ ) { Is_Serial_DoMain: printf("\n輸入序號(hào) of the NO.%d (0<x<=%d): ",i,nsc); scanf("%d",&serial); if ( serial > nsc ) { printf("\n超過(guò)學(xué)校數(shù)目,請(qǐng)重新輸入"); goto Is_Serial_DoMain; } if ( head->next == NULL ) { create(); } psecond = head->next ; while ( psecond != NULL ) { if ( psecond->serial == serial ) { pfirst = psecond; pfirst->count = pfirst->count + 1; goto Store_Data; } else { psecond = psecond->next; } } create(); Store_Data: pfirst->athlete[pfirst->count].item = overgame; pfirst->athlete[pfirst->count].range = i; pfirst->serial = serial; printf("Input name:) : "); scanf("%s",pfirst->athlete[pfirst->count].name); } printf("\n繼續(xù)輸入運(yùn)動(dòng)項(xiàng)目(y&n)?"); answer = getchar(); printf("\n"); } } void calculate() /**/ { pfirst = head->next; while ( pfirst->next != NULL ) { for (i=1;i<=pfirst->count;i++) { if ( pfirst->athlete[i].item % 2 == 0 ) { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 5;break; case 2:pfirst->athlete[i].score = 3;break; case 3:pfirst->athlete[i].score = 2;break; } } else { switch (pfirst->athlete[i].range) { case 1:pfirst->athlete[i].score = 7;break; case 2:pfirst->athlete[i].score = 5;break; case 3:pfirst->athlete[i].score = 3;break; case 4:pfirst->athlete[i].score = 2;break; case 5:pfirst->athlete[i].score = 1;break; } } if ( pfirst->athlete[i].item <=msp ) { pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score; } else { pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score; } } pfirst->totalscore = pfirst->menscore + pfirst->womenscore; pfirst = pfirst->next; } } void output() { pfirst = head->next; psecond = head->next; while ( pfirst->next != NULL ) { // clrscr(); printf("\n第%d號(hào)學(xué)校的結(jié)果成績(jī):",pfirst->serial); printf("\n\n項(xiàng)目的數(shù)目\t學(xué)校的名字\t分?jǐn)?shù)"); for (i=1;i<=ntsp;i++) { for (j=1;j<=pfirst->count;j++) { if ( pfirst->athlete[j].item == i ) { printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break; } } } printf("\n\n\n\t\t\t\t\t\t按任意建 進(jìn)入下一頁(yè)"); getchar(); pfirst = pfirst->next; } // clrscr(); printf("\n運(yùn)動(dòng)會(huì)結(jié)果:\n\n學(xué)校編號(hào)\t男運(yùn)動(dòng)員成績(jī)\t女運(yùn)動(dòng)員成績(jī)\t總分"); pfirst = head->next; while ( pfirst->next != NULL ) { printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore); pfirst = pfirst->next; } printf("\n\n\n\t\t\t\t\t\t\t按任意建結(jié)束"); getchar(); } void create() { pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct)); pfirst->next = head->next ; head->next = pfirst ; pfirst->count = 1; pfirst->menscore = 0; pfirst->womenscore = 0; pfirst->totalscore = 0; } void Save() {FILE *fp; if((fp = fopen("school.dat","wb"))==NULL) {printf("can't open school.dat\n"); fclose(fp); return; } fwrite(pfirst,sizeof(SCH),10,fp); fclose(fp); printf("文件已經(jīng)成功保存\n"); } void main() { system("cls"); printf("\n\t\t\t 運(yùn)動(dòng)會(huì)分?jǐn)?shù)統(tǒng)計(jì)\n"); printf("輸入學(xué)校數(shù)目 (x>= 5):"); scanf("%d",&nsc); printf("輸入男選手的項(xiàng)目(x<=20):"); scanf("%d",&msp); printf("輸入女選手項(xiàng)目(<=20):"); scanf("%d",&wsp); ntsp = msp + wsp; phead = (int *)calloc(ntsp,sizeof(int)); pafirst = phead; pasecond = phead; input(); calculate(); output(); Save(); }
標(biāo)簽: 源代碼
上傳時(shí)間: 2016-12-28
上傳用戶(hù):150501
#include "string.h" #include "ctype.h" #include "stdio.h" search(char pd[]) {FILE *fp; int time=0,i=0,j=0,add[80],k=0,m; char *ch, str[900]; m=strlen(pd); if((fp=fopen("haha.txt","r"))==NULL) { printf("Cannot open this file\n"); exit(0); } for(;!feof(fp);i++) { str[i]=fgetc(fp); if(tolower(str[i])==tolower(pd[k])) {k++; if(k==m) if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp)))) { time++; add[j]=i-m+1; j++; k=0; } else k=0; } } if(time) { printf("The time is:%d\n",time); printf("The adders is:\n"); for(i=0;i
標(biāo)簽: 查詢(xún)學(xué)會(huì)少年宮
上傳時(shí)間: 2016-12-29
上傳用戶(hù):767483511
#include "string.h" #include "ctype.h" #include "stdio.h" search(char pd[]) {FILE *fp; int time=0,i=0,j=0,add[80],k=0,m; char *ch, str[900]; m=strlen(pd); if((fp=fopen("haha.txt","r"))==NULL) { printf("Cannot open this file\n"); exit(0); } for(;!feof(fp);i++) { str[i]=fgetc(fp); if(tolower(str[i])==tolower(pd[k])) {k++; if(k==m) if(!isalpha(i-m)&&!isalpha((str[i++]=fgetc(fp)))) { time++; add[j]=i-m+1; j++; k=0; } else k=0; } } if(time) { printf("The time is:%d\n",time); printf("The adders is:\n"); for(i=0;i<j;i++) printf("%5d",add[i]); if(i%5==0) printf("\n"); getch(); fclose(fp); } else printf("Sorry!Cannot find the word(^_^)"); } main() { char pd[10],choose='y'; int flag=1; while(flag) {printf("In put the word you want to seqarch:"); scanf("%s",pd); search(strlwr(pd)); printf("\nWould you want to continue?(Y/N):"); getchar(); scanf("%c",&choose); if((tolower(choose))=='n') flag=0; else flag=1; } printf("Thanks for your using!Bye-bye!\n"); getch(); }
標(biāo)簽: 學(xué)生專(zhuān)用
上傳時(shí)間: 2016-12-29
上傳用戶(hù):767483511
/*import java.util.Scanner; //主類(lèi) public class student122 { //主方法 public static void main(String[] args){ //定義7個(gè)元素的字符數(shù)組 String[] st = new String[7]; inputSt(st); //調(diào)用輸入方法 calculateSt(st); //調(diào)用計(jì)算方法 outputSt(st); //調(diào)用輸出方法 } //其他方法 //輸入方法 private static void inputSt(String st[]){ System.out.println("輸入學(xué)生的信息:"); System.out.println("學(xué)號(hào) 姓名 成績(jī)1,2,3"); //創(chuàng)建鍵盤(pán)輸入類(lèi) Scanner ss = new Scanner(System.in); for(int i=0; i<5; i++){ st[i] = ss.next(); //鍵盤(pán)輸入1個(gè)字符串 } } //計(jì)算方法 private static void calculateSt(String[] st){ int sum = 0; //總分賦初值 int ave = 0; //平均分賦初值 for(int i=2;i<5;i++) { /計(jì)總分,字符變換成整數(shù)后進(jìn)行計(jì)算 sum += Integer.parseInt(st[i]); } ave = sum/3; //計(jì)算平均分 //整數(shù)變換成字符后保存到數(shù)組里 st[5] = String.valueOf(sum); st[6] = String.valueOf(ave); } //輸出方法 private static void outputSt(String[] st){ System.out.print("學(xué)號(hào) 姓名 "); //不換行 System.out.print("成績(jī)1 成績(jī)2 成績(jī)3 "); System.out.println("總分 平均分");//換行 //輸出學(xué)生信息 for(int i=0; i<7; i++){ //按格式輸出,小于6個(gè)字符,補(bǔ)充空格 System.out.printf("%6s", st[i]); } System.out.println(); //輸出換行 } }*/ import java.util.Scanner; public class student122 { public static void main(String[] args) { // TODO 自動(dòng)生成的方法存根 String[][] st = new String[3][8]; inputSt(st); calculateSt(st); outputSt(st); } //輸入方法 private static void inputSt(String st[][]) { System.out.println("輸入學(xué)生信息:"); System.out.println("班級(jí) 學(xué)號(hào) 姓名 成績(jī):數(shù)學(xué) 物理 化學(xué)"); //創(chuàng)建鍵盤(pán)輸入類(lèi) Scanner ss = new Scanner(System.in); for(int j = 0; j < 3; j++) { for(int i = 0; i < 6; i++) { st[j][i] = ss.next(); } } } //輸出方法 private static void outputSt(String st[][]) { System.out.println("序號(hào) 班級(jí) 學(xué)號(hào) 姓名 成績(jī):數(shù)學(xué) 物理 化學(xué) 總分 平均分"); //輸出學(xué)生信息 for(int j = 0; j < 3; j++) { System.out.print(j+1 + ":"); for(int i = 0; i < 8; i++) { System.out.printf("%6s", st[j][i]); } System.out.println(); } } //計(jì)算方法 private static void calculateSt(String[][] st) { int sum1 = 0; int sum2 = 0; int sum3 = 0; int ave1 = 0; int ave2 = 0; int ave3 = 0; for(int i = 3; i < 6; i++) { sum1 += Integer.parseInt(st[0][i]); } ave1 = sum1/3; for(int i = 3; i < 6; i++) { sum2 += Integer.parseInt(st[1][i]); } ave2 = sum2/3; for(int i = 3; i < 6; i++) { sum3 += Integer.parseInt(st[2][i]); } ave3 = sum3/3; st[0][6] = String.valueOf(sum1); st[1][6] = String.valueOf(sum2); st[2][6] = String.valueOf(sum3); st[0][7] = String.valueOf(ave1); st[1][7] = String.valueOf(ave2); st[2][7] = String.valueOf(ave3); } }
標(biāo)簽: java 數(shù)據(jù)庫(kù)
上傳時(shí)間: 2017-03-17
上傳用戶(hù):simple
題目:古典問(wèn)題:有一對(duì)兔子,從出生后第3個(gè)月起每個(gè)月都生一對(duì)兔子,小兔子長(zhǎng)到第三個(gè)月后每個(gè)月又生一對(duì)兔子,假如兔子都不死,問(wèn)每個(gè)月的兔子總數(shù)為多少? //這是一個(gè)菲波拉契數(shù)列問(wèn)題 public class lianxi01 { public static void main(String[] args) { System.out.println("第1個(gè)月的兔子對(duì)數(shù): 1"); System.out.println("第2個(gè)月的兔子對(duì)數(shù): 1"); int f1 = 1, f2 = 1, f, M=24; for(int i=3; i<=M; i++) { f = f2; f2 = f1 + f2; f1 = f; System.out.println("第" + i +"個(gè)月的兔子對(duì)數(shù): "+f2); } } } 【程序2】 題目:判斷101-200之間有多少個(gè)素?cái)?shù),并輸出所有素?cái)?shù)。 程序分析:判斷素?cái)?shù)的方法:用一個(gè)數(shù)分別去除2到sqrt(這個(gè)數(shù)),如果能被整除, 則表明此數(shù)不是素?cái)?shù),反之是素?cái)?shù)。 public class lianxi02 { public static void main(String[] args) { int count = 0; for(int i=101; i<200; i+=2) { boolean b = false; for(int j=2; j<=Math.sqrt(i); j++) { if(i % j == 0) { b = false; break; } else { b = true; } } if(b == true) {count ++;System.out.println(i );} } System.out.println( "素?cái)?shù)個(gè)數(shù)是: " + count); } } 【程序3】 題目:打印出所有的 "水仙花數(shù) ",所謂 "水仙花數(shù) "是指一個(gè)三位數(shù),其各位數(shù)字立方和等于該數(shù)本身。例如:153是一個(gè) "水仙花數(shù) ",因?yàn)?53=1的三次方+5的三次方+3的三次方。 public class lianxi03 { public static void main(String[] args) { int b1, b2, b3;
上傳時(shí)間: 2017-12-24
上傳用戶(hù):Ariza
#include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構(gòu)中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請(qǐng)輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請(qǐng)輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個(gè):"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U,L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U,L的第r行,第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計(jì)算U得:"<<endl; U.Disp(); cout<<"計(jì)算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
標(biāo)簽: 道理特分解法
上傳時(shí)間: 2018-05-20
上傳用戶(hù):Aa123456789
function [alpha,N,U]=youxianchafen2(r1,r2,up,under,num,deta) %[alpha,N,U]=youxianchafen2(a,r1,r2,up,under,num,deta) %該函數(shù)用有限差分法求解有兩種介質(zhì)的正方形區(qū)域的二維拉普拉斯方程的數(shù)值解 %函數(shù)返回迭代因子、迭代次數(shù)以及迭代完成后所求區(qū)域內(nèi)網(wǎng)格節(jié)點(diǎn)處的值 %a為正方形求解區(qū)域的邊長(zhǎng) %r1,r2分別表示兩種介質(zhì)的電導(dǎo)率 %up,under分別為上下邊界值 %num表示將區(qū)域每邊的網(wǎng)格剖分個(gè)數(shù) %deta為迭代過(guò)程中所允許的相對(duì)誤差限 n=num+1; %每邊節(jié)點(diǎn)數(shù) U(n,n)=0; %節(jié)點(diǎn)處數(shù)值矩陣 N=0; %迭代次數(shù)初值 alpha=2/(1+sin(pi/num));%超松弛迭代因子 k=r1/r2; %兩介質(zhì)電導(dǎo)率之比 U(1,1:n)=up; %求解區(qū)域上邊界第一類(lèi)邊界條件 U(n,1:n)=under; %求解區(qū)域下邊界第一類(lèi)邊界條件 U(2:num,1)=0;U(2:num,n)=0; for i=2:num U(i,2:num)=up-(up-under)/num*(i-1);%采用線(xiàn)性賦值對(duì)上下邊界之間的節(jié)點(diǎn)賦迭代初值 end G=1; while G>0 %迭代條件:不滿(mǎn)足相對(duì)誤差限要求的節(jié)點(diǎn)數(shù)目G不為零 Un=U; %完成第n次迭代后所有節(jié)點(diǎn)處的值 G=0; %每完成一次迭代將不滿(mǎn)足相對(duì)誤差限要求的節(jié)點(diǎn)數(shù)目歸零 for j=1:n for i=2:num U1=U(i,j); %第n次迭代時(shí)網(wǎng)格節(jié)點(diǎn)處的值 if j==1 %第n+1次迭代左邊界第二類(lèi)邊界條件 U(i,j)=1/4*(2*U(i,j+1)+U(i-1,j)+U(i+1,j)); end if (j>1)&&(j U2=1/4*(U(i,j+1)+ U(i-1,j)+ U(i,j-1)+ U(i+1,j)); U(i,j)=U1+alpha*(U2-U1); %引入超松弛迭代因子后的網(wǎng)格節(jié)點(diǎn)處的值 end if i==n+1-j %第n+1次迭代兩介質(zhì)分界面(與網(wǎng)格對(duì)角線(xiàn)重合)第二類(lèi)邊界條件 U(i,j)=1/4*(2/(1+k)*(U(i,j+1)+U(i+1,j))+2*k/(1+k)*(U(i-1,j)+U(i,j-1))); end if j==n %第n+1次迭代右邊界第二類(lèi)邊界條件 U(i,n)=1/4*(2*U(i,j-1)+U(i-1,j)+U(i+1,j)); end end end N=N+1 %顯示迭代次數(shù) Un1=U; %完成第n+1次迭代后所有節(jié)點(diǎn)處的值 err=abs((Un1-Un)./Un1);%第n+1次迭代與第n次迭代所有節(jié)點(diǎn)值的相對(duì)誤差 err(1,1:n)=0; %上邊界節(jié)點(diǎn)相對(duì)誤差置零 err(n,1:n)=0; %下邊界節(jié)點(diǎn)相對(duì)誤差置零 G=sum(sum(err>deta))%顯示每次迭代后不滿(mǎn)足相對(duì)誤差限要求的節(jié)點(diǎn)數(shù)目G end
標(biāo)簽: 有限差分
上傳時(shí)間: 2018-07-13
上傳用戶(hù):Kemin
function y=lagr(x0,y0,x) %x0,y0為節(jié)點(diǎn) %x是插值點(diǎn) n=length(x0); m=length(x); for i=1:m z=x(i); s=0.0; for k=1:n p=1.0; for j=1:n if j~=k p=p*(z-x0(j))/(x0(k)-x0(j)); end end s=p*y0(k)+s; end y(i)=s; end
標(biāo)簽: lagr
上傳時(shí)間: 2020-06-09
上傳用戶(hù):shiyc2020
Cadence Allegro是一款專(zhuān)業(yè)的PCB設(shè)計(jì)軟件,是世界上最大的電子設(shè)計(jì)技術(shù)和配套服務(wù)的 EDA 供貨商之一,在EDA工具中屬于高端的PCB設(shè)計(jì)軟件,它的知名度在全球電子設(shè)計(jì)行業(yè)領(lǐng)域內(nèi)如雷貫耳,是電子行業(yè)創(chuàng)新的領(lǐng)導(dǎo)者。allegro主要用于PCB設(shè)計(jì)布線(xiàn),為當(dāng)前高速、高密度、多層的復(fù)雜 PCB 設(shè)計(jì)布線(xiàn)提供了最完美解決方案。allegro 功能包括原理圖輸入、生成、模擬數(shù)字/混合電路仿真,fpga設(shè)計(jì),pcb編輯和自動(dòng)布局布線(xiàn)mcm電路設(shè)計(jì)、高速pcb版圖的設(shè)計(jì)仿真等等。包括:* Concept HDL原理圖設(shè)計(jì)輸入工具,有for NT和for Unix的產(chǎn)品。* Check Plus HDL原理圖設(shè)計(jì)規(guī)則檢查工具。(NT & Unix)* SPECTRA Quest Engineer PCB版圖布局規(guī)劃工具(NT & Unix)* Allegro Expert專(zhuān)家級(jí)PCB版圖編輯工具 (NT & Unix)* SPECTRA Expert AutoRouter 專(zhuān)家級(jí)pcb自動(dòng)布線(xiàn)工具* SigNoise信噪分析工具* EMControl電磁兼容性檢查工具* Synplify FPGA / CPLD綜合工具* HDL Analyst HDL分析器* Advanced Package Designer先進(jìn)的MCM封裝設(shè)計(jì)工具allegro 特點(diǎn)1.系統(tǒng)軟件互聯(lián)服務(wù)平臺(tái)可以跨集成電路、封裝和PCB協(xié)同設(shè)計(jì)性能卓越互聯(lián)。2.應(yīng)用平臺(tái)的協(xié)同設(shè)計(jì)方式,技術(shù)工程師能夠 快速提升I/O油壓緩沖器中間和跨集成電路、封裝和PCB的系統(tǒng)軟件互連。3.該方式能防止硬件返修并減少硬件成本費(fèi)和減少設(shè)計(jì)周期時(shí)間。4.管束驅(qū)動(dòng)器的Allegro步驟包含高級(jí)作用用以設(shè)計(jì)捕獲、信號(hào)完整性和物理學(xué)完成。5.因?yàn)樗€獲得CadenceEncounter與Virtuoso服務(wù)平臺(tái)的適用。6.Allegro協(xié)同設(shè)計(jì)方式促使高效率的設(shè)計(jì)鏈協(xié)作變成實(shí)際。
標(biāo)簽: Allegro
上傳時(shí)間: 2022-06-20
上傳用戶(hù):canderile
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