-
本代碼為編碼開關代碼，編碼開關也就是數字音響中的
360度旋轉的數字音量以及顯示器上用的（單鍵飛梭開
關）等類似鼠標滾輪的手動計數輸入設備。
我使用的編碼開關為5個引腳的，其中2個引腳為按下
轉輪開關（也就相當于鼠標中鍵）。另外3個引腳用來
檢測旋轉方向以及旋轉步數的檢測端。引腳分別為a,b,c
b接地a，c分別接到P2.0和P2.1口并分別接兩個10K上拉
電阻，并且a，c需要分別對地接一個104的電容，否則
因為編碼開關的觸點抖動會引起輕微誤動作。本程序不
使用定時器，不占用中斷，不使用延時代碼，并對每個
細分步數進行判斷，避免一切誤動作，性能超級穩定。
我使用的編碼器是APLS的EC11B可以參照附件的時序圖
編碼器控制流水燈最能說明問題，下面是以一段流水
燈來演示。
標簽：
代碼
編碼開關
上傳時間：
2017-07-03
上傳用戶：gaojiao1999
-
【問題描述】
在一個N*N的點陣中，如N=4,你現在站在（1，1），出口在（4，4）。你可以通過上、下、左、右四種移動方法，在迷宮內行走，但是同一個位置不可以訪問兩次，亦不可以越界。表格最上面的一行加黑數字A[1..4]分別表示迷宮第I列中需要訪問并僅可以訪問的格子數。右邊一行加下劃線數字B[1..4]則表示迷宮第I行需要訪問并僅可以訪問的格子數。如圖中帶括號紅色數字就是一條符合條件的路線。
給定N，A[1..N] B[1..N]。輸出一條符合條件的路線，若無解，輸出NO ANSWER。（使用U，D，L，R分別表示上、下、左、右。）
2 2 1 2
（4，4） 1
（2，3） （3，3） （4，3） 3
（1，2） （2，2） 2
（1，1） 1
【輸入格式】
第一行是數m (n < 6 )。第二行有n個數，表示a[1]..a[n]。第三行有n個數，表示b[1]..b[n]。
【輸出格式】
僅有一行。若有解則輸出一條可行路線，否則輸出“NO ANSWER”。
標簽：
點陣
上傳時間：
2014-06-21
上傳用戶：llandlu
-
userial is an Free project building an USB to I2C/SPI/GPIO bridge, using the Atmel AT90USB647 chip. Hardware and Software are released under an Open Source licence. It supports the following interfaces:
* USB interface (serial emulation)
* JTAG
* I2C (TWI)
* SPI
* 8 General purpose digital I/O
* 4 Analog to Digital converters (currently no firmware support)
標簽：
USB
building
userial
project
上傳時間：
2013-12-25
上傳用戶：小鵬
-
A large body of computer-aided techniques has been developed in recent years to assist
in the process of modeling, analyzing, and designing communication systems . These
computer-aided techniques fall into two categories: formula-based approaches, where the
computer is used to evaluate complex formulas, and simulation-based approaches, where the
computer is used to simulate the waveforms or signals that flow through the system. The
second approach, which involves “waveform”-level simulation (and often incorporates
analytical techniques), is the subject of this book.
Since performance evaluation and trade off studies are the central issues in the analysis
and design of communication systems, we will focus on the use of simulation for evaluating
the performance of analog and digital communication systems with the emphasis on digitalcommunication systems.
標簽：
computer-aided
techniques
developed
assist
上傳時間：
2014-01-01
上傳用戶：541657925
-
實驗源代碼
//Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("請輸入矩陣第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可傳遞閉包關系矩陣是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元關系的可傳遞閉包\n"); void warshall(int,int); int k , n; printf("請輸入矩陣的行數 i: "); scanf("%d",&k);
四川大學實驗報告 printf("請輸入矩陣的列數 j: "); scanf("%d",&n); warshall(k,n); }
標簽：
warshall
離散
實驗
上傳時間：
2016-06-27
上傳用戶：梁雪文以
-
#include "iostream" using namespace std;
class Matrix
{
private:
double** A; //矩陣A
double *b; //向量b
public:
int size;
Matrix(int );
~Matrix();
friend double* Dooli(Matrix& );
void Input();
void Disp();
};
Matrix::Matrix(int x) {
size=x;
//為向量b分配空間并初始化為0
b=new double [x];
for(int j=0;j<x;j++)
b[j]=0;
//為向量A分配空間并初始化為0
A=new double* [x];
for(int i=0;i<x;i++)
A[i]=new double [x];
for(int m=0;m<x;m++)
for(int n=0;n<x;n++)
A[m][n]=0;
}
Matrix::~Matrix() {
cout<<"正在析構中~~~~"<<endl;
delete b;
for(int i=0;i<size;i++)
delete A[i];
delete A;
}
void Matrix::Disp()
{
for(int i=0;i<size;i++)
{
for(int j=0;j<size;j++)
cout<<A[i][j]<<" ";
cout<<endl;
}
}
void Matrix::Input()
{
cout<<"請輸入A:"<<endl;
for(int i=0;i<size;i++)
for(int j=0;j<size;j++){
cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl;
cin>>A[i][j];
}
cout<<"請輸入b:"<<endl;
for(int j=0;j<size;j++){
cout<<"第"<<j+1<<"個:"<<endl;
cin>>b[j];
}
}
double* Dooli(Matrix& A) {
double *Xn=new double [A.size];
Matrix L(A.size),U(A.size);
//分別求得U，L的第一行與第一列
for(int i=0;i<A.size;i++)
U.A[0][i]=A.A[0][i];
for(int j=1;j<A.size;j++)
L.A[j][0]=A.A[j][0]/U.A[0][0];
//分別求得U，L的第r行，第r列
double temp1=0,temp2=0;
for(int r=1;r<A.size;r++){
//U
for(int i=r;i<A.size;i++){
for(int k=0;k<r-1;k++)
temp1=temp1+L.A[r][k]*U.A[k][i];
U.A[r][i]=A.A[r][i]-temp1;
}
//L
for(int i=r+1;i<A.size;i++){
for(int k=0;k<r-1;k++)
temp2=temp2+L.A[i][k]*U.A[k][r];
L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r];
}
}
cout<<"計算U得:"<<endl;
U.Disp();
cout<<"計算L的:"<<endl;
L.Disp();
double *Y=new double [A.size];
Y[0]=A.b[0];
for(int i=1;i<A.size;i++ ){
double temp3=0;
for(int k=0;k<i-1;k++)
temp3=temp3+L.A[i][k]*Y[k];
Y[i]=A.b[i]-temp3;
}
Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1];
for(int i=A.size-1;i>=0;i--){
double temp4=0;
for(int k=i+1;k<A.size;k++)
temp4=temp4+U.A[i][k]*Xn[k];
Xn[i]=(Y[i]-temp4)/U.A[i][i];
}
return Xn;
}
int main()
{
Matrix B(4);
B.Input();
double *X;
X=Dooli(B);
cout<<"~~~~解得:"<<endl;
for(int i=0;i<B.size;i++)
cout<<"X["<<i<<"]:"<<X[i]<<" ";
cout<<endl<<"呵呵呵呵呵";
return 0;
}
標簽：
道理特分解法
上傳時間：
2018-05-20
上傳用戶：Aa123456789
-
16-, 14-, 12-Bit, Six-Channel, Simultaneous Sampling
ANALOG-TO-DIGITAL CONVERTERS
標簽：
8556i
8556
ads
上傳時間：
2018-06-07
上傳用戶：nj精靈
-
From the transition of analog to digital communication along with seamless mobility and
high computing power of small handheld devices, the wireless communications industry has
seen tremendous changes leading to the integration of several telecommunication networks,
devices and services over last 30 years. The rate of this progress and growth has increased
particularly in the past decade because people no longer use their devices and networks for
voice only, but demand bundle contents such as data download/streaming, HDTV, HD video ,
3D video conferencing with higher efficiency, seamless connectivity, intelligence, reliability
and better user experience. Although the challenges facing service providers and
telecommunication companies differ by product, region, market size, and their areas of
concentration but time to market, efficient utilization of their assets and revenue expansion,
have impacted significantly how to manage and conduct their business while maintaining
sufficient margin.
標簽：
Convergence
Networks
Beyond
4G
of
上傳時間：
2020-05-26
上傳用戶：shancjb
-
The continued reduction of integrated circuit feature sizes and
commensurate improvements in device performance are fueling the progress
to higher functionality and new application areas. For example, over the last
15 years, the performance of microprocessors has increased 1000 times.
Analog circuit performance has also improved, albeit at a slower pace. For
example, over the same period the speed/resolution figure-of-merit of
analog-to-digital converters improved by only a factor 10.
標簽：
Digitally
Assisted
Pipeline
ADCs
上傳時間：
2020-05-27
上傳用戶：shancjb
-
Mobile multimedia communication is increasingly in demand because of the basic need to communi-
cate at any time, anywhere, using any technology. In addition, to voice communication, people have a
desire to access a range of other services that comprise multimedia elements—text, image, animation,
high fidelity audio and video using mobile communication networks. To meet these demands, mobile
communication technologies has evolved from analog to digital, and the networks have passed through
a number of generations from first generation (1G) to fourth generation (4G).
標簽：
Communications
Multimedia
Concepts
Mobile
上傳時間：
2020-05-30
上傳用戶：shancjb
