光學(xué)設(shè)計(jì)軟件zemax源碼： This DLL models an nular aspheric surface as described in: "Annular surfaces in annular field systems" By Jose M. Sasian Opt. eng. 36 (12) P 3401-3401 December 1997 This surface is essentially an odd aspheric surface with an offset in the aspheric terms. The sag is given by: Z = (c*r*r) / (1+(1-((1+k)*c*c*r*r))^ 1/2 ) + a*(r-q)^2 + b*(r-q)^3 + c*(r-q)^4 + ... Note the terms a, b, c, ... have units of length to the -1, -2, -3, ... power.
標(biāo)簽： described aspheric surfaces Annular
上傳時(shí)間： 2014-01-08
上傳用戶(hù)：yyyyyyyyyy
THIS M-FILE USES THE TRANFER MATRIX METHOD TO EVALUATE THE COUPLED-MODE ％EQUATIONS. THE REFLECTION SPECTRUM OF THE GRATING AND THE TRANSMISSION ％SPECTRUM, DELAY AND DISPERSION OF THE FABRY-PEROT FILTER ARE SIMULATED
標(biāo)簽： THE COUPLED-MODE REFLECTION EQUATIONS
上傳時(shí)間： 2015-08-11
上傳用戶(hù)：CHINA526
Documentation and source code Copyright (C) 1985 by Mark E. Mallett permission is granted to distribute this document and the code indiscriminately. Please leave credits in place, and add your own as appropriate.
標(biāo)簽： E. Documentation permission Copyright
上傳時(shí)間： 2013-12-21
上傳用戶(hù)：wlcaption
MODE_Switch1Processing multi-interrupt request needs to set the priority of these interrupt requests. The IRQ flags of the 7 interrupt are controlled by the interrupt event occurring. But the IRQ flag set doesn t mean the system to execute the interrupt vector. The IRQ flags can be triggered by the events without interrupt enable. Just only any the event occurs and the IRQ will be logic "1".
標(biāo)簽： multi-interrupt MODE_Switch Processing interrupt
上傳時(shí)間： 2013-12-04
上傳用戶(hù)：zhichenglu
EXAMPLE SOURCE CODE FOR IMPLIB FILTER This filter accepts input through the standard input stream, convertsit and outputs it to the standard output am. The streams are linkedthrough pipes, such that the input stream is the output from the import librarian being invoked, and the output stream is connected to the message window of the IDE, ie.
標(biāo)簽： input standard EXAMPLE accepts
上傳時(shí)間： 2014-11-18
上傳用戶(hù)：siguazgb
EXAMPLE SOURCE CODE FOR TASM FILTER his filter accepts input through the standard input stream, converts it and outputs it to the standard output stream. The streams are linked through pipes, such that the input stream is the output from the assembler being invoked, and the output stream is connected to the message window of the IDE, ie.
標(biāo)簽： input standard EXAMPLE accepts
上傳時(shí)間： 2014-01-13
上傳用戶(hù)：小碼農(nóng)lz
Cracking the Code - Wireless Programming with J2ME This book is based on the unique concept of cracking the code and mastering the technology.The technologies covered are J2ME version 1.0.2 and the applications are also tested on version 1.0.3 Beta.
標(biāo)簽： Programming the Cracking Wireless
上傳時(shí)間： 2015-08-20
上傳用戶(hù)：fhzm5658
PCI-to-PCI Bridge Architecture Specification Revision 1.1 This specification establishes the requirements that a PCI-to-PCI bridge must meet to be compliant to this specification and the PCI Local Bus Specification. In addition, the requirements for optional extensions are specified. This specification does not describe the implementation details of any particular requirement or optional feature of a PCI-to-PCI bridge, nor is it a goal of this specification to describe any particular PCI-to-PCI bridge implementation. However, some recommendations are provided for some implementation-specific features that can be provided by a PCI-to-PCI bridge.
標(biāo)簽： Specification specification Architecture establishes
上傳時(shí)間： 2014-01-14
上傳用戶(hù)：caiiicc
ACM試題An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
標(biāo)簽： Description computers Problem binary
上傳時(shí)間： 2013-12-11
上傳用戶(hù)：libenshu01
Following is a repost of the public domain make that I posted to net.sources a couple of months ago. I have fixed a few bugs, and added some more features, and the resulting changes amounted to about as much text as the whole program (hence the repost).一個(gè)編譯器C代碼，詳見(jiàn)REDME。
標(biāo)簽： Following sources domain couple
上傳時(shí)間： 2015-09-01
上傳用戶(hù)：manlian
蟲(chóng)蟲(chóng)下載站版權(quán)所有 京ICP備2021023401號(hào)-1
