【問題描述】 在一個(gè)N*N的點(diǎn)陣中,如N=4,你現(xiàn)在站在(1,1),出口在(4,4)。你可以通過上、下、左、右四種移動方法,在迷宮內(nèi)行走,但是同一個(gè)位置不可以訪問兩次,亦不可以越界。表格最上面的一行加黑數(shù)字A[1..4]分別表示迷宮第I列中需要訪問并僅可以訪問的格子數(shù)。右邊一行加下劃線數(shù)字B[1..4]則表示迷宮第I行需要訪問并僅可以訪問的格子數(shù)。如圖中帶括號紅色數(shù)字就是一條符合條件的路線。 給定N,A[1..N] B[1..N]。輸出一條符合條件的路線,若無解,輸出NO ANSWER。(使用U,D,L,R分別表示上、下、左、右。) 2 2 1 2 (4,4) 1 (2,3) (3,3) (4,3) 3 (1,2) (2,2) 2 (1,1) 1 【輸入格式】 第一行是數(shù)m (n < 6 )。第二行有n個(gè)數(shù),表示a[1]..a[n]。第三行有n個(gè)數(shù),表示b[1]..b[n]。 【輸出格式】 僅有一行。若有解則輸出一條可行路線,否則輸出“NO ANSWER”。
標(biāo)簽: 點(diǎn)陣
上傳時(shí)間: 2014-06-21
上傳用戶:llandlu
實(shí)驗(yàn)源代碼 //Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("請輸入矩陣第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可傳遞閉包關(guān)系矩陣是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元關(guān)系的可傳遞閉包\n"); void warshall(int,int); int k , n; printf("請輸入矩陣的行數(shù) i: "); scanf("%d",&k); 四川大學(xué)實(shí)驗(yàn)報(bào)告 printf("請輸入矩陣的列數(shù) j: "); scanf("%d",&n); warshall(k,n); }
標(biāo)簽: warshall 離散 實(shí)驗(yàn)
上傳時(shí)間: 2016-06-27
上傳用戶:梁雪文以
#include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構(gòu)中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個(gè):"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U,L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U,L的第r行,第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計(jì)算U得:"<<endl; U.Disp(); cout<<"計(jì)算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
標(biāo)簽: 道理特分解法
上傳時(shí)間: 2018-05-20
上傳用戶:Aa123456789
n present power system, the engineers face variety of challenges in planning, construction and operation. In some of the problems, the engineers need to use managerial talents. In system design or upgrading the entire system into automatic control instead of slow response of human operator, the engineers need to exercise more technical knowledge and experience. It is principally the engi- neer’s ability to achieve the success in all respect and provide the reliable and uninterrupted service to the customers. This chapter covers some important areas of the traditional power system that helps engineers to overcome the challenges. It emphasizes the characteristics of the various components of a power system such as generation, transmission, distribution, protection and SCADA system. During normal operating conditions and disturbances, the acquired knowledge will pro- vide the engineers the ability to analyse the performance of the complex system and execute future improvement
上傳時(shí)間: 2020-06-07
上傳用戶:shancjb
The basic topic of this book is solving problems from system and control theory using convex optimization. We show that a wide variety of problems arising in system and control theory can be reduced to a handful of standard convex and quasiconvex optimization problems that involve matrix inequalities. For a few special cases there are “analytic solutions” to these problems, but our main point is that they can be solved numerically in all cases. These standard problems can be solved in polynomial- time (by, e.g., the ellipsoid algorithm of Shor, Nemirovskii, and Yudin), and so are tractable, at least in a theoretical sense. Recently developed interior-point methods for these standard problems have been found to be extremely efficient in practice. Therefore, we consider the original problems from system and control theory as solved.
標(biāo)簽: Linear_Matrix_Inequalities_in_Sys tem
上傳時(shí)間: 2020-06-10
上傳用戶:shancjb
概覽CM ISP(Cortex-M In-System Programmer)是為華大半導(dǎo)體(HDSC)的Cortex-M 系列MCU 提供的一款在線編程器軟件,支持華大半導(dǎo)體旗下所有的Cortex-M 系列MCU 產(chǎn)品。本文將介紹在線編程器軟件(HDSC.exe)的使用方法和編程注意事項(xiàng)。本文適用于在線編程器軟件版本號為V2.02。
上傳時(shí)間: 2022-06-25
上傳用戶:kingwide
AR0231AT7C00XUEA0-DRBR(RGB濾光)安森美半導(dǎo)體推出采用突破性減少LED閃爍 (LFM)技術(shù)的新的230萬像素CMOS圖像傳感器樣品AR0231AT,為汽車先進(jìn)駕駛輔助系統(tǒng)(ADAS)應(yīng)用確立了一個(gè)新基準(zhǔn)。新器件能捕獲1080p高動態(tài)范圍(HDR)視頻,還具備支持汽車安全完整性等級B(ASIL B)的特性。LFM技術(shù)(專利申請中)消除交通信號燈和汽車LED照明的高頻LED閃爍,令交通信號閱讀算法能于所有光照條件下工作。AR0231AT具有1/2.7英寸(6.82 mm)光學(xué)格式和1928(水平) x 1208(垂直)有源像素陣列。它采用最新的3.0微米背照式(BSI)像素及安森美半導(dǎo)體的DR-Pix?技術(shù),提供雙轉(zhuǎn)換增益以在所有光照條件下提升性能。它以線性、HDR或LFM模式捕獲圖像,并提供模式間的幀到幀情境切換。 AR0231AT提供達(dá)4重曝光的HDR,以出色的噪聲性能捕獲超過120dB的動態(tài)范圍。AR0231AT能同步支持多個(gè)攝相機(jī),以易于在汽車應(yīng)用中實(shí)現(xiàn)多個(gè)傳感器節(jié)點(diǎn),和通過一個(gè)簡單的雙線串行接口實(shí)現(xiàn)用戶可編程性。它還有多個(gè)數(shù)據(jù)接口,包括MIPI(移動產(chǎn)業(yè)處理器接口)、并行和HiSPi(高速串行像素接口)。其它關(guān)鍵特性還包括可選自動化或用戶控制的黑電平控制,支持?jǐn)U頻時(shí)鐘輸入和提供多色濾波陣列選擇。封裝和現(xiàn)狀:AR0231AT采用11 mm x 10 mm iBGA-121封裝,現(xiàn)提供工程樣品。工作溫度范圍為-40℃至105℃(環(huán)境溫度),將完全通過AEC-Q100認(rèn)證。
標(biāo)簽: 圖像傳感器
上傳時(shí)間: 2022-06-27
上傳用戶:XuVshu
This example shows how you can use signal functions in the Visiondebugger to simulate a signal that is coming into one of the analog inputs of the LPC21xx.The Measure example is described in detail in the Getting StartedUser's Guide.The MEASURE example program is available for several targets:Simulator: uVision Simulator for LPC2129MCB2100: Keil MCB2100 evaluation board with ULINK debugger - Application is loaded to internal Flash. - Switch S2 (INT1) is used as GPIO and sampled (jumper positions: J1= off, J7= on) - potentiometer POT1 is sampled as AIN0 (jumper position: J2= on) - serial port COM1 parameters: 9600 baud, no parity, 8-bits, 1 stop bit, flow control noneMCB2130: Keil MCB2130 evaluation board with ULINK debugger - Application is loaded to internal Flash. - Switch S2 (INT1) is used as GPIO and sampled (jumper positions: J1= off, J7= on) - potentiometer POT1 is sampled as AIN1 (jumper position: J2= on) - serial port COM1 parameters: 9600 baud, no parity, 8-bits, 1 stop bit, flow control none
標(biāo)簽: dac8568
上傳時(shí)間: 2022-06-28
上傳用戶:
VME has been the de-facto bus standard for Commercial off the Shelf(COTS ) Circuit Card Assemblies since the 1980's. VME boards have proven to be remarkably capable of evolving to support newer technologies with innovations such as VME Subsystem Bus, PCI Mezzanine Cards(PMC's) and VME320.However, advances in technologies, appearing particularly in interconnects, have demonstratedthe need for an advance in system development. This advance needs to accommodate high speed interconnect, particularly serial interconnects, and higher power delivery in concert with better heat removal.
標(biāo)簽: vpx標(biāo)準(zhǔn)
上傳時(shí)間: 2022-07-27
上傳用戶:bluedrops
Specification for conveying ITU-R System B Teletext in DVB bitstreams
標(biāo)簽: Specification bitstreams conveying Teletext
上傳時(shí)間: 2014-02-18
上傳用戶:mikesering
蟲蟲下載站版權(quán)所有 京ICP備2021023401號-1