E:\Visual_C__MFC擴展編程實例 例18 動態地抓取應用程序的屏幕圖像并將其打印。 上一個實例打印的是文檔的報表，而不是當前出現在屏幕上的內容。在本例中，將實現 屏幕抓取并打印其內容。M F C 為打印視提供了有限的支持， 但只要用M F C 在 C Vi e w : : O n D r a w ( )中所提供的設備環境，就可以繪制自己的視。在打印視的時候， M F C只需調 用具備打印機設備環境的O n D r a w ( )函數即可。但是，如果不繪制自己的視，例如，用一個或 者一個以上的控件窗口填充自己的視就不會打印任何東西。每個控件將使用自己的設備環境 將自己打印到屏幕，因此打印視的唯一途徑就是抓取屏幕(拷貝其內容到一個位圖對象)并將其 打印到打印機。由于該功能整個與位圖相關，因此將該功能封裝到了位圖類中。
上傳時間： 2015-10-18
上傳用戶：asddsd
This book is the most accurate and up-to-date source of information the STL currently available. ... It has an approach and appeal of its own: it explains techniques for building data structures and algorithms on top of the STL, and in this way appreciates the STL for what it is - a framework. Angelika Langer, Independent Consultant and C++ Report Columnist "A superbly authored treatment of the STL......an excellent book which belongs in any serious C++ developer s library." Jim Armstrong, President 2112 F/X, Texas. \n The C++ Standard Template Library (STL) represents a breakthrough in C++ programming techniques. With it, software developers can achieve vast improvements in the reliability of their software, and increase their own productivity.
標簽： information up-to-date available currently
上傳時間： 2015-10-31
上傳用戶：CHINA526
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
Sherwood算法消除最壞實例，以達到對任何實例都能有好的性能的效果 文件： rd_list.c --> create a random sequence of n integers not equal to each other list.c --> create a descending sequence of n integers not equal to each other sherwood.c --> 就是該算法，靜態鏈表的長度默認設為1000，可在宏定義處修改 用法： gcc -o sherwood sherwood.c gcc -o rd_list rd_list.c gcc -o list list.c ./rd_list s.txt 1000 產生一個長度為1000的互不相等的隨機序列，保存在s.txt中 ./list s1.txt 1000 產生一個長度為1000的互不相等的降序序列，保存雜s1.txt中 ./sherwood s1.txt 運行算法，比較其中的4個算法的性能差異
上傳時間： 2016-01-20
上傳用戶：ainimao
The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical) of any level of nesting to XML format and vice versa. For example, >> project.name = MyProject >> project.id = 1234 >> project.param.a = 3.1415 >> project.param.b = 42 becomes with str=xml_format(project, off ) "<project> <name>MyProject</name> <id>1234</id> <param> <a>3.1415</a> <b>42</b> </param> </project>" On the other hand, if an XML string XStr is given, this can be converted easily to a MATLAB data type or structure V with the command V=xml_parse(XStr).
標簽： converts Toolbox complex logical
上傳時間： 2016-02-12
上傳用戶：a673761058
java做書箱管理系統，C／S結構的，數據庫是access2003的
上傳時間： 2014-01-16
上傳用戶：GavinNeko
java做的學生管理系統，C／S結構，數據庫是access2003.
上傳時間： 2016-02-25
上傳用戶：牛津鞋
turbo碼simulink編碼程序，可以用來學如何用c++編寫s函數。
上傳時間： 2016-03-29
上傳用戶：baitouyu
微分方程的數值解法MATLAB Matlab. 程序. (. 主程序：. ZCX). global P. t0，Y0，h，N ％輸入初始條件、計算步長和迭代次數. M, K, C ％輸入結構參數. A=[0, I -M
上傳時間： 2014-01-15
上傳用戶：D&L37
武漢理工大學的WEB技術課件，講述了JSP的M,V,C三個層，以及JAVA的一些
上傳時間： 2013-12-27
上傳用戶：hasan2015
