NO.7信令（MTP,TUP） 相當(dāng)好的信令資料
上傳時間： 2016-12-02
上傳用戶：924484786
ST uPSD32XX I2C This example demo code is provided as is and has NO warranty, implied or otherwise. You are free to use/modify any of the provided code at your own risk in your applications with the expressed limitation of liability (see below) so long as your product using the code contains at least one uPSD products (device)
標(biāo)簽： otherwise provided warranty example
上傳時間： 2013-12-07
上傳用戶：標(biāo)點符號
信令的基本概念和分類 NO.7信令系統(tǒng)概述 消息傳遞部分 （MTP） 電話用戶部分（TUP） 信令連接控制部分（SCCP） 事務(wù)處理能力（TCAP）
上傳時間： 2014-11-26
上傳用戶：牛布牛
download it NO pay NO password something about organic reaction
標(biāo)簽： something download password reaction
上傳時間： 2014-01-24
上傳用戶：LouieWu
FDTD code in Free Space with NO absorbing boundary conditions.
標(biāo)簽： conditions absorbing boundary Space
上傳時間： 2014-01-16
上傳用戶：z1191176801
64-bits H.264 from ffmpeg 2008 version Build in VC++ 2008 NO error warning, Jesse Stone, Taiwan
標(biāo)簽： 2008 version warning Taiwan
上傳時間： 2013-12-09
上傳用戶：zhangjinzj
The combinatorial core of the OVSF code assignment problem that arises in UMTS is to assign some NOdes of a complete binary tree of height h (the code tree) to n simultaneous connections, such that NO two assigned NOdes (codes) are on the same root-to-leaf path. Each connection requires a code on a specified level. The code can change over time as long as it is still on the same level. We consider the one-step code assignment problem: Given an assignment, move the minimum number of codes to serve a new request. Minn and Siu proposed the so-called DCAalgorithm to solve the problem optimally. We show that DCA does NOt always return an optimal solution, and that the problem is NP-hard. We give an exact NO(h)-time algorithm, and a polyNOmial time greedy algorithm that achieves approximation ratio Θ(h). Finally, we consider the online code assignment problem for which we derive several results
標(biāo)簽： combinatorial assignment problem arises
上傳時間： 2014-01-19
上傳用戶：BIBI
Input : A set S of planar points Output : A convex hull for S Step 1: If S contains NO more than five points, use exhaustive searching to find the convex hull and return. Step 2: Find a median line perpendicular to the X-axis which divides S into SL and SR SL lies to the left of SR . Step 3: Recursively construct convex hulls for SL and SR. DeNOte these convex hulls by Hull(SL) and Hull(SR) respectively. Step 4: Apply the merging procedure to merge Hull(SL) and Hull(SR) together to form a convex hull. Time complexity: T(n) = 2T(n/2) + O(n) = O(n log n)
標(biāo)簽： contains Output convex planar
上傳時間： 2017-02-19
上傳用戶：wyc199288
Title:Newlegacy RPG Game Description:This is a VB RPG Game.Just use Standard VB Objests.NO use Paint Picture,BitBlt,DirectX.
標(biāo)簽： Game Description Newlegacy RPG
上傳時間： 2013-12-23
上傳用戶：fxf126@126.com
解決NO pubkey問題腳本，用于ubuntu添加key，直接運行addkey key值 后為key值
上傳時間： 2014-11-05
上傳用戶：
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