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RANGE-doppler

  • msp430

    msp430The LDC1312 and LDC1314 are 2- and 4-channel, 1? Easy-to-use – minimal configuration required 12-bit inductance to digital converters (LDCs) for ? Measure up to 4 sensors with one IC inductive sensing solutions. With multiple channels ? Multiple channels support environmental and and support for remote sensing, the LDC1312 and aging compensation LDC1314 enable the performance and reliability benefits of inductive sensing to be realized at minimal? Multi-channel remote sensing provides lowest cost and power. The products are easy to use, onlysystem cost requiring that the sensor frequency be within 1 kHz ? Pin-compatible medium and high-resolution and 10 MHz to begin sensing. The wide 1 kHz to 10 options MHz sensor frequency range also enables use of very small PCB coils, further reducing sensing– LDC1312/4: 2/4-ch 12-bit LDC solution cost and size.– LDC1612/4: 2/4-ch 28

    標簽: msp 430

    上傳時間: 2016-07-22

    上傳用戶:tongmoonsky

  • 運動會源代碼

    #include <malloc.h>       #include <stdio.h>       #include <stdlib.h>       #include <string.h>       #define NULL 0      #define MaxSize 30          typedef struct athletestruct /*運動員*/     {         char name[20];          int score; /*分數*/         int range; /**/         int item; /*項目*/     }ATH;     typedef struct schoolstruct /*學校*/     {         int count; /*編號*/         int serial; /**/          int menscore; /*男選手分數*/         int womenscore; /*女選手分數*/         int totalscore; /*總分*/         ATH athlete[MaxSize]; /**/         struct schoolstruct *next;      }SCH;         int nsc,msp,wsp;      int ntsp;      int i,j;      int overgame;      int serial,range;      int n;      SCH *head,*pfirst,*psecond;      int *phead=NULL,*pafirst=NULL,*pasecond=NULL;     void create();         void input ()     {         char answer;          head = (SCH *)malloc(sizeof(SCH)); /**/         head->next = NULL;         pfirst = head;          answer = 'y';         while ( answer == 'y' )         {         Is_Game_DoMain:         printf("\nGET Top 5 when odd\nGET Top 3 when even");         printf("\n輸入運動項目序號 (x<=%d):",ntsp);         scanf("%d",pafirst);         overgame = *pafirst;         if ( pafirst != phead )         {             for ( pasecond = phead ; pasecond < pafirst ; pasecond ++ )             {                 if ( overgame == *pasecond )                 {                     printf("\n這個項目已經存在請選擇其他的數字\n");                     goto Is_Game_DoMain;                 }             }         }         pafirst = pafirst + 1;         if ( overgame > ntsp )         {             printf("\n項目不存在");             printf("\n請重新輸入");             goto Is_Game_DoMain;         }         switch ( overgame%2 )         {         case 0: n = 3;break;         case 1: n = 5;break;         }         for ( i = 1 ; i <= n ; i++ )         {         Is_Serial_DoMain:         printf("\n輸入序號 of the NO.%d (0<x<=%d): ",i,nsc);                 scanf("%d",&serial);         if ( serial > nsc )          {             printf("\n超過學校數目,請重新輸入");             goto Is_Serial_DoMain;         }         if ( head->next == NULL )          {             create();         }         psecond = head->next ;          while ( psecond != NULL )          {             if ( psecond->serial == serial )             {                 pfirst = psecond;                 pfirst->count = pfirst->count + 1;                 goto Store_Data;             }             else             {                 psecond = psecond->next;             }         }         create();         Store_Data:                 pfirst->athlete[pfirst->count].item = overgame;         pfirst->athlete[pfirst->count].range = i;         pfirst->serial = serial;         printf("Input name:) : ");                 scanf("%s",pfirst->athlete[pfirst->count].name);         }         printf("\n繼續輸入運動項目(y&n)?");         answer = getchar();         printf("\n");         }     }         void calculate() /**/     {         pfirst = head->next;         while ( pfirst->next != NULL )         {             for (i=1;i<=pfirst->count;i++)             {                 if ( pfirst->athlete[i].item % 2 == 0 )                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 5;break;                     case 2:pfirst->athlete[i].score = 3;break;                     case 3:pfirst->athlete[i].score = 2;break;                     }                 }                 else                  {                     switch (pfirst->athlete[i].range)                     {                     case 1:pfirst->athlete[i].score = 7;break;                     case 2:pfirst->athlete[i].score = 5;break;                     case 3:pfirst->athlete[i].score = 3;break;                     case 4:pfirst->athlete[i].score = 2;break;                     case 5:pfirst->athlete[i].score = 1;break;                     }                 }                 if ( pfirst->athlete[i].item <=msp )                  {                     pfirst->menscore = pfirst->menscore + pfirst->athlete[i].score;                 }                 else                  {                     pfirst->womenscore = pfirst->womenscore + pfirst->athlete[i].score;                 }             }             pfirst->totalscore = pfirst->menscore + pfirst->womenscore;             pfirst = pfirst->next;         }     }         void output()     {         pfirst = head->next;         psecond = head->next;         while ( pfirst->next != NULL )          {             // clrscr();              printf("\n第%d號學校的結果成績:",pfirst->serial);             printf("\n\n項目的數目\t學校的名字\t分數");             for (i=1;i<=ntsp;i++)              {                 for (j=1;j<=pfirst->count;j++)                  {                     if ( pfirst->athlete[j].item == i )                     {                                                                         printf("\n %d\t\t\t\t\t\t%s\n %d",i,pfirst->athlete[j].name,pfirst->athlete[j].score);break;                                             }                 }             }             printf("\n\n\n\t\t\t\t\t\t按任意建 進入下一頁");             getchar();             pfirst = pfirst->next;         }     //  clrscr();          printf("\n運動會結果:\n\n學校編號\t男運動員成績\t女運動員成績\t總分");         pfirst = head->next;         while ( pfirst->next != NULL )         {             printf("\n %d\t\t %d\t\t %d\t\t %d",pfirst->serial,pfirst->menscore,pfirst->womenscore,pfirst->totalscore);             pfirst = pfirst->next;         }         printf("\n\n\n\t\t\t\t\t\t\t按任意建結束");         getchar();     }         void create()     {                 pfirst = (struct schoolstruct *)malloc(sizeof(struct schoolstruct));         pfirst->next = head->next ;         head->next = pfirst ;                 pfirst->count = 1;         pfirst->menscore = 0;         pfirst->womenscore = 0;         pfirst->totalscore = 0;     }     void Save()     {FILE *fp;     if((fp = fopen("school.dat","wb"))==NULL)     {printf("can't open school.dat\n");     fclose(fp);     return;     }     fwrite(pfirst,sizeof(SCH),10,fp);     fclose(fp);     printf("文件已經成功保存\n");     }         void main()     {         system("cls");         printf("\n\t\t\t 運動會分數統計\n");         printf("輸入學校數目 (x>= 5):");         scanf("%d",&nsc);          printf("輸入男選手的項目(x<=20):");         scanf("%d",&msp);          printf("輸入女選手項目(<=20):");         scanf("%d",&wsp);          ntsp = msp + wsp;                  phead = (int *)calloc(ntsp,sizeof(int));         pafirst = phead;         pasecond = phead;         input();         calculate();          output();         Save();     }             

    標簽: 源代碼

    上傳時間: 2016-12-28

    上傳用戶:150501

  • L9352B

    Description The L9352B is an integrated quad low-side power switch to drive inductive loads like valves used in ABS systems. Two of the four channels are current regulators with current range from 0 mA to 2.25 A. All channels are protected against fail functions. They are monitored by a status output.

    標簽: L9352B

    上傳時間: 2019-03-27

    上傳用戶:guaixiaolong

  • python爬蟲獲取大量免費有效代理ip--有效防止ip被封

    以后再也不用擔心寫爬蟲ip被封,不用擔心沒錢買代理ip的煩惱了 在使用python寫爬蟲時候,你會遇到所要爬取的網站有反爬取技術比如用同一個IP反復爬取同一個網頁,很可能會被封。如何有效的解決這個問題呢?我們可以使用代理ip,來設置代理ip池。 現在教大家一個可獲取大量免費有效快速的代理ip方法,我們訪問西刺免費代理ip網址 這里面提供了許多代理ip,但是我們嘗試過后會發現并不是每一個都是有效的。所以我們現在所要做的就是從里面提供的篩選出有效快速穩定的ip。 以下介紹的免費獲取代理ip池的方法: 優點:免費、數量多、有效、速度快 缺點:需要定期篩選 主要思路: 從網址上爬取ip地址并存儲 驗證ip是否能使用-(隨機訪問網址判斷響應碼) 格式化ip地址 代碼如下: 1.導入包 import requests from lxml import etree import time 1 2 3 2.獲取西刺免費代理ip網址上的代理ip def get_all_proxy():     url = 'http://www.xicidaili.com/nn/1'     headers = {         'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36',     }     response = requests.get(url, headers=headers)     html_ele = etree.HTML(response.text)     ip_eles = html_ele.xpath('//table[@id="ip_list"]/tr/td[2]/text()')     port_ele = html_ele.xpath('//table[@id="ip_list"]/tr/td[3]/text()')     proxy_list = []     for i in range(0,len(ip_eles)):         proxy_str = 'http://' + ip_eles[i] + ':' + port_ele[i]         proxy_list.append(proxy_str)     return proxy_list 1 2 3 4 5 6 7 8 9 10 11 12 13 14 3.驗證獲取的ip def check_all_proxy(proxy_list):     valid_proxy_list = []     for proxy in proxy_list:         url = 'http://www.baidu.com/'         proxy_dict = {             'http': proxy         }         try:             start_time = time.time()             response = requests.get(url, proxies=proxy_dict, timeout=5)             if response.status_code == 200:                 end_time = time.time()                 print('代理可用:' + proxy)                 print('耗時:' + str(end_time - start_time))                 valid_proxy_list.append(proxy)             else:                 print('代理超時')         except:             print('代理不可用--------------->'+proxy)     return valid_proxy_list 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 4.輸出獲取ip池 if __name__ == '__main__':     proxy_list = get_all_proxy()     valid_proxy_list = check_all_proxy(proxy_list)     print('--'*30)     print(valid_proxy_list) 1 2 3 4 5 技術能力有限歡迎提出意見,保證積極向上不斷學習 ———————————————— 版權聲明:本文為CSDN博主「彬小二」的原創文章,遵循 CC 4.0 BY-SA 版權協議,轉載請附上原文出處鏈接及本聲明。 原文鏈接:https://blog.csdn.net/qq_39884947/article/details/86609930

    標簽: python ip 代理 防止

    上傳時間: 2019-11-15

    上傳用戶:fygwz1982

  • AD810

    PRODUCT DESCRIPTION The AD810 is a composite and HDTV compatible, current feedback, video operational amplifier, ideal for use in systems such as multimedia, digital tape recorders and video cameras. The 0.1 dB flatness specification at bandwidth of 30 MHz (G = +2) and the differential gain and phase of 0.02% and 0.04° (NTSC) make the AD810 ideal for any broadcast quality video system. All these specifications are under load conditions of 150 ? (one 75 ? back terminated cable). The AD810 is ideal for power sensitive applications such as video cameras, offering a low power supply current of 8.0 mA max. The disable feature reduces the power supply current to only 2.1 mA, while the amplifier is not in use, to conserve power. Furthermore the AD810 is specified over a power supply range of ±5 V to ±15 V.

    標簽: 810 AD

    上傳時間: 2020-04-19

    上傳用戶:su1254

  • AD8001AR

    transimpedance linearization circuitry. This allows it to drive video loads with excellent differential gain and phase perfor mance on only 50 mW of power. The AD8001 is a current feedback amplifier and features gain flatness of 0.1 dB to 100 MHz while offering differential gain and phase error of 0.01% and 0.025°. This makes the AD8001 ideal for professional video electronics such as cameras and video switchers. Additionally, the AD8001’s low distortion and fast settling make it ideal for buffer high-speed A-to-D converters. The AD8001 offers low power of 5.5 mA max (VS = ±5 V) and can run on a single +12 V power supply, while being capable of delivering over 70 mA of load current. These features make this amplifier ideal for portable and battery-powered applications where size and power are critical. The outstanding bandwidth of 800 MHz along with 1200 V/μs of slew rate make the AD8001 useful in many general purpose high-speed applications where dual power supplies of up to ±6 V and single supplies from 6 V to 12 V are needed. The AD8001 is available in the industrial temperature range of –40°C to +85°C.

    標簽: 8001 AD AR

    上傳時間: 2020-04-21

    上傳用戶:su1254

  • 3GPP LTE Radio and Cellular Technology

    This book provides technical information about all aspects of 3GPP LTE. The areas covered range from basic concepts to research-grade material, including future directions. The book captures the current state of 3GPP LTE technology and serves as a source of comprehensive reference material on this subject. It has a total of 12 chapters authored by 50 experts from around the world. The targeted audi- ence includes professionals who are designers or planners for 3GPP LTE systems, researchers (faculty members and graduate students), and those who would like to learn about this field.

    標簽: Technology Cellular Radio 3GPP LTE and

    上傳時間: 2020-05-26

    上傳用戶:shancjb

  • Ambient Networks

    One traditional view of how wireless networks evolve is of a continuous, inevitable progres- sion to higher link speeds, combined with greater mobility over wider areas. This standpoint certainly captures the development from first and second generation cellular systems focused on voice support, and the early short-range wireless data networks, through to today’s 3G cellular and mobile broadband systems; there is every confidence that the trend will continue some way into the future. 

    標簽: Networks Ambient

    上傳時間: 2020-05-26

    上傳用戶:shancjb

  • Cognitive+Radio+Networks

    According to the statistics of the Federal Communications Commission (FCC), temporal and geographical variations in the utilization of the as- signed spectrum range from 15% to 85%. The limited available radio spec- trum and the inefficiency in spectrum usage necessitate a new commu- nication paradigm to exploit the existing spectrum dynamically. 

    標簽: Cognitive Radio Networks

    上傳時間: 2020-05-26

    上傳用戶:shancjb

  • Cognitive+Radio+Technology

    This introduction takes a visionary look at ideal cognitive radios (CRs) that inte- grate advanced software-defined radios (SDR) with CR techniques to arrive at radios that learn to help their user using computer vision, high-performance speech understanding, global positioning system (GPS) navigation, sophisticated adaptive networking, adaptive physical layer radio waveforms, and a wide range of machine learning processes.

    標簽: Technology Cognitive Radio

    上傳時間: 2020-05-26

    上傳用戶:shancjb

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