x=[1,2,0,-1,3,2];h=[1,-1,1];
y1=x*h(1);
Y2=x*h(2);
y3=x*h(3);
Y1=[0,0,y1];
Y2=[0,Y2,0];
Y3=[y3,0,0];
y=Y1+Y2+Y3;
L=-2:1:5;
figure(1);
subplot(211);stem(L,y,'*');
xlabel('L');ylabel('y');title('(1)');
X=x.';X=X';
r1=X*y(1);r2=X*y(2);r3=X*y(3);r4=X*y(4);
r5=X*y(5);r6=X*y(6);r7=X*y(7);r8=X*y(8);
R1=[0,0,0,0,0,0,0,r1];R2=[0,0,0,0,0,0,r2,0];
R3=[0,0,0,0,0,r3,0,0];R4=[0,0,0,0,r4,0,0,0];
R5=[0,0,0,r5,0,0,0,0];R6=[0,0,r6,0,0,0,0,0];
R7=[0,r7,0,0,0,0,0,0];R8=[r8,0,0,0,0,0,0,0];
R=R1+R2+R3+R4+R5+R6+R7+R8;
n=-7:5;
subplot(212);stem(n,R);title('(2)');
標簽：
ketang
上傳時間：
2020-11-10
上傳用戶：
本源代碼是基于STM32F4xx硬件平臺設(shè)計的貪吃蛇小游戲，主要難點在：隨機點產(chǎn)生、貪吃蛇轉(zhuǎn)向、貪吃蛇貪吃點；本部分主要接收產(chǎn)生隨機點，產(chǎn)生隨機點需要注意兩個方面：1、隨機點在有效的范圍內(nèi)；2、貪吃點與貪吃蛇不重合。產(chǎn)生隨機點主要有兩個函數(shù)，分別如下：//隨機數(shù)產(chǎn)生任務(wù)void rng_chansheng(void *p_arg){OS_ERR err;while(1){OSSemPend(&RNG_SEM,0,OS_OPT_PEND_BLOCKING,0,&err);zou.x = RNG_Get_RandomRange(0,50)*8 + 40;zou.y = RNG_Get_RandomRange(0,50)*8 + 260;lcd_fangkuan(zou.x,zou.y,zou.x+SHE_FAANGKUAN_SIZE,zou.y+SHE_FAANGKUAN_SIZE);OSTimeDlyHMSM(0,0,0,500,OS_OPT_TIME_HMSM_STRICT,&err); //延時500ms}}//往下方向畫一個實心的正方形，代表貪食蛇的一段void lcd_fangkuan(u16 x1,u16 y1,u16 x2 ,u16 Y2){u16 i,j;u16 xx,yy;if(((x2 - x1) != SHE_FAANGKUAN_SIZE)||((Y2 - y1) != SHE_FAANGKUAN_SIZE))return ;if(x1 > x2) {xx = x1;x1 = x2;x2 = xx;}if(y1 > Y2){yy = y1;y1 = Y2;Y2 = yy;}if((y1 < 260)|| (Y2 > 660)||(x1 < 40)||(x2 > 448)){game_yun_error = 1;LCD_ShowString(150,300,500,24,24,"GAME OVER!!");return ;}for(i=x1; i<x2; i++){for(j=y1; j<Y2; j++){LCD_DrawPoint(i,j);}}}
標簽：
stm32
ucosiii
貪吃蛇游戲
上傳時間：
2022-08-10
上傳用戶：
