void insert_sort(int *a,int n) { if(n==1) return insert_sort(a,n-1) int temp=a[n-1] for(int i=n-2 i>=0 i--) { if(temp<a[i]) a[i+1]=a[i] else break } a[i+1]=temp }
標簽: insert_sort int return void
上傳時間: 2014-01-22
上傳用戶:banyou
int main(int argc,char *argv[]) { char ch while(true) { printf("*************************************\n") printf(" 1.Reader Priority\n") printf(" 2.Writer Priority\n") printf(" 3.Exit to Windows\n") printf("*************************************\n") printf("Enter your choice(1,2,3): ") do{ ch=(char)_getch() }while(ch!= 1 &&ch!= 2 &&ch!= 3 ) system("cls") if(ch== 3 ) return 0 else if(ch== 1 ) ReaderPriority("thread.dat") else WriterPriority("thread.dat") printf("\nPress Any Key to Coutinue:") _getch() system("cls") } return 0
上傳時間: 2017-01-06
上傳用戶:gonuiln
Introduction Computer security is undeniably important, and as new vulnerabilities are discovered and exploited, the perceived need for new security solutions grows. "Trusted computing" initiatives propose to solve some of today s security problems through hardware changes to the personal computer. Changing hardware design isn t inherently suspicious, but the leading trusted computing proposals have a high cost: they provide security to users while giving third parties the power to enforce policies on users computers against the users wishes -- they let others pressure you to hand some control over your PC to someone else. This is a "feature" ready-made for abuse by software authors who want to anticompetitively choke off rival software. It needn t be this way: a straightforward change to the plans of trusted computing vendors could leave the security benefits intact while ensuring that a PC owner s
標簽: vulnerabilities Introduction discovered undeniably
上傳時間: 2014-01-05
上傳用戶:yph853211
Visual 開發 希望對你們有幫助 public static int Rom(int n, int m)//雙寄或雙偶 { int count = 0 //第一排Y坐標上要幾個 if (n < m) { for (int i = 1 i <= n i = i + 2) { count++ } } else { for (int j = 1 j <= m j = j + 2) { count++ } } return count }
上傳時間: 2013-12-13
上傳用戶:懶龍1988
元式,遞歸下降法書寫的if。。else條件語句的語法分析及語義分析程
標簽:
上傳時間: 2014-01-23
上傳用戶:Miyuki
pl0語言拓展,拓展了else ,repeat。。dowhile,—— ,++,-=,+=等
上傳時間: 2013-12-15
上傳用戶:jennyzai
編譯原理課程設計 PL0 (報告實驗和課程設計報告,已經設計方法,步驟) 1. 基本內容 (1)擴充賦值運算:+= 和 -= (2)擴充語句 REPEAT <語句序列> DOWHILE <條件> 其中,<條件>是循環條件,即條件成立時,重復執行循環體的<語句序列> 2. 選做內容 (1)增加運算:++ 和 --。 (2)增加類型:① 字符類型; ② 實數類型。 (3)擴充函數:① 有返回值和返回語句;② 有參數函數。 (4)增加一維數組類型(可增加指令)。 (5)其他典型語言設施。 3.本人在課程設計中已實現的功能 (1)增加單詞:保留字 else,REPEAT,DOWHILE,RETURN 運算符 +=,-=,++,-- (2)修改單詞:不等號# 改為 <> (3)增加條件語句的else子句 (4)擴充賦值運算:+= 和 -= (5)擴充語句 REPEAT <語句序列> DOWHILE <條件> (6)增加運算:++ 和 --(包括前后++、--運算) (7)增加類型:① 字符類型;② 實數類型。 (8)其他典型語言設施:FOR TO語句,FOR DOWNTO語句;
上傳時間: 2014-01-10
上傳用戶:天誠24
利用java實現文件的AES加密功能 This Java AES Crypt package contains the Java class es.vocali.util.AESCrypt, which provides file encryption and decryption using aescrypt file format. Requirements The Java AES Crypt package only works in Java 6, but can be easily adapted to Java 5 by replacing the call to NetworkInterface.getHardwareAddress() with something else. In order to use 256 bit AES keys, you must download and install "Java Cryptography Extension (JCE) Unlimited Strength Jurisdiction Policy Files" from http://java.sun.com/javase/downloads/index.jsp
標簽: Java AES AESCrypt contains
上傳時間: 2017-02-11
上傳用戶:kiklkook
//獲得當前的模式 oldmode = vga_getcurrentmode[] //初始化 vga_init[] //判斷是否支持該模式 if[vga_hasmode[mode]] vga_setmode[mode] else { printf["No such mode\n"] exit[1] } //取得信息 width = vga_getxdim[] height = vga_getydim[] colors = vga_getcolors[] //繪圖 for[i=0 i<colors i++]{ vga_setcolor[i] vga_drawline[0, i, width-1, i] }
標簽: vga_getcurrentmode vga_init oldmode vga_ha
上傳時間: 2014-12-19
上傳用戶:maizezhen
//獲得當前的模式 oldmode = vga_getcurrentmode[] //初始化 vga_init[] //判斷是否支持該模式 if[vga_hasmode[mode]] vga_setmode[mode] else { printf["No such mode\n"] exit[1] } //獲得當前的模式 mode = vga_getcurrentmode[] info = vga_getmodeinfo[mode]
標簽: vga_getcurrentmode vga_init oldmode vga_ha
上傳時間: 2017-03-24
上傳用戶:ecooo