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  • 3.畫橢圓ellipse 4.利用ellipse and rectangle 畫圖 5.一個最優(yōu)美的圖案 6.輸入3個數(shù)a,b,c

    3.畫橢圓ellipse 4.利用ellipse and rectangle 畫圖 5.一個最優(yōu)美的圖案 6.輸入3個數(shù)a,b,c,按大小順序輸出 :輸入數(shù)組,最大的與第一個元素交換,最小的與最后一個元素交換,輸出數(shù)組。 7.有n個整數(shù),使其前面各數(shù)順序向后移m個位置,最后m個數(shù)變成最前面的m個數(shù)

    標(biāo)簽: ellipse rectangle and 橢圓

    上傳時間: 2016-11-16

    上傳用戶:royzhangsz

  • 溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }

    標(biāo)簽: include stdlib stdio gt

    上傳時間: 2014-11-10

    上傳用戶:wpwpwlxwlx

  • 溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void)

    溫度華氏轉(zhuǎn)變攝氏 #include <stdio.h> #include <stdlib.h> enum x {A,B,C,D,E} int main(void) { int a=73,b=85,c=66 { if (a>=90) printf("a=A等級!!\n") else if (a>=80) printf("73分=B等級!!\n") else if (a>=70) printf("73分=C等級!!\n") else if (a>=60) printf("73分=D等級!!\n") else if (a<60) printf("73分=E等級!!\n") } { if (b>=90) printf("b=A等級!!\n") else if (b>=80) printf("85分=B等級!!\n") else if (b>=70) printf("85分=C等級!!\n") else if (b>=60) printf("85分=D等級!!\n") else if (b<60) printf("85分=E等級!!\n") } { if (c>=90) printf("c=A等級!!\n") else if (c>=80) printf("66分=B等級!!\n") else if (c>=70) printf("66分=C等級!!\n") else if (c>=60) printf("66分=D等級!!\n") else if (c<60) printf("66分=E等級!!\n") } system("pause") return 0 }

    標(biāo)簽: include stdlib stdio gt

    上傳時間: 2013-12-12

    上傳用戶:亞亞娟娟123

  • Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... &l

    Problem B:Longest Ordered Subsequence A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).

    標(biāo)簽: Subsequence sequence Problem Longest

    上傳時間: 2016-12-08

    上傳用戶:busterman

  • basic.c */ /**//* Project:NeuroBasic, basic package*//**/ /* Survey:This is a simple Basic b-code

    basic.c */ /**//* Project:NeuroBasic, basic package*//**/ /* Survey:This is a simple Basic b-code compiler which*/ /*can be used as a comfortable command shell for */ /* any program. The actual compiler is found in */ /*compiler.c.*/ /*The functions m_fctptr() and user_server()*/ /*build an interface to an

    標(biāo)簽: basic NeuroBasic Project package

    上傳時間: 2017-02-15

    上傳用戶:xymbian

  • Instead of finding the longest common subsequence, let us try to determine the length of the LCS.

    Instead of finding the longest common subsequence, let us try to determine the length of the LCS. 􀂄 Then tracking back to find the LCS. 􀂄 Consider a1a2…am and b1b2…bn. 􀂄 Case 1: am=bn. The LCS must contain am, we have to find the LCS of a1a2…am-1 and b1b2…bn-1. 􀂄 Case 2: am≠bn. Wehave to find the LCS of a1a2…am-1 and b1b2…bn, and a1a2…am and b b b b1b2…bn-1 Let A = a1 a2 … am and B = b1 b2 … bn 􀂄 Let Li j denote the length of the longest i,g g common subsequence of a1 a2 … ai and b1 b2 … bj. 􀂄 Li,j = Li-1,j-1 + 1 if ai=bj max{ L L } a≠b i-1,j, i,j-1 if ai≠j L0,0 = L0,j = Li,0 = 0 for 1≤i≤m, 1≤j≤n.

    標(biāo)簽: the subsequence determine Instead

    上傳時間: 2013-12-17

    上傳用戶:evil

  • 該程序用以查找任意兩個整數(shù)之間的所有素數(shù)。 Prime number finder can find all primes between a and b and will write the res

    該程序用以查找任意兩個整數(shù)之間的所有素數(shù)。 Prime number finder can find all primes between a and b and will write the results to the file PRIMES.TXT

    標(biāo)簽: and between number finder

    上傳時間: 2014-01-14

    上傳用戶:cccole0605

  • 設(shè)B是一個n×n棋盤

    設(shè)B是一個n×n棋盤,n=2k,(k=1,2,3,…)。用分治法設(shè)計一個算法,使得:用若干個L型條塊可以覆蓋住B的除一個特殊方格外的所有方格。其中,一個L型條塊可以覆蓋3個方格。且任意兩個L型條塊不能重疊覆蓋棋盤。

    標(biāo)簽:

    上傳時間: 2013-12-19

    上傳用戶:xc216

  • 生成Trick文件工具 1.Open command line 2.input tricktest Usage: TrickTest -f -o -i -f source mpeg2 fil

    生成Trick文件工具 1.Open command line 2.input tricktest Usage: TrickTest -f -o -i -f source mpeg2 file to trick -o trick output directory -i output file id -m max coding error, default 0 -b max bitrate for trick generate, default 0 mean no limit -s trick buffer block size, must be n*188 -l log file, default c:\tricktest.log example: tricktest -f 黑鷹行動.mpg -o c:\temp -i A -m 1000 -b 3750000 soure file: 黑鷹行動.mpg output directory: c:\temp filename: 000000A,000000A.ff,000000A.fr,000000A.vvx max coding error: 1000 trick generation speed: 3750000 bps a

    標(biāo)簽: TrickTest tricktest command source

    上傳時間: 2014-01-23

    上傳用戶:水口鴻勝電器

  • function g=distance_classify(A,b) 距離判別法程序。 輸入已分類樣本A(元胞數(shù)組)

    function g=distance_classify(A,b) 距離判別法程序。 輸入已分類樣本A(元胞數(shù)組),輸入待分類樣本b 輸出待分類樣本b的類別g 注:一般還應(yīng)計算回代誤差yita 輸入已知分類樣本的總類別數(shù)n 每類作為元胞數(shù)組的一列

    標(biāo)簽: distance_classify function 判別 分類

    上傳時間: 2013-11-25

    上傳用戶:yyyyyyyyyy

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