Insurance A Vehicle Vehicle Insured In Accident Vehicle Inspected Online fprms goto insurer Claim Approved Vehicle Repaired Insurer Pays All data should be saved to the data base
標簽： Vehicle Insurance Inspected Accident
上傳時間： 2017-09-01
上傳用戶：xz85592677
實驗源代碼 //Warshall.cpp #include<stdio.h> void warshall(int k,int n) { int i , j, t; int temp[20][20]; for(int a=0;a<k;a++) { printf("請輸入矩陣第%d 行元素:",a); for(int b=0;b<n;b++) { scanf ("%d",&temp[a][b]); } } for(i=0;i<k;i++){ for( j=0;j<k;j++){ if(temp[ j][i]==1) { for(t=0;t<n;t++) { temp[ j][t]=temp[i][t]||temp[ j][t]; } } } } printf("可傳遞閉包關系矩陣是:\n"); for(i=0;i<k;i++) { for( j=0;j<n;j++) { printf("%d", temp[i][ j]); } printf("\n"); } } void main() { printf("利用 Warshall 算法求二元關系的可傳遞閉包\n"); void warshall(int,int); int k , n; printf("請輸入矩陣的行數 i: "); scanf("%d",&k); 四川大學實驗報告 printf("請輸入矩陣的列數 j: "); scanf("%d",&n); warshall(k,n); }
上傳時間： 2016-06-27
上傳用戶：梁雪文以
#include "iostream" using namespace std; class Matrix { private: double** A; //矩陣A double *b; //向量b public: int size; Matrix(int ); ~Matrix(); friend double* Dooli(Matrix& ); void Input(); void Disp(); }; Matrix::Matrix(int x) { size=x; //為向量b分配空間并初始化為0 b=new double [x]; for(int j=0;j<x;j++) b[j]=0; //為向量A分配空間并初始化為0 A=new double* [x]; for(int i=0;i<x;i++) A[i]=new double [x]; for(int m=0;m<x;m++) for(int n=0;n<x;n++) A[m][n]=0; } Matrix::~Matrix() { cout<<"正在析構中~~~~"<<endl; delete b; for(int i=0;i<size;i++) delete A[i]; delete A; } void Matrix::Disp() { for(int i=0;i<size;i++) { for(int j=0;j<size;j++) cout<<A[i][j]<<" "; cout<<endl; } } void Matrix::Input() { cout<<"請輸入A:"<<endl; for(int i=0;i<size;i++) for(int j=0;j<size;j++){ cout<<"第"<<i+1<<"行"<<"第"<<j+1<<"列:"<<endl; cin>>A[i][j]; } cout<<"請輸入b:"<<endl; for(int j=0;j<size;j++){ cout<<"第"<<j+1<<"個:"<<endl; cin>>b[j]; } } double* Dooli(Matrix& A) { double *Xn=new double [A.size]; Matrix L(A.size),U(A.size); //分別求得U，L的第一行與第一列 for(int i=0;i<A.size;i++) U.A[0][i]=A.A[0][i]; for(int j=1;j<A.size;j++) L.A[j][0]=A.A[j][0]/U.A[0][0]; //分別求得U，L的第r行，第r列 double temp1=0,temp2=0; for(int r=1;r<A.size;r++){ //U for(int i=r;i<A.size;i++){ for(int k=0;k<r-1;k++) temp1=temp1+L.A[r][k]*U.A[k][i]; U.A[r][i]=A.A[r][i]-temp1; } //L for(int i=r+1;i<A.size;i++){ for(int k=0;k<r-1;k++) temp2=temp2+L.A[i][k]*U.A[k][r]; L.A[i][r]=(A.A[i][r]-temp2)/U.A[r][r]; } } cout<<"計算U得:"<<endl; U.Disp(); cout<<"計算L的:"<<endl; L.Disp(); double *Y=new double [A.size]; Y[0]=A.b[0]; for(int i=1;i<A.size;i++ ){ double temp3=0; for(int k=0;k<i-1;k++) temp3=temp3+L.A[i][k]*Y[k]; Y[i]=A.b[i]-temp3; } Xn[A.size-1]=Y[A.size-1]/U.A[A.size-1][A.size-1]; for(int i=A.size-1;i>=0;i--){ double temp4=0; for(int k=i+1;k<A.size;k++) temp4=temp4+U.A[i][k]*Xn[k]; Xn[i]=(Y[i]-temp4)/U.A[i][i]; } return Xn; } int main() { Matrix B(4); B.Input(); double *X; X=Dooli(B); cout<<"~~~~解得:"<<endl; for(int i=0;i<B.size;i++) cout<<"X["<<i<<"]:"<<X[i]<<" "; cout<<endl<<"呵呵呵呵呵"; return 0; }
標簽： 道理特分解法
上傳時間： 2018-05-20
上傳用戶：Aa123456789
Mobile communication devices like smart phones or tablet PCs enable us to consume information at every location and at every time. The rapid development of new applications and new services and the demand to access data in real time create an increasing throughput demand. The data have to be transmitted reliably to ensure the desired quality of service. Furthermore, an improved utilization of the bandwidth is desired to reduce the cost of transmission.
標簽： Architectures Processing Baseband Signal for
上傳時間： 2020-05-26
上傳用戶：shancjb
Long-TermEvolution(LTE)isarguablyoneofthemostimportantstepsinthecurrentphaseof the development of modern mobile communications. It provides a suitable base for enhanced services due to increased data throughput and lower latency figures, and also gives extra impetus to the modernization of telecom architectures. The decision to leave the circuit- switched domainoutofthescope ofLTE/SAEsystem standardization might soundradical but itindicatesthatthetelecomworldisgoingstronglyfortheall-IPconcept----andthedeployment of LTE/SAE is concrete evidence of this global trend.
標簽： Deployment Handbook LTE-SAE The
上傳時間： 2020-06-01
上傳用戶：shancjb
This book intends to prepare you to define Unified Communications (UC) for yourself and then get it to work for you. Each vendor pulls together from its available products a package of features related to voice, data, messaging, and image communications. That’s UC for one vendor, but it’s unlikely to match exactly the UC from another vendor. You need a detailed specification to know what you’ll see installed.
標簽： Communications Unified VoIP and
上傳時間： 2020-06-01
上傳用戶：shancjb
Identification is pervasive nowadays in daily life due to many complicated activities such as bank and library card reading, asset tracking, toll collecting, restricted access to sensitive data and procedures and target identification. This kind of task can be realized by passwords, bio- metric data such as fingerprints, barcode, optical character recognition, smart cards and radar. Radiofrequencyidentification(RFID)isatechniquetoidentifyobjectsbyusingradiosystems. It is a contactless, usually short distance, wireless data transmission and reception technique for identification of objects. An RFID system consists of two components: the tag (also called transponder) and the reader (also called interrogator).
標簽： Processing Digital Signal RFID for
上傳時間： 2020-06-08
上傳用戶：shancjb
高清電子書-C++ Primer Plus, 第6版英文版 1438頁Learning C++ is an adventure of discovery, particularly because the language accommodates several programming paradigms, including object-oriented programming, generic programming, and the traditional procedural programming.The fifth edition of this book described the language as set forth in the ISO C++ standards, informally known as C++99 and C++03, or, sometimes as C++99/03. (The 2003 version was largely a technical correction to the 1999 standard and didn’t add any new features.) Since then, C++ continues to evolve.As this book is written, the international C++ Standards Committee has just approved a new version of the standard.This standard had the informal name of C++0x while in development, and now it will be known as C++11. Most contemporary compilers support C++99/03 quite well, and most of the examples in this book comply with that standard. But many features of the new standard already have appeared in some implementations, and this edition of C++ Primer Plus explores these new features. C++ Primer Plus discusses the basic C language and presents C++ features, making this book self-contained. It presents C++ fundamentals and illustrates them with short, to-the-point programs that are easy to copy and experiment with.You learn about input/output (I/O), how to make programs perform repetitive tasks and make choices, the many ways to handle data, and how to use functions.You learn about the many features C++ has added to C, including the followi
標簽： C++
上傳時間： 2022-02-19
上傳用戶：trh505
說明： STM8S單片機驅動CC1101 433無線模塊 實現發送數據和接收數據。(STM8S single-chip microcomputer drives CC1101 433 wireless module to transmit data and receive data)
上傳時間： 2022-05-16
上傳用戶：
In this presentation, we will look at what the Serial Peripheral Interface, otherwise known as the SPI, is. and how it is used to communicate data to and from the PICmicro microcontroller.SPl is frequently used when few 1/O lines are available, but communication between two or more devices must be fast and easy to implement.In this presentation, we will discuss the following topics: We will first cover an Overview of SPI This section of the tutorial will introduce you to SPI and its concepts.Next, we will examine the use of SPI on the PICmicro MCU.The details of how SPI is implemented on a PICmicro device will be examined.Then, a Code Walkthrough will be given.The walkthough will explore code for both an SPI Master and SPI Slave. The example will have the Master generate data for sending to the slave.Finally, there will be a few resources given at the end of the presentation. These resources will allow you to explore in more detail the SPI interface
標簽： spi協議
上傳時間： 2022-06-20
上傳用戶：
