GNU ccAudio2 is a stand-alone portable C++ class framework for manipulating audio data. It has existed for some time as GNU GPL licensed package and has most recently been designated a GNU package. It is commonly used in GNU Bayonne.
標簽： manipulating stand-alone framework ccAudio2
上傳時間： 2013-12-28
上傳用戶：sjyy1001
What is it? A generic stand-alone MIPS program that can do printf on a standard UART. requirements: . CPU has CP0 structure (r4k compatible) Configure:
標簽： stand-alone requirem standard generic
上傳時間： 2017-02-19
上傳用戶：shawvi
Serial UART open source core. The design is engineered for use as a stand alone chip or for use with other of our cores. The reason for developing the Serial UART core is the fact, that asynchronous serial communication is very common that almost every machine understands it.Also, for OCRP-1, we needed a way of communication with a host computer, to make it available over the net.
標簽： engineered for use Serial
上傳時間： 2017-03-11
上傳用戶：aa17807091
Prentice Hall 出版的整合linux和windows <b>英文原版<b> 另本人有大量電子書，O Reilly的最多 有需要的朋友在我的個人空間上給我留言
標簽： Prentice windows linux Hall
上傳時間： 2014-01-22
上傳用戶：JIUSHICHEN
歐幾里德算法：輾轉(zhuǎn)求余 原理: gcd(a,b)=gcd(b,a mod b) 當b為0時,兩數(shù)的最大公約數(shù)即為a getchar()會接受前一個scanf的回車符
上傳時間： 2014-01-10
上傳用戶：2467478207
//9488定時器B功能測試 9488定時器B功能測試B:DAMI調(diào)試通過: 9488 8位定時器B的使用 有關的I/O為三個:TBPWM(輸出)(P1.0) 模式有:間隔定時功能,PWM模式 有定時中斷:定時器B溢出中斷
上傳時間： 2017-06-01
上傳用戶：ryb
Stand-alone C codes for fuzzy inference systems.
標簽： Stand-alone inference systems codes
上傳時間： 2013-12-16
上傳用戶：ippler8
stand alone crosshair code c++
標簽： crosshair stand alone code
上傳時間： 2017-08-23
上傳用戶：wyc199288
pic mcu code:This application note describes the design and implementation of a USB Mass Storage Device (MSD) using a Secure Digital card, which should prove useful to developers of USB mass storage solutions. This application may be used as a stand-alone MSD or as a Secure Digital/Multimedia Card (SD/MMC) reader/ writer interface.
標簽： implementation application describes Storage
上傳時間： 2014-11-23
上傳用戶：天誠24
1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經(jīng)過研究發(fā)現(xiàn)，漢諾塔的破解很簡單，就是按照移動規(guī)則向一個方向移動金片： 如3階漢諾塔的移動：A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外，漢諾塔問題也是程序設計中的經(jīng)典遞歸問題
標簽： 移動 發(fā)現(xiàn)
上傳時間： 2016-07-25
上傳用戶：gxrui1991
