利用MSP430 單片機的一般 I/O口進行的數字量的采集 利用A/D采集通道實現模擬量到數字量的轉化
上傳時間： 2013-12-21
上傳用戶：古谷仁美
The code assumes a two-dimensional computational domain with TMz polarization (i.e., non-zero field Ez, Hx, and Hy). The program is currently written so that the incident field always strikes the lower-left corner of the total-field region first. (If you want a different corner, that should be a fairly simple tweak to the code, but for now you ll have to make that tweak yourself.) I have attempted to provide copious comments in the code and hope that a knowledgeable C programmer can quickly map the approach as described in the paper to what is in the program.
標簽： two-dimensional computational polarization non-zero
上傳時間： 2013-12-13
上傳用戶：cylnpy
Many many developers all over the net respect NASM for what i s - a widespread (thus netwide), portable (thus netwide!), very flexible and mature assembler tool with support for many output formats (thus netwide!!). Now we have good news for you: NASM is licensed under LGPL. This means its development is open to even wider society of programmers wishing to improve their lovely assembler. The NASM project is now situated at SourceForge.net, the most famous Open Source development center on The Net. Visit our development page at http://nasm.2y.net/ and our SF project at http://sf.net/projects/nasm/
標簽： developers widespread netwide respect
上傳時間： 2014-01-20
上傳用戶：2404
FlashFlex51 Microcontroller Control of CompactFlash Card in I/O Mode
標簽： Microcontroller CompactFlash FlashFlex Control
上傳時間： 2014-01-24
上傳用戶：鳳臨西北
提出了一種基于樣本的分級檢索 MPEG 視頻的新方法:首先用I 幀的dct_dc_size 字段快速粗檢,然后用斷層攝影(tomography)法分析B 幀運動矢 量的時空分布特性以進一步縮小結果集,最后用DC 圖像的精確匹配方法驗證檢索結果.試驗結果表明,本方法 所需計算量較小,且可保證較高的檢索精度.
標簽： dct_dc_size tomography MPEG 幀
上傳時間： 2013-12-30
上傳用戶：獨孤求源
Motorola 單片機 掌握I/O口的基本使用方法
上傳時間： 2014-06-30
上傳用戶：pompey
ＭＳＰ４３０Ｆ４４９的i/o口AQ430 Practice Code
上傳時間： 2014-01-26
上傳用戶：牧羊人8920
巴特沃斯、切比雪夫I和橢圓濾波器設計的源程序！非常難得！ 簡潔的C語言編寫
上傳時間： 2015-04-15
上傳用戶：縹緲
MCS51系列單片機采用普通I/O實現I2C接口，數據的讀寫等
上傳時間： 2015-04-16
上傳用戶：s363994250
用Doolittle方法求解此方程組； 1．先由U[1][i]=a[1][i] 求的U的第一行，在根據L[i][1]=a[i][1]/U[1][1] 求的L的第一列；2..然后根據公式求得U，L其他的值； 3 回帶求解得到X
上傳時間： 2013-12-10
上傳用戶：洛木卓
