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Two

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no Two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare Two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標簽: represented integers group items

    上傳時間: 2016-01-17

    上傳用戶:jeffery

  • FIST可堆疊文件系統

    FIST可堆疊文件系統,linux文件系統修改相關的開源軟件,使得對linux文件系統功能的改進很簡單了 The FiST (File System Translator) system combines Two methods to solve the above problems in a novel way: a set of stackable file system templates for each operating system, and a high-level language that can describe stackable file systems in a cross-platform portable fashion. Using FiST, stackable file systems need only be described once. FiST s code generation tool, fistgen, compiles a single file system description into loadable kernel modules for several operating systems (currently Solaris, Linux, and FreeBSD). The project demonstrates that with FiST, code size and development time are reduced significantly, while imposing a small performance overhead of only 1-2%. These benefits are achieved, as well as portability, without changing existing operating systems or file system.

    標簽: FIST 堆疊 文件系統

    上傳時間: 2014-01-10

    上傳用戶:xsnjzljj

  • This the third edition of the Writing Device Drivers articles. The first article helped to simply ge

    This the third edition of the Writing Device Drivers articles. The first article helped to simply get you acquainted with device drivers and a simple framework for developing a device driver for NT. The second tutorial attempted to show to use IOCTLs and display what the memory layout of Windows NT is. In this edition, we will go into the idea of contexts and pools. The driver we write today will also be a little more interesting as it will allow Two user mode applications to communicate with each other in a simple manner. We will call this the “poor man’s pipes” implementation.

    標簽: the articles Drivers edition

    上傳時間: 2014-01-16

    上傳用戶:ommshaggar

  • Solving Engineering Problems Using MATLAB C++ Math Library Introduction In the previous article, we

    Solving Engineering Problems Using MATLAB C++ Math Library Introduction In the previous article, we studied how can use MATLAB C API to solve engineering problems. In this article I will show you how can use MATLAB C++ math library. The MATLAB® C++ Math Library serves Two separate constituencies: MATLAB programmers seeking more speed or complete independence from interpreted MATLAB, and C++ programmers who need a fast, easy-to-use matrix math library. To each, it offers distinct advantages.

    標簽: Introduction Engineering Problems previous

    上傳時間: 2014-12-02

    上傳用戶:13160677563

  • Ink Blotting One method for escaping from a maze is via ‘ink-blotting’. In this method your startin

    Ink Blotting One method for escaping from a maze is via ‘ink-blotting’. In this method your starting square is marked with the number ‘1’. All free, valid squares north, south, east and west around the number ‘1‘ are marked with a number ‘2’. In the next step, all free, valid squares around the Two are marked with a ‘3’ and the process is repeated iteratively until :  The exit is found (a free square other than the starting position is reached on the very edge of the maze), or,  No more free squares are available, and hence no exit is possible.

    標簽: method ink-blotting Blotting escaping

    上傳時間: 2014-12-03

    上傳用戶:123啊

  • This code implements min binomial heaps and min leftist trees.Plus, measure and compare the relative

    This code implements min binomial heaps and min leftist trees.Plus, measure and compare the relative performance of these Two implementations under the assumption that the only permissible operations are insert and delete-min.

    標簽: implements and min binomial

    上傳時間: 2014-11-27

    上傳用戶:2467478207

  • Using Jacobi method and Gauss-Seidel iterative methods to solve the following system The require

    Using Jacobi method and Gauss-Seidel iterative methods to solve the following system The required precision is   =0.00001, and the maximum iteration number N=25. Compare the number of iterations and the convergence of these Two methods

    標簽: Gauss-Seidel iterative following methods

    上傳時間: 2016-02-06

    上傳用戶:zmy123

  • Synthesizable FIFO Model This example describes a synthesizable implementation of a FIFO. The FIFO

    Synthesizable FIFO Model This example describes a synthesizable implementation of a FIFO. The FIFO depth and FIFO width in bits can be modified by simply changing the value of Two parameters, `FWIDTH and `FDEPTH. For this example, the FIFO depth is 4 and the FIFO width is 32 bits.

    標簽: FIFO implementation Synthesizable synthesizable

    上傳時間: 2016-02-12

    上傳用戶:源弋弋

  • this procedure is a game of basketball or subsystems time, the competition will record the entire ti

    this procedure is a game of basketball or subsystems time, the competition will record the entire time, and can amend the Competition time suspended contest time, the Two can be set at any time during the competition process of the match, the Two teams exchanged scores midfielder position, Competition can end report issued directives

    標簽: competition basketball subsystems procedure

    上傳時間: 2016-02-14

    上傳用戶:cuibaigao

  • The algorm of viterbi. You talk to your friend three days in a row and discover that on the first da

    The algorm of viterbi. You talk to your friend three days in a row and discover that on the first day he went for a walk, on the second day he went shopping, and on the third day he cleaned his apartment. You have Two questions: What is the overall probability of this sequence of observations? And what is the most likely sequence of rainy/sunny days that would explain these observations? The first question is answered by the forward algorithm the second question is answered by the Viterbi algorithm. These Two algorithms are structurally so similar (in fact, they are both instances of the same abstract algorithm) that they can be implemented in a single function:

    標簽: discover viterbi algorm friend

    上傳時間: 2016-02-16

    上傳用戶:xc216

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