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About:
hamsterdb is a database engine written in ANSI C. It supports a B+Tree index structure, uses memory mapped I/O (if available), supports cursors, and can create in-memory databases.
Release focus: Major feature enhancements
Changes:
This release comes with many changes and new features. It can manage multiple databases in one file. A new flag (HAM_LOCK_EXCLUSIVE) places an exclusive lock on the file. hamsterdb was ported to Windows CE, and the Solution file for Visual Studio 2005 now supports builds for x64. Several minor bugs were fixed, performance was improved, and small API changes occurred. Pre-built libraries for Windows (32-bit and 64-bit) are available for download.
Author:
cruppstahl
標簽：
C.
hamsterdb
structure
database
上傳時間：
2013-12-11
上傳用戶：LouieWu
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B樹算法實現，非常難得！btree implementation for random lookups, transaction handling, sequential access methods, and a small embeddable footprint.
標簽：
樹
算法
上傳時間：
2014-01-10
上傳用戶：王小奇
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Floyd-Warshall算法描述
1)適用范圍：
a)APSP(All Pairs Shortest Paths)
b)稠密圖效果最佳
c)邊權可正可負
2)算法描述：
a)初始化：dis[u,v]=w[u,v]
b)For k:=1 to n
For i:=1 to n
For j:=1 to n
If dis[i,j]>dis[i,k]+dis[k,j] Then
Dis[I,j]:=dis[I,k]+dis[k,j]
c)算法結束：dis即為所有點對的最短路徑矩陣
3)算法小結：此算法簡單有效，由于三重循環結構緊湊，對于稠密圖，效率要高于執行|V|次Dijkstra算法。時間復雜度O(n^3)。
考慮下列變形：如(I,j)∈E則dis[I,j]初始為1,else初始為0，這樣的Floyd算法最后的最短路徑矩陣即成為一個判斷I,j是否有通路的矩陣。更簡單的，我們可以把dis設成boolean類型，則每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”來代替算法描述中的藍色部分，可以更直觀地得到I,j的連通情況。
標簽：
Floyd-Warshall
Shortest
Pairs
Paths
上傳時間：
2013-12-01
上傳用戶：dyctj
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Program main BIOS image |
| /B - Program Boot Block |
| /N - Program NVRAM |
| /C - Destroy CMOS checksum |
| /E - Program Embedded Controller Block |
| /K - Program all non-critical blocks |
| /Kn - Program n th non-critical block only(n=0-7) |
| /Q - Silent execution |
| /REBOOT - Reboot after programming |
| /X - Don t Check ROM ID |
| /S - Display current system s ROMID |
| /Ln - Load CMOS defaults
標簽：
Program
Destroy
Block
NVRAM
上傳時間：
2016-07-26
上傳用戶：wfl_yy
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這是一個三次樣條插值的.m程序
輸入的是一個二維數組A(Nx2)
插值方法為:
S(x) = A(J) + B(J)*( x - x(J) ) + C(J)*( x - x(J) )**2 +D(J) * ( x - x(J) )**3 for x(J) <= x < x(J + 1)
標簽：
Nx2
插值
三次樣條
二維
上傳時間：
2013-12-14
上傳用戶：gengxiaochao
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采用3D Bresenham算法在兩點間劃一直線
％ This program is ported to MATLAB from:
％ B.Pendleton. line3d - 3D Bresenham s (a 3D line drawing algorithm)
％ ftp://ftp.isc.org/pub/usenet/comp.sources.unix/volume26/line3d, 1992
％
％ Which is referenced by:
％ Fischer, J., A. del Rio (2004). A Fast Method for Applying Rigid
％ Transformations to Volume Data, WSCG2004 Conference.
％ http://wscg.zcu.cz/wscg2004/Papers_2004_Short/M19.pdf
標簽：
Bresenham
Pendleton
program
MATLAB
上傳時間：
2013-12-10
上傳用戶：sz_hjbf
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Atheros Communications
AR6001 WLAN Driver for SDIO installation Read Me
March 26,2007
(based on k14 fw1.1)
Windows CE Embedded CE 6.0 driver installation.
1. Unzip the installation file onto your system (called installation directory below)
2. Create an OS design or open an existing OS design in Platform Builder 6.0.
a. The OS must support the SD bus driver and have an SD Host Controller driver (add these from Catalog Items).
b. Run image size should be set to allow greater than 32MB.
3. a. From the Project menu select Add Existing Subproject...
b. select AR6K_DRV.pbxml
c. select open
This should create a subproject within your OS Design project for the AR6K_DRV driver.
4. Build the solution.
標簽：
Communications
installation
Atheros
Driver
上傳時間：
2016-10-27
上傳用戶：hebmuljb
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溫度華氏轉變攝氏
#include <stdio.h>
#include <stdlib.h>
enum x {A,B,C,D,E}
int main(void)
{
int a=73,b=85,c=66
{
if (a>=90)
printf("a=A等級!!\n")
else if (a>=80)
printf("73分=B等級!!\n")
else if (a>=70)
printf("73分=C等級!!\n")
else if (a>=60)
printf("73分=D等級!!\n")
else if (a<60)
printf("73分=E等級!!\n")
}
{
if (b>=90)
printf("b=A等級!!\n")
else if (b>=80)
printf("85分=B等級!!\n")
else if (b>=70)
printf("85分=C等級!!\n")
else if (b>=60)
printf("85分=D等級!!\n")
else if (b<60)
printf("85分=E等級!!\n")
}
{
if (c>=90)
printf("c=A等級!!\n")
else if (c>=80)
printf("66分=B等級!!\n")
else if (c>=70)
printf("66分=C等級!!\n")
else if (c>=60)
printf("66分=D等級!!\n")
else if (c<60)
printf("66分=E等級!!\n")
}
system("pause")
return 0
}
標簽：
include
stdlib
stdio
gt
上傳時間：
2014-11-10
上傳用戶：wpwpwlxwlx
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溫度華氏轉變攝氏
#include <stdio.h>
#include <stdlib.h>
enum x {A,B,C,D,E}
int main(void)
{
int a=73,b=85,c=66
{
if (a>=90)
printf("a=A等級!!\n")
else if (a>=80)
printf("73分=B等級!!\n")
else if (a>=70)
printf("73分=C等級!!\n")
else if (a>=60)
printf("73分=D等級!!\n")
else if (a<60)
printf("73分=E等級!!\n")
}
{
if (b>=90)
printf("b=A等級!!\n")
else if (b>=80)
printf("85分=B等級!!\n")
else if (b>=70)
printf("85分=C等級!!\n")
else if (b>=60)
printf("85分=D等級!!\n")
else if (b<60)
printf("85分=E等級!!\n")
}
{
if (c>=90)
printf("c=A等級!!\n")
else if (c>=80)
printf("66分=B等級!!\n")
else if (c>=70)
printf("66分=C等級!!\n")
else if (c>=60)
printf("66分=D等級!!\n")
else if (c<60)
printf("66分=E等級!!\n")
}
system("pause")
return 0
}
標簽：
include
stdlib
stdio
gt
上傳時間：
2013-12-12
上傳用戶：亞亞娟娟123
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Problem B:Longest Ordered Subsequence
A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, sequence (1, 7, 3, 5, 9, 4, 8) has ordered subsequences, e. g., (1, 7), (3, 4, 8) and many others. All longest ordered subsequences are of length 4, e. g., (1, 3, 5, 8).
標簽：
Subsequence
sequence
Problem
Longest
上傳時間：
2016-12-08
上傳用戶：busterman
