<button id="kmkwy"></button> All of Java s Input/Output (I/O) facilities are based on streams, which provide simple ways to read and write data of different types. Java provides many different kinds of streams, each with its own application. The universe of streams is divided into four large categories: input streams and output streams, for reading and writing binary data and readers and writers, for reading and writing textual (character) data. You re almost certainly familiar with the basic kinds of streams--but did you know that there s a CipherInputStream for reading encrypted data? And a ZipOutputStream for automatically compressing data? Do you know how to use buffered streams effectively to make your I/O operations more efficient? Java I/O, 2nd Edition has been updated for Java 5.0 APIs and tells you all you ever need to know about streams--and probably more.
標簽： facilities streams provide Output
上傳時間： 2013-12-17
上傳用戶：6546544
Algo s in C++. A higly valued book on various algo s book in c++. Go through the book and u will be highly enriched. A fantastic book for beginners.
標簽： book through various valued
上傳時間： 2017-05-01
上傳用戶：fanboynet
Learn how to: * Tokenize a null-terminated string * Create a search and replace function for strings * Implement subtraction for string objects * Use the vector, deque, and list sequence containers * Use the container adaptors stack, queue, and priority_queue * Use the map, multimap, set, and multiset associative containers * Reverse, rotate, and shuffle a sequence * Create a function object * Use binders, negators, and iterator adapters * Read and write files * Use stream iterators to handle file I/O * Use exceptions to handle I/O errors * Create custom inserters and extractors * Format date, time, and numeric data * Use facets and the localization library * Overload the [ ], ( ), and -> operators * Create an explicit constructor * And much, much more
標簽： null-terminated Tokenize Create string
上傳時間： 2014-01-18
上傳用戶：yph853211
特點(FEATURES) 精確度0.1%滿刻度 (Accuracy 0.1%F.S.) 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A| (Math functioA+B/A-B/AxB/A/B/A&B(Hi&Lo)/|A|/etc.....) 16 BIT 類比輸出功能(16 bit DAC isolating analog output function) 輸入/輸出1/輸出2絕緣耐壓2仟伏特/1分鐘(Dielectric strength 2KVac/1min. (input/output1/output2/power)) 寬范圍交直流兩用電源設計(Wide input range for auxiliary power) 尺寸小,穩定性高(Dimension small and High stability)
上傳時間： 2013-11-24
上傳用戶：541657925
TLC2543是TI公司的12位串行模數轉換器，使用開關電容逐次逼近技術完成A/D轉換過程。由于是串行輸入結構，能夠節省51系列單片機I/O資源；且價格適中，分辨率較高，因此在儀器儀表中有較為廣泛的應用。 TLC2543的特點 （1）12位分辯率A/D轉換器； （2）在工作溫度范圍內10μs轉換時間； （3）11個模擬輸入通道； （4）3路內置自測試方式； （5）采樣率為66kbps； （6）線性誤差±1LSBmax； （7）有轉換結束輸出EOC； （8）具有單、雙極性輸出； （9）可編程的MSB或LSB前導； （10）可編程輸出數據長度。 TLC2543的引腳排列及說明 TLC2543有兩種封裝形式：DB、DW或N封裝以及FN封裝，這兩種封裝的引腳排列如圖1，引腳說明見表1 TLC2543電路圖和程序欣賞 #include<reg52.h> #include<intrins.h> #define uchar unsigned char #define uint unsigned int sbit clock=P1^0; sbit d_in=P1^1; sbit d_out=P1^2; sbit _cs=P1^3; uchar a1,b1,c1,d1; float sum,sum1; double sum_final1; double sum_final; uchar duan[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f}; uchar wei[]={0xf7,0xfb,0xfd,0xfe}; void delay(unsigned char b) //50us { unsigned char a; for(;b>0;b--) for(a=22;a>0;a--); } void display(uchar a,uchar b,uchar c,uchar d) { P0=duan[a]|0x80; P2=wei[0]; delay(5); P2=0xff; P0=duan[b]; P2=wei[1]; delay(5); P2=0xff; P0=duan[c]; P2=wei[2]; delay(5); P2=0xff; P0=duan[d]; P2=wei[3]; delay(5); P2=0xff; } uint read(uchar port) { uchar i,al=0,ah=0; unsigned long ad; clock=0; _cs=0; port<<=4; for(i=0;i<4;i++) { d_in=port&0x80; clock=1; clock=0; port<<=1; } d_in=0; for(i=0;i<8;i++) { clock=1; clock=0; } _cs=1; delay(5); _cs=0; for(i=0;i<4;i++) { clock=1; ah<<=1; if(d_out)ah|=0x01; clock=0; } for(i=0;i<8;i++) { clock=1; al<<=1; if(d_out) al|=0x01; clock=0; } _cs=1; ad=(uint)ah; ad<<=8; ad|=al; return(ad); } void main() { uchar j; sum=0;sum1=0; sum_final=0; sum_final1=0; while(1) { for(j=0;j<128;j++) { sum1+=read(1); display(a1,b1,c1,d1); } sum=sum1/128; sum1=0; sum_final1=(sum/4095)*5; sum_final=sum_final1*1000; a1=(int)sum_final/1000; b1=(int)sum_final%1000/100; c1=(int)sum_final%1000%100/10; d1=(int)sum_final%10; display(a1,b1,c1,d1); } }
上傳時間： 2013-11-19
上傳用戶：shen1230
This scheme is initiated by Ziv and Lempel [1]. A slightly modified version is described by Storer and Szymanski [2]. An implementation using a binary tree is proposed by Bell [3]. The algorithm is quite simple: Keep a ring buffer, which initially contains "space" characters only. Read several letters from the file to the buffer. Then search the buffer for the longest string that matches the letters just read, and send its length and position in the buffer.
標簽： initiated described modified slightly
上傳時間： 2014-01-09
上傳用戶：sk5201314
Description: FASBIR(Filtered Attribute Subspace based Bagging with Injected Randomness) is a variant of Bagging algorithm, whose purpose is to improve accuracy of local learners, such as kNN, through multi-model perturbing ensemble. Reference: Z.-H. Zhou and Y. Yu. Ensembling local learners through multimodal perturbation. IEEE Transactions on Systems, Man, and Cybernetics - Part B: Cybernetics, 2005, vol.35, no.4, pp.725-735.
標簽： Description Randomness Attribute Filtered
上傳時間： 2015-04-10
上傳用戶：ynzfm
Description: S-ISOMAP is a manifold learning algorithm, which is a supervised variant of ISOMAP. Reference: X. Geng, D.-C. Zhan, and Z.-H. Zhou. Supervised nonlinear dimensionality reduction for visualization and classification. IEEE Transactions on Systems, Man, and Cybernetics - Part B: Cybernetics, 2005, vol.35, no.6, pp.1098-1107.
標簽： Description supervised algorithm S-ISOMAP
上傳時間： 2015-04-10
上傳用戶：wfeel
數字運算，判斷一個數是否接近素數 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no
上傳時間： 2015-05-21
上傳用戶：daguda
The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition
標簽： government streamline important alphabet
上傳時間： 2015-06-09
上傳用戶：weixiao99
