merge sort give a set S of n integers and another integer x, determine whether or not there exits two elements in S whose sum is exactly x.
標簽： determine integers another integer
上傳時間： 2013-12-23
上傳用戶：xmsmh
附錄MATLAB 圖像處理命令 1．applylut 功能： 在二進制圖像中利用lookup 表進行邊沿操作。 語法： A = applylut(BW,lut) 舉例 lut = makelut( sum(x(:)) == 4 ,2) BW1 = imread( text.tif ) BW2 = applylut(BW1,lut) imshow(BW1) figure, imshow(BW2) 相關命令： makelut 2．bestblk 功 舉例
標簽： applylut lut MATLAB lookup
上傳時間： 2015-09-08
上傳用戶：gundamwzc
Distribution generator Here is a simple generator which can build some distributions with given properties. Distributions generator (compile with -lm) Typical use might be: ./distributions -u -m 1 -M 10 -n 100 -s 500 Generates a distribution of 100 uniform random numbers between 1 and 10, such that the sum of numbers is 500. ./distributions -p -2.2 -m 1 -M 100 -n 200 -s 500 Idem with 200 numbers between 1 and 100 following a power law with exponent -
標簽： generator distributions Distribution simple
上傳時間： 2014-01-27
上傳用戶：sammi
Implement the step 2 of two-level logic minimization. Our goal is to find the minimum (exact minimum) sum-of-products expression for a given function.
標簽： minimization Implement the two-level
上傳時間： 2014-01-09
上傳用戶：無聊來刷下
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
To date tests are still the best solution mankind has found to deliver working software. This book is the sum of four years of research and practice in the testing field. The practice comes from my IT consulting background, first at Octo Technology and then at Pivolis the research comes from my involvement with open source development at night and on weekends.
標簽： solution software mankind deliver
上傳時間： 2014-01-11
上傳用戶：sclyutian
本文檔提供JSR120無線消息API規范的說明，也描述sum的RI的API.
上傳時間： 2014-12-07
上傳用戶：baitouyu
Waterfilling algorithm (from [Palomar and Fonollosa, Trans-SP2004]) to compute: pi = (mu*ai - bi)^+ sum(pi) = Pt By Daniel Perez Palomar (last revision: May 10, 2004).
標簽： Waterfilling Fonollosa algorithm Trans-SP
上傳時間： 2014-01-10
上傳用戶：liansi
北京大學ACM比賽題目 In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of two odd prime numbers. For example: 8 = 3 + 5. Both 3 and 5 are odd prime numbers. 20 = 3 + 17 = 7 + 13. 42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23. Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.) Anyway, your task is now to verify Goldbach s conjecture for all even numbers less than a million.
標簽： mathematician Christian Goldbach Leonhard
上傳時間： 2016-04-22
上傳用戶：wangchong
設計一個程序完成求1－100的累加和，結果送到sum單元中
上傳時間： 2013-12-25
上傳用戶：1051290259
