替代加密:
A B C D E F G H I J K L M N O P Q R S T U V W 密文
Y Z D M R N H X J L I O Q U W A C B E G F K P 明文
X Y Z
T S V
I HAVE A DREAM!#
密文??
用ARM編程實現替代加密。
樣板 B 樹 ( B - tree )
規則 :
(1) 每個節點內元素個數在 [MIN,2*MIN] 之間, 但根節點元素個數為 [1,2*MIN]
(2) 節點內元素由小排到大, 元素不重複
(3) 每個節點內的指標個數為元素個數加一
(4) 第 i 個指標所指向的子節點內的所有元素值皆小於父節點的第 i 個元素
(5) B 樹內的所有末端節點深度一樣
Floyd-Warshall算法描述
1)適用范圍:
a)APSP(All Pairs Shortest Paths)
b)稠密圖效果最佳
c)邊權可正可負
2)算法描述:
a)初始化:dis[u,v]=w[u,v]
b)For k:=1 to n
For i:=1 to n
For j:=1 to n
If dis[i,j]>dis[i,k]+dis[k,j] Then
Dis[I,j]:=dis[I,k]+dis[k,j]
c)算法結束:dis即為所有點對的最短路徑矩陣
3)算法小結:此算法簡單有效,由于三重循環結構緊湊,對于稠密圖,效率要高于執行|V|次Dijkstra算法。時間復雜度O(n^3)。
考慮下列變形:如(I,j)∈E則dis[I,j]初始為1,else初始為0,這樣的Floyd算法最后的最短路徑矩陣即成為一個判斷I,j是否有通路的矩陣。更簡單的,我們可以把dis設成boolean類型,則每次可以用“dis[I,j]:=dis[I,j]or(dis[I,k]and dis[k,j])”來代替算法描述中的藍色部分,可以更直觀地得到I,j的連通情況。
acm HDOJ 1051WoodenSticks
Description:
There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows:
(a) The setup time for the first wooden stick is 1 minute.
(b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l and weight w if l<=l and w<=w . Otherwise, it will need 1 minute for setup.